Hi,
suppose that we have a triangular upper matrix A
test - matrix(ncol = 4, nrow = 4)
test[1, ] - c(NA,1,1,1)
test[2, ] - c(NA,NA,1,1)
test[3, ] - c(NA,NA,NA,1)
test[4, ] - c(NA,NA,NA,NA)
I know how quickly set diagonal value diag(test) - 1. But how quickly set
down value i.e. matrix is
Mhy,
I think that this solution It doesn't work with odd dimension. Suppose we
have a reference matrix 13x13 (near i present a table format i.e save by
write.table). This matrix name a response2.
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11 V12 V13
1 0 1.4142135623731 1 1.73205080756888 1.4142135623731
Ok,
thanks this solution
test[lower.tri(test)] - t(test)[lower.tri(test)]
works perfectly well :)
Thanks
Best
marcin M.
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Hi,
I try use Rmpi package to my compute. In my work I'm using eclipse version
3.6.2 and statEt version 0.10.0 (launch Rterm or RJ). Actually I observed
strange behavior, when I try loading Rmpi directly I don't have any problem
i.e.:
library(Rmpi)
mpi.spawn.Rslaves()
8 slaves are spawned
I try loading Rmpi directly I don't have any problem i.e. I loading Rmpi by R
x64 2.12.2 (GUI)
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Hi,
thanks for response it's work perfect. Yes 't' is not good wariable it will
be 'test', my wrong.
Best
Marcin M.
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Hi,
It's my problem, supppose that we have a data.frame:
t
a b c
1 1 1 1
2 0 1 1
3 1 1 1
4 0 0 0
5 1 0 1
6 0 1 0
7 1 1 1
8 0 1 0
I need extract duplicat row i.e i nedd frame like this
a b c
3 1 1 1
8 0 1 0
I try use subset(t, duplicated(t)) and t[duplicated(t), ] but this command
return
Hi,
suppose we have a data in data.frame like a:
data
id q1 q2 q3 c
1 1 0 0 1 a
2 2 0 0 1 b
3 3 1 0 0 b
4 4 0 1 0 a
I need from this data receive cross validation table like a
a b -- classified as
2 0 | a = a
1 1 | b = b
Plus i need have information about 'id' i.e I
Hi,
Currently I testing the packets that contain built-in features for
classification. Actually I looked packages such as: e1071, Klar, Caret,
CORElearn. However, from what I noticed when building a naive Bayesian
classifier, that they package use of the finite mixture model to estimate P
(x | C)
Hi,
many thanks for helpful answer.
Best
Marcin M.--
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Hi,
thanks for response.
The Kolmogorov-Smirnov test is designed for distributions on continuous
variable, not discrete like the poisson. That is why you are getting
some of your warnings.
I read in Fitting distributions whith R Vito Ricci page 19 that: ...
Kolmogorov-Smirnov test is
This test SnowsPenultimateNormalityTest() is great :)
Best
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Hi,
I have a problem with Kolmogorov-Smirnov test fit. I try fit distribution to
my data. Actualy I create two test:
- # First Kolmogorov-Smirnov Tests fit
- # Second Kolmogorov-Smirnov Tests fit
see below. This two test return difrent result and i don't know which is
properly. Which result is
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