Please I need help processing files with strings in R. All the files have two
patterns (thus,examine separately):
Pattern 1 (see file1 below): Delete Lines 1,2 & 4 in file1. Line 3 contains the
column names. Then find anything as.character and delete. Please do not delete
any values (e.g.
I have data for 90 climate stations. For each station, I have made 100+
simulations using a statistical model. So, in R, I have 90 dataframes, each
dataframe has 100+ simulations arranged column-wise.
Now, I would like to fit an extreme value distribution (EVD) to each climate
station. That
Hello, I have a list object with many dataframes (example provided below). Each
coulmn in a dataframe represents a simluation and each dataframe represents a
clmate station. I want to fit an extreme value distribution on each coulmn of a
dataframe and then average the confidence intervals and
Many thanks, Petr.You solved my problem.AT.
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I have a list object in R with dataframe names as:
pav_DJF_histo.csvpav_DJF_rcp26_2040s.csv
pav_DJF_rcp26_2080s.csv
pav_DJF_rcp45_2040s.csvpav_DJF_rcp45_2080s.csv
pav_DJF_rcp85_2040s.csv pav_DJF_rcp85_2080s.csv
pav_JJA_histo.csv
pav_JJA_rcp26_2040s.csv pav_JJA_rcp26_2080s.csv
.
lst4 - lapply(lst4, function(x) {as.data.frame(t(iris1.csv))})
#Get the data.frames in the list to the global environment
list2env(lst4 ,.GlobalEnv)
Regards
On 17 February 2015 at 09:23, Zilefac Elvis via R-help
r-help@r-project.org wrote:
Hi All,I have a dataframe called 'means' as shown
, is more useful.
Chris Campbell, PhD
Tel. +44 (0)1249 705 450 | Mobile. +44 (0) 7929 628 349
www.mango-solutions.com
Mango Solutions
2 Methuen Park, Chippenham, Wiltshire. SN14 OGB UK
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Zilefac Elvis
Hi All,I have a dataframe called 'means' as shown below:iris1.csv - iris
iris2.csv - iris
names - c(iris1.csv, iris2.csv)
dat - mget(names)
lst4 - lapply(dat, function(x) apply(x[,-5], 2, mean))
# Build the new data frame
means - as.data.frame(do.call(rbind, lst4))
means$source - names(lst4)
Perfect! #
italic(symbol(\341)*T[min]*symbol(\361))
Thanks, Uwe.
Asong.
On 10.12.2014 04:49, Zilefac Elvis via R-help wrote:
Hi All,
Please, I would like to enclose T[min] using angle brackets in R.
I have tried something like:
mtext(text=expression(Winter(DJF)~daily~minimum~temperature
Hi,
I would like to add a dash (—) on a letter in R.
How can I add a dash on letter P in the following:
mtext(text=expression(Winter(DJF)~mean~daily~precipitation~italic(P)), side=3,
line=1, cex=1.3, col=black)
?plotmath could not provide an answer to my problem.
many thanks for your
I got the right answer:
mtext(text=expression(Winter(DJF)~mean~daily~precipitation~bar(italic(P))),
side=3, line=1, cex=1.3, col=black)
Thanks.
On Tuesday, December 9, 2014 1:28 PM, Zilefac Elvis zilefacel...@yahoo.com
wrote:
Hi,
I would like to add a dash (—) on a letter in R.
How can I
Hi All,
Please, I would like to enclose T[min] using angle brackets in R.
I have tried something like:
mtext(text=expression(Winter(DJF)~daily~minimum~temperature~bold((italic(symbol(\341)T[min]symbol(\361),
side=3, line=1, cex=1.3, col=black)
but did not succeed. I learnt that adobe-type
.
format(c(1,5,32,100), width=3, flag=0)
[1] 1 5 32 100
formatC(c(1,5,32,100), width=3, flag=0)
[1] 001 005 032 100
I hope this helps.
Chel Hee Lee
On 12/04/2014 10:54 PM, Zilefac Elvis wrote:
Hi Chel,
Thanks for the timely reply.
It works but a minor problem remains.
Here
Hi Chel,
I got it right.
