Hi Jim. If I avoid the dataframe, how can use the function model.matrix() to
   build the incident matrices X, And Z? I tried saving the design as matrix
   but ghen I got the wrong design matrix.


   Thanks.

   Laz


   Sent from my LG Optimus G™, an AT&T 4G LTE smartphone
   ------ Original message ------
   From: jim holtman
   Date: 6/18/2014 3:49 PM
   To: Laz;
   Cc: R mailing list;
   Subject:Re: [R] How can I avoid the for and If loops in my function?

   First order of business, without looking in detail at the code, is to avoid
   the use of dataframes.  If all your values are numerics, then use a matrix.
    It will be faster execution.
   I did see the following statements:
          newmatdf<-Des[[i]]
          Des[[i]]<-newmatdf
   why are you just putting back what you pulled out of the list?

   Jim Holtman
   Data Munger Guru

   What is the problem that you are trying to solve?
   Tell me what you want to do, not how you want to do it.
   On Wed, Jun 18, 2014 at 12:41 PM, Laz <[1]lmra...@ufl.edu> wrote:

     Dear R-users,
     I have a 3200 by 3200 matrix that was build from a data frame that had
     180 observations,  with variables: x, y, blocks (6 blocks) and
     treatments (values range from 1 to 180) I am working on. I build other
     functions that seem to work well. However, I have one function that has
     many If loops and a long For loop that delays my results for over 10
     hours ! I need your help to avoid these loops.
     ########################################################
     ## I need to avoid these for loops and if loops here :
     ########################################################
     ### swapsimple() is a function that takes in a dataframe, randomly swaps
     two elements from the same block in a data frame and generates a new
     dataframe called newmatdf
     ### swapmainF() is a function that calculates the trace of the final N
     by N matrix considering the incident matrices and blocks and treatments
     and residual errors in a linear mixed model framework using Henderson
     approach.
     funF<- function(newmatdf, n, traceI)
     {
     # n = number of iterations (swaps to be made on pairs of elements of the
     dataframe, called newmatdf)
     # newmatdf : is the original dataframe with N rows, and 4 variables
     (x,y,blocks,genotypes)
        matrix0<-newmatdf
        trace<-traceI  ##  sum of the diagonal elements of the N by N matrix
     (generated outside this loop) from the original newmatdf dataframe
        res <- list(mat = NULL, Design_best = newmatdf, Original_design =
     matrix0) # store our output of interest
        res$mat <- rbind(res$mat, c(value = trace, iterations = 0)) #
     initialized values
        Des<-list()
        for(i in seq_len(n)){
          ifelse(i==1,
     newmatdf<-swapsimple(matrix0),newmatdf<-swapsimple(newmatdf))
          Des[[i]]<-newmatdf
          if(swapmainF(newmatdf) < trace){
            newmatdf<-Des[[i]]
            Des[[i]]<-newmatdf
            trace<- swapmainF(newmatdf)
            res$mat <- rbind(res$mat, c(trace = trace, iterations = i))
            res$Design_best <- newmatdf
          }
          if(swapmainF(newmatdf) > trace & nrow(res$mat)<=1){
            newmatdf<-matrix0
            Des[[i]]<-matrix0
            res$Design_best<-matrix0
          }
          if(swapmainF(newmatdf)> trace & nrow(res$mat)>1){
            newmatdf<-Des[[length(Des)-1]]
            Des[[i]]<-newmatdf
            res$Design_best<-newmatdf
          }
        }
        res
     }
     The above function was created to:
          Take  an original matrix, called matrix0, calculate its trace.
     Generate a new matrix, called newmatdf after  swapping two elements of the
      old one and  calculate the trace. If the trace of the newmatrix is
     smaller than
          that of the previous matrix, store both the current trace together
     with the older trace and their  iteration values. If the newer matrix has
     a trace larger than the previous trace, drop this trace and drop this
     matrix too (but count its iteration).
          Re-swap the old matrix that you stored previously and recalculate the
     trace. Repeat the
          process many times, say 10,000. The final results should be a list
          with the original initial matrix and its trace, the final best
          matrix that had the smallest trace after the 10000 simulations and a
          dataframe  showing the values of the accepted traces that
          were smaller than the previous and their respective iterations.
     $Original_design
           x  y block genotypes
     1    1  1     1        29
     7    1  2     1         2
     13   1  3     1         8
     19   1  4     1        10
     25   1  5     1         9
     31   1  6     2        29
     37   1  7     2         4
     43   1  8     2        22
     49   1  9     2         3
     55   1 10     2        26
     61   1 11     3        18
     67   1 12     3        19
     73   1 13     3        28
     79   1 14     3        10
     ------truncated ----
     the final results after running  funF<-
          function(newmatdf,n,traceI)  given below looks like this:
     ans1
     $mat
               value iterations
       [1,] 1.474952          0
       [2,] 1.474748          1
       [3,] 1.474590          2
       [4,] 1.474473          3
       [5,] 1.474411          5
       [6,] 1.474294         10
       [7,] 1.474182         16
       [8,] 1.474058         17
       [9,] 1.473998         19
     [10,] 1.473993         22
          ---truncated
     $Design_best
           x  y block genotypes
     1    1  1     1        29
     7    1  2     1         2
     13   1  3     1        18
     19   1  4     1        10
     25   1  5     1         9
     31   1  6     2        29
     37   1  7     2        21
     43   1  8     2         6
     49   1  9     2         3
     55   1 10     2        26
          ---- truncated
     $Original_design
           x  y block genotypes
     1    1  1     1        29
     7    1  2     1         2
     13   1  3     1         8
     19   1  4     1        10
     25   1  5     1         9
     31   1  6     2        29
     37   1  7     2         4
     43   1  8     2        22
     49   1  9     2         3
     55   1 10     2        26
     61   1 11     3        18
     67   1 12     3        19
     73   1 13     3        28
     79   1 14     3        10
     ------truncated
     Regards,
     Laz
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References

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