[R] Using Foreach for downloading data

Hi! I have this code which is working formula <- function(x){ return(x) } For( x in names) { x5 <- rbind(x5,formula(x)) } Now, I want to convert this code to parallel processing, so i am using foreach function foreach(x=names, .packages="checkpoint" ,.combine=

[R] using foreach function with gtrendsR

I have this code which is working library("checkpoint") library("gtrendsR") library("doParallel") cl<-makeCluster(4) registerDoParallel(cl) gconnect(usr = "em...@gmail.com", psw = "password", verbose = FALSE) names <- c("apple","shit", "android", "rocks") formula <- function(x){ x0 <- gtrends(x,

Re: [R] Need help with lm function on MAC OS X. R version - 3.2.0

e National Laboratory > 7000 East Ave., L-627 > Livermore, CA 94550 > 925-423-1062 > > > > > > On 5/14/15, 5:07 AM, "samarvir singh" wrote: > > >I Have a data frame named BSE and CP is my independent variable > >and here;s the error I get if

[R] Need help with lm function on MAC OS X. R version - 3.2.0

I Have a data frame named BSE and CP is my independent variable and here;s the error I get if I try to run an lm function any idea whats wrong P.S - all my data is in numeric except company which is a factor. I have 2700 row and 450 variable P.P.S - I have no missing data, I have 0 in Empty fiel

[R] Selecting cell values with XLSX package

Hello, I am working with some 2700 files in .xlsx format Like the one attached below I want to transform all tabular data to a single row as shown below in example or in attachment so that all data can be used as a variable. and replicate all to make a single csv file which has all the data EXAM

[R] Can't load CARET package, on Mac OS X (latest), on R version 3.1.2 (2014-10-31)

I installed CARET package, but when I try to load CARET. I see this error. Please help. thank you install.packages("caret") trying URL ' http://cran.rstudio.com/bin/macosx/mavericks/contrib/3.1/caret_6.0-41.tgz' Content type 'application/x-gzip' length 3997718 bytes (3.8 Mb) opened URL ==

Re: [R] how to Subset based on partial matching of columns?

rd to copy and > paste. Alternatively, don't post in HTML, because it screws up your > code. > > On Wed, Apr 8, 2015 at 8:57 PM, samarvir singh > wrote: > > So I have a list that contains certain characters as shown below > > > > `list <- c("MY",&qu

[R] how to Subset based on partial matching of columns?

So I have a list that contains certain characters as shown below `list <- c("MY","GM+" ,"TY","RS","LG")` And I have a variable named "CODE" in the data frame as follows `code <- c("MY GM+", ,"LGTY", "RS","TY")` 'x <- c(1:5) `df <- data.frame(x,code)` df x code 1 MY GM+ 2 3 LGT

[R] How to subset data, by sorting names alphabetically.

hello, I am cleaning some large data with 4 million observation and 7 variable. Of the 7 variables , 1 is name/string I want to subset data, which have same name Example- Name var1 var2 var3 var4 var5 var6 aa- - - - -- ab bd ac ad af ba bd aa av i want