Many thanks.
file.rename(file_names, to=paste0(rcp45_Daily_Sim, 200:210))
list.files(pattern=rcp45_Daily_Sim)
[1] rcp45_Daily_Sim200 rcp45_Daily_Sim201 rcp45_Daily_Sim202
On Friday, December 5, 2014 9:35 AM, Zilefac Elvis zilefacel...@yahoo.com
wrote:
Hi Chel,
How
Hello,
I would like to rename multiple files in a directory. Filenames are read using:
lfile - list.files(pattern=rcp45_Daily_)
files - paste(paste(getwd(),lfile,sep=/), list.files(lfile),sep=/)# getwd
of these files
dput(lfile)
c(rcp45_Daily_Sim001.dat, rcp45_Daily_Sim002.dat)
- How can
:44 PM, Zilefac Elvis via R-help wrote:
Hello,
I would like to rename multiple files in a directory. Filenames are read
using:
lfile - list.files(pattern=rcp45_Daily_)
files - paste(paste(getwd(),lfile,sep=/), list.files(lfile),sep=/)#
getwd of these files
dput(lfile)
c
Hi All,
I have a tricky problem here.
The short code below plots some percentiles from a simulation. The percentiles
are indicated in different colors.
Problem:
- How can I fill the area under the curve using the same colors as for the
percentiles-1?
- Also, I would like the rainbow intensity
Hi Admas,Sorry I missed out the reproducible example.Here it is:
dput(xy)structure(list(ID = 1:120, X = c(-102.6, -101.9, -97.1, -97, -95.7,
-99.1, -100.1, -97.2, -97, -99.3, -96, -95.2, -98.8, -98.1, -99.6, -97.8,
-96.1, -98.3, -95.6, -96.8, -101.2, -101.1, -97.2, -111.1, -111.2, -116,
-117.6,
Hi Adam,I was not sure if my solution was correct.This is what I got using
ArcGIS to convert the same coordinates:
+proj=lcc +lat_1=49 +lat_2=77 +lat_0=49 +lon_0=-95 +x_0=0 +y_0=0 +datum=NAD83
+units=m +no_defs +ellps=GRS80 +towgs84=0,0,0
structure(list(Long = c(662843L, 303344L, 634922L,
Many thanks Jean for the clarification.Zilefac.
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Hi,
I am trying to convert lat/lon to UTM but my results are extremely flawed.
Is it because of wrong UTM zone or my lon points are negative?
I read a shapefile from ESRI using:
library(rgdal)
stations - readOGR(.,stations)
print(proj4string(stations))
## +proj=longlat +ellps=WGS84 +datum=WGS84
Hello,
I have two spatial map objects (reproducible example further down) which I
would like to overlay in R. The ESRI shapefiles were read using:
library(rgdal)
Prairie.Boundaries - readOGR(., boundaries)
watersheds-readOGR(.,watersheds)
The two objects have same projection:
Hello,
I have two spatial map objects (reproducible example further down) which I
would like to overlay in R. The ESRI shapefiles were read using:
library(rgdal)
Prairie.Boundaries - readOGR(., boundaries)
watersheds-readOGR(.,watersheds)
The two objects have same projection:
Hi,
I have fixed width data that I would like to split into columns. Here is a
sanpshot of the data (actual data is a list object):
lst1Sub-
20131124GGG1 23.00
20131125GGG1 15.00
20131128GGG1 0.00
201312 1GGG1 0.00
201312 4GGG1 0.00
201312 7GGG1 10.00
20131210GGG1 0.00
20131213GGG1
] On
Behalf Of Zilefac Elvis
Sent: 22 October 2014 16:38
To: R. Help
Subject: [R] Split fixed width data in R
Hi,
I have fixed width data that I would like to split into columns. Here is a
sanpshot
of the data (actual data is a list object):
lst1Sub-
20131124GGG1 23.00
20131125GGG1 15.00
Thanks John.
AT.
On Wednesday, October 22, 2014 5:23 PM, John McKown
john.archie.mck...@gmail.com wrote:
On Wed, Oct 22, 2014 at 10:37 AM, Zilefac Elvis zilefacel...@yahoo.comwrote:
Hi,
I have fixed width data that I would like to split into columns. Here is a
sanpshot of the data (actual
Hi,
I have a plotting issue which I am trying to resolve in R. Please load my
attached sample data (I used dput(lapply(sim.summary,head,1)) but the data are
too large) to R, install Rglimclim package and run this code which shows an
example plot I would like to change. My main function, myplot
Great! Thanks.
