mma(x, rate=0.02220921, shape=3.63421746),from=0, to=500,
main="Gamma distribution", add = T, col = "red")
but the gamma fit is not fitted onto histogram as much as it supposed to
be. How should I overcome this?
Thank you in advanced.
Dila
[[alternative HTML ve
1L, 2L,
3L), Rain = c(176.8, 228.2, 90.9, 81, 73.1, 127.7, 242.8, 189.5,
204.2)), .Names = c("Year", "Month", "Rain"), class = "data.frame",
row.names = c(NA,
-9L))
Thank you so much
Dila
[[alternative HTML version deleted]]
_
0, 0, 0, 0, 0, 0, 0, 0, 0.1, 0.03, 0, 0, 0, 0, 0, 0, 0, 0,
0, 0, 0, 0.08, 0.04, 0, 0, 0, 0, 0, 0, 0, 0, 0.02, 0, 0)), .Names =
c("obs",
"tobs", "month", "day", "year", "Prec"), row.names = c(NA, 40L
), class = "data.frame")
Thank you ver
t;, "V2", "V3", "V4", "V5", "V6", "V7",
"V8", "V9", "V10", "V11"), class = "data.frame", row.names = c(NA,
-210L))
I want to replace all NA's value in column 1 until column 10 with
uot;orange",lwd=3,lty=2)
axis(1,at=1:3,c("5%","10%", "20%"))
legend("topright", bty="n",c("NRM","AAM","IDW","CCM","MI"),
lwd=c(3,3,3,3,3), lty =c(1,2,1,4),col=
c("blue","black&q
0' under variable 'B', the next value under variable 'C'
also should be '0'.
2) When value is '1' under variable 'B', there is no changes for values
under variable 'C'.
How do I achieved this by fulfill these two conditions? Thank you
at when I
rearrange it column by column, it wont appear anymore.
Using this command, I can rearrange the data column by column
library(reshape2)
res <-
transform(melt(dat,id.var=c("Year","Day")),Month=match(variable,month.abb),Amount=value)[,-c(3:4)]
res1 <- res[wi
have
29 days in Feb)
Hope you can help me. Thanks a lot.
Regards,
Dila
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PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and
5 4 110.5 2013 6 4 22 2013 7 4 3.5 2013 8 4 36.5
I want to rearrange the data according to the YEAR (year by year)
Thank you.
Regards,
Dila
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0
3/1/2012 0
4/1/2012 0
... ...
... ...
How can I achieve this?
Thank you in advanced!
Regards,
Dila
[[alternative HTML version deleted]]
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R-help@r-project.org
lied to non-(list or vector) of type 'NULL'
How to solve this?
Thank you in advance.
Regards,
Dila.
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PLEASE do r
ght5*Phg);
Targetstation
but I still could not replace the NA's. My problem is, how do I replace
those NA's with another value?
Thank you so much for your help and attention.
Regards,
Dila
[[alternative HTML version deleted]]
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R-help@r-projec
48603 71 1 1 1
48603 71 1 2 0.5
48603 71 1 3 1.3
48603 71 1 4 0.8
48603 71 1 5 0
48603 71 1 6 0
48603 71 1 7 0
...
Thank you so much for your attention and help.
Regards,
Dila
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Hi, I run this code to get the power of the test for modified bartlett's
test..but I'm not really sure that my coding is right..
#normal distribution unequal variance
asim<-5000
pv<-rep(NA,asim)
for(i in 1:asim)
{print(i)
set.seed(i)
n1<-20
n2<-20
n3<-20
mu<-0
sd1<-sqrt(25)
sd2<-sqrt(50)
sd3<-sqrt
Hi, I run this code to get the power of the test for modified bartlett's
test..but I'm not really sure that my coding is right..
#normal distribution unequal variance
asim<-5000
pv<-rep(NA,asim)
for(i in 1:asim)
{print(i)
set.seed(i)
n1<-20
n2<-20
n3<-20
mu<-0
sd1<-sqrt(25)
sd2<-sqrt(50)
sd3<-sqrt
hello,
I try to run simulation of levene's test to find the p-value but the error
of replacement has length zero occur, could anyone help me to fix this
problem?
asim <- 1000
pv<-rep(NA,asim)
for(i in 1:asim)
{print(i)
set.seed(i)
g1 <- rnorm(20,0,2)
g2 <- rnorm(20,0,2)
g3 <- rnorm(20,0,2)
x
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