Hello,
I have a data set that looks like this.
IDvalue
111 5
111 6
111 2
178 7
178 3
138 3
138 8
138 7
138 6
.
.
.
I'd like to calculate the mean and var for each object identified by the ID.
I can in theory just loop through the whole thing..., but is th
Hello,
I need to assign a number to each x[i], i=1:100, based on the value of x[i]
and where they are in the distribution of x[i]. For example 1 for x[4] means
x[4] is below 25%. I can obtain the quantile using quantile command, and
just loop through the 1:100 and assign the correct number. But I
Hello,
I have a time series plot drawn using 3 different colored lines, each line
corresponds to different category group. I'd like to put legends on the
plot. I am using "legend" to do this, however, I can either specify lty or
col in legend. Will I be able to do the following in the legend box:
Dear R users,
I have this vector that consists numeric numbers. Is there a command that
detects the repeated numbers in a vector and returns the index of the
repeated numbers (or the actual numbers)? For example, v <- c(3,4,5,7,4).
The command would return me index 2 and 5 (or the repeated number
Duncan,
Thank you so much. It is exactly what I was looking for. However, for some
reason, indices() does not work ("Error: could not find function "indices").
I used which(), it worked.
Thanks again for the help,
Julia
Duncan Murdoch-2 wrote:
>
> On 08/10/2008
Dear R users,
I am building a hierarchical model on a large data set. It can take quite
some time to finish one fit, I was just wondering whether it is possible to
store the fit object (the result) to a file for later (offline) analysis.
thanks
Julia
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Dear R users:
I have a data set that looks something like this:
IDtime y
12/01/20084
12/09/200812
19/01/20088
21/06/20083
23/01/20084
23/09/20089
26/03/20084
31/02/20083
31/10/20088
32/02/20087
32/10
Dear R users,
I am running lmer() and having memory problem: "reached total allocation of
1535Mb".
The lmer() function was successful (no errors or warnings). However when I
do "summary(fit.lmer), I got this "Error: cannot allocate vector of size
19.5 Mb). I used memory.size() and got 1880. I us
Dear R users:
I am running lmer(), and I had the following warning message:
"In mer_finalize(ans): iteration limit reached without convergence (9)
What is the default limit for lmer()? And how do I increase the limit?
Many thanks,
Julia
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e syntax to increase iteration limit?
Thank you so much,
Julia
Dieter Menne wrote:
>
> liujb yahoo.com> writes:
>
>> I am running lmer(), and I had the following warning message:
>> "In mer_finalize(ans): iteration limit reached without convergence (9)
>>
>>
Dear R users,
I need to compare two scatter plots,
plot(x1, y1)
plot(x2, y2)
and would like to plot them in the same figure. How do I do it?
Thank you.
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Sent from the R help mailing list a
Hello,
I have the exact same question: how to extract dispersion parameter from
lmer() quasipoisson model?
I did a search here and saw this post. However, I do not see answer. Could
somebody please help?
Thank you very much,
Julia
wayne hallstrom wrote:
>
> Hi,
> I would like to obtain the
Dear R users,
Suppose I have a vector that consists of characters like ABC, A02, RCA,
etc., and there are about 700 of possible characters. For example,
x <- c("ABC", "ABC", "ABC", "A02", "ABC", "RCA", "ABC", "ABC")
I'd like to get a frequency matrix that looks something like this:
ABC 6
A02
Hello,
I have a vector:
x <- c("A", "A", "A", "B", "A", "A", "C")
I'd like to compare each of elements of vector x from its previous element
(except for the 1st element which does not have previous element). So I'd
like to get a vector y (of same length) that looks something like
(0, 0, 0, 1, 1,
Hello,
I have a data file (.csv) that has a size of about 2.6 GB. I am not able to
read in the whole data set because of the memory limit. I actually only need
some columns (3 columns) of the data set, is there a way to read in
specified columns?
I am using windows.
Thanks,
Julia
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Hello,
I have a set of data that has a Date column looks like this:
12/9/2007
12/16/2007
1/1/2008
1/3/2008
1/12/2008
etc.
I'd like the date to look something like the follow (so that I could sort by
date easily).
20071209
20071216
20080101
20080103
20080112
How to do it? Thank you very much
Jul
Dear R users:
I have a vector of dates as follows:
t <- c("2007-01-05", "2007-05-14", "2007-12-28", "2008-01-09", "2008-04-24",
"2009-02-14")
I'd like to calculate number of days between those dates (time interval).
How to do it?
Thank you,
Julia
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Dear R users,
I would like to test the randomness in a series of N values (N>=2). I know
that runs.test works for dichotomous factor only:
x <- rep(c(1,2), 50)
runs.test(factor(x))
However it doesn't work for series that can take any N values (N>2):
x <- rep(c(1,2,5,4),50)
runs.test(factor(x))
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