AT.
On Monday, August 4, 2014 8:59 PM, rhelpmaillist rhelpmaill...@163.com wrote:
Try this:
lapply(a,function(x) apply(x[,-c(1,2)],2,quantile,probs=0.95))
# a is your example list
At 2014-08-05 09:17:23, Zilefac Elvis zilefacel...@yahoo.com wrote:
Hello,
I would like
Great! Thanks, John.
For the eye sees not itself, but by reflection and someother things
On Sunday, August 3, 2014 4:54 PM, John McKown john.archie.mck...@gmail.com
wrote:
On Sun, Aug 3, 2014 at 5:12 PM, Zilefac Elvis zilefacel...@yahoo.com wrote:
Dear All,
I have a List in R and would like
Hello,
I would like to calculate for each numeric column in a dataframe,
quantile(x,probs=o.95).
My list object has 120 dataframes, each dataframe has 102 columns.
Here is an example as well as a reproducible example:
[[120]]
Year Site Sim001 Sim002 Sim003 Sim004 Sim005 Sim006 Sim007 Sim008
, 2014 1:47 AM, Uwe Ligges lig...@statistik.tu-dortmund.de
wrote:
On 03.08.2014 07:17, Zilefac Elvis wrote:
Hi ALL,
I have a List object in R. The dataframes in the List have equal rows and
columns.
How can I extract from the List, data corresponding to say c(June, July ,
August)?
Remember
Great! Thanks very much Uwe.
AT.
On Sunday, August 3, 2014 2:12 PM, Uwe Ligges lig...@statistik.tu-dortmund.de
wrote:
On 03.08.2014 21:23, Zilefac Elvis wrote:
Hi Uwe,
Thanks for replying.
Here is a reproducible example.
I would like to extract data for the Months of c(6,7,8).
Output
Dear All,
I have a List in R and would like to convert it to data.frame.
Below is a reproducible example. I can do something like:
x1-do.call(cbind.data.frame, lst3) #OR
x1-as.data.frame(lst3).
However, my output looks like this:
Year Site x Year Site x
2001 G101 33.1 2001 G102 34
I
, Aug 3, 2014 at 5:43 PM, John McKown
john.archie.mck...@gmail.com wrote:
On Sun, Aug 3, 2014 at 5:12 PM, Zilefac Elvis zilefacel...@yahoo.com wrote:
Dear All,
I have a List in R and would like to convert it to data.frame.
Below is a reproducible example. I can do something like:
x1-do.call
Hi ALL,
I have a List object in R. The dataframes in the List have equal rows and
columns.
How can I extract from the List, data corresponding to say c(June, July ,
August)?
Remember, it is a List object, containing 100 dataframes, with daily data
arranged by YYMMDD.
Thanks for your thoughtful
Hi,
I would like to create a nice looking bubble map in R.
Here is what I have done so far (the data is found below):
#
library(ggplot2)
if (dev.cur() == 1) x11(width=8,height=6)
par(mfcol=c(1,1))
Hi,
I will like to free up memory in R and make my program execute faster. At the
moment, MY PROGRAM IS VERY SLOW probably due to memory issues. Here is sample
data (Rcode is found at the end) from one simulation(I have 1000 such files to
process):
list(c(1971 1 1GGG1 0.00 -3.68 -0.29,
Hi AK,
Thanks very much for the updated code.
My simulated results are even more consistent with observations after apply the
updated version of the code.
Cheers,
Atem.
On Wednesday, April 16, 2014 11:31 PM, Zilefac Elvis zilefacel...@yahoo.com
wrote:
Hi AK,
Thanks very much.
Atem
1% 1.005563 1.039288
#3 2% 1.029126 1.057685
any(is.na(ReadOut2$pint_DJF))
[1] FALSE
A.K.
On Wednesday, April 16, 2014 12:34 PM, Zilefac Elvis zilefacel...@yahoo.com
wrote:
Hi AK,
I tried the updated Quantilecode.txt. It works well but when I open the files
, Zilefac Elvis zilefacel...@yahoo.com
wrote:
Hi AK,
Please ignore any such site.
I will check it and include in the analysis.
Thanks,
Atem.
On Monday, April 14, 2014 9:34 PM, arun smartpink...@yahoo.com wrote:
Hi,
I looked at your Observed.zip. In that one of the file is without any data
0.96572
#3 2% 0.825364 0.96904
Attached is the file.
A.K.
On Tuesday, April 15, 2014 4:00 AM, Zilefac Elvis zilefacel...@yahoo.com
wrote:
Hi AK,
I tried all codes for observations. All others work great except this (probably
due to different dimensions.
What I did is that I
.
On Sunday, April 13, 2014 2:46 AM, Zilefac Elvis zilefacel...@yahoo.com wrote:
Hi AK,
Q1) I need your help again. Using the previous data (attached) and the previous
code below,instead of taking rowMeans, let's do quantile(x,seq(0,1,by=0.01)).
Delete the last 2 rows (Trend and p) in each file
was unable to edit lst1NEW-.
-- Original Message --
From : arun
To : Zilefac Elvis;
Sent : 10-04-2014 22:02
Subject : Re: Re: Splitting columns and forming new data files in R
Hi Atem, It may be that the program slows with the size of the dataset. On
Thursday, April 10, 2014 11:13 PM
Thanks, Rui.
It works great.
Atem.
On Saturday, April 5, 2014 4:46 AM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
Maybe the following will do.
dat - structure(...)
aggregate(dat[5:8], dat[c(1, 2, 4)], FUN = mean)
Hope this helps,
Rui Barradas
Em 05-04-2014 06:37, Zilefac Elvis
Hi,
I have daily data arranged by date and site. Keeping the number of columns as
there are, I will like to aggregate (FUN=mean) from daily to monthly the
following data (only part is shown here) which starts in 1971 and ends in 1980.
Year Month Day Site Sim001 Sim002 Sim003 Sim004
1 1971
Hi,
I have daily data arranged by date and site. Keeping the number of columns as
there are, I will like to aggregate (FUN=mean) from daily to monthly the
following data (only part is shown here) which starts in 1971 and ends in 1980.
structure(list(Year = c(1971, 1971, 1971, 1971, 1971,
-14.32 3.87
26 1971 6 5 G107 144.09 11.25 30.44
27 1971 6 5 G108 0.66 9.33 32.96
A.K.
On Monday, March 31, 2014 2:35 AM, Zilefac Elvis zilefacel...@yahoo.com wrote:
Hi AK,
I figured out that the error is from Sim1971-2000_Daily_Sim001.dat.
The other files had
Hi,
I have a dataframe in R and would like to split the data (1900-1980) into two
sets.
For example, one dataframe should have data from 1900-1960 and the other from
1961-1980.
Thanks for your help.
AT.
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__
Hi,
I have rainfall data from 100 locations, with coordinates for each location
available.
Now, I have a correlation matrix showing the correlation between rainfall at a
single location against all other locations and so on for the 100 locations.
How can I visualize this correlation matrix
Hi Jim,
I tried as you described but did not succeed.
Can I send you sample data?
Thanks,
Zilefac.
On Tuesday, December 3, 2013 4:19 PM, Jim Lemon j...@bitwrit.com.au wrote:
On 12/04/2013 08:59 AM, Jim Lemon wrote:
On 12/04/2013 05:26 AM, Zilefac Elvis wrote:
Hi,
I have rainfall data from
- dat2M[with(dat2M,order(year,month,day,variable)),]
dim(dat2M1)
#[1] 1972320 5
row.names(dat2M1) - 1:nrow(dat2M1)
colnames(dat2M1)[4:5] - c(site,rain)
16436*120
#[1] 1972320
A.K.
On Saturday, November 16, 2013 11:28 PM, Zilefac Elvis zilefacel...@yahoo.com
wrote:
Hello AK,
I would
,stringsAsFactors=FALSE)
str(res3)
res3$dates-as.Date(res3$dates)
res4 - res3[!is.na(res3$dates),]
res4[1:3,1:3]
dim(res4)
#[1] 16436 99
A.K.
On Friday, November 8, 2013 5:54 PM, Zilefac Elvis zilefacel...@yahoo.com
wrote:
Hi Ak,
I think I figured out how to do the sub-setting. All I
Hi,
I have 300 .txt files in a directory. Out of this 300, I need just 100 of the
files.
I have the names of the 100 .txt files which are also found in the 300 .txt
files.
How can I extract only the 100 .txt files from the 300 ,txt files?
e.g given d1.txt, ds.txt, dx.txt, df.txt...d300.txt, how
the question. If you already know the names what is the
problem to select the files by names?
If you have the names but not inside of R you have to find a name pattern to
avoid typing them in. Is there a pattern, e.g. da.txt, db.txt, dc.txt?
On 08 Nov 2013, at 18:33, Zilefac Elvis zilefacel
Hi,
I have a data frame with each column representing a separate site.
Following this code, I can apply acf to all columns in A. 'A' contains randomly
generated data.
A - matrix(rnorm(1500),nrow=500)
par(mfrow=c(ncol(A),1))
lapply(split(A,col(A)), acf)
#OR
lapply(split(A,col(A)),
is not a multiple of split variable
AE.
From: arun smartpink...@yahoo.com
To: Zilefac Elvis zilefacel...@yahoo.com
Cc: R help r-help@r-project.org
Sent: Sunday, June 23, 2013 11:41 AM
Subject: Re: [R] Apply acf to data frame containing 'NA'
Hi,
May
Hi A.K,
I go an error on line 24 when processing all the 100 files:
res-fun1(lstf1)
Error in read.table(x, sep = , header = TRUE, stringsAsFactors = FALSE) :
more columns than column names
There seem to be a difference between lstf and lstf1.
Thanks,
Atem.
Hello,
I have a 'zoo' object containing dates [dd/mm/yr] in the first column and
values in the second column.
I tried as.Date but did not succeed.
Here is an example of date format
01/01/2000
01/02/2000
...
01/12/2000
01/01/2001
01/02/2001
...
01/12/2000
etc.
I would like to sort all Jans
.
From: arun smartpink...@yahoo.com
To: Zilefac Elvis zilefacel...@yahoo.com
Cc: R help r-help@r-project.org
Sent: Wednesday, May 22, 2013 8:47 PM
Subject: Re: [R] Sort data by month
Hi,
May be this helps.
date1-seq.Date(as.Date(01/01/2000,format=%d/%m/%Y),as.Date(31/12/2010
Hello,
I need your help on this matrix:
1 1 1 1 1 1
2 2 2 2 2 2
3 3 3 3 3 3
5 5 5 5 5 5
2 2 2 2 2 2
3 3 3 3 3 3
6 6 6 6 6 6
2 2 2 2 2 2
3 3 3 3 3 3
1 1 1 1 1 1
2 2 2 2 2 2
3 3 3 3 3 3
First three rows represent first simulation, next three rows = second
simulation etc.
I
Thanks AK. It works as expected.
Atem.
From: arun [smartpink...@yahoo.com]
Sent: Thursday, May 16, 2013 11:16 AM
To: Zilefac, Elvis
Cc: R help
Subject: Re: Loop through a simulation
Hi,
May be this is what you meant.
dat1- read.csv(data2.csv,header
Hi,
I have 1000 simulations each arranged beneath another. The attached data is on
monthly basis. First column is number of simulation, second is year and the
rest, months.
Problem:
1) Take sim 1 for example to be my original data from 1961-2005 with twelve
months. You can delete the years.
.
Thanks for much.
-- Original Message --
From : arun
To : Zilefac Elvis;
Cc : R help;
Sent :
27-04-2013 16:29
Subject : Re: [R] Help
HI, Find 'T','C','A','F' and 'Y',
delete them from all the 110 files
I assume that you meant to replace it with NA. set.seed(28)
myfiles- lapply(1:5
Hello,
I have a question and need your help urgently. I am new to R but want to learn
it.
I have several files in a folder which I have imported to R using :
temp = list.files(pattern=*.txt)
myfiles = lapply(temp, read.delim)
The resulting files are on the workspace stored as List[110]. So
Hello,
I have a question and need your help urgently. I am new to R but want to learn
it.
I have several files in a folder which I have imported to R using :
temp = list.files(pattern=*.txt)
myfiles = lapply(temp, read.delim)
The resulting files are on the workspace stored as List[110]. So
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