[R] i can't read large NETCDF file like CRU

i use library(ncdf) to read this file as follow library(ncdf) sst.nc = open.ncdf(title) lonall = get.var.ncdf(sst.nc,'lon') latall = get.var.ncdf(sst.nc,'lat') precip = get.var.ncdf(sst.nc,'pre') close(sst.nc) if i use this method my pc freeze and not respond until i restart it is there -- View

Re: [R] what is the difference between using function predict() and coef() in prediction

X8 = c(0.42808332, 0.14058333, 0.30558333, 0.09558333, 0.01808333, -0.09191666, -0.11441666, -0.12941666, 0.13808333, -0.31691666, 0.25308333 ,-0.20941666 ,0.02808333, -0.04441667, -0.43691666) xy.lm = lm(Y~X8) z = predict(xy.lm,list(X8=X8)) sz = coef(xy.lm)[1]+(coef(xy.lm)[2])*X8 is

Re: [R] what is the difference between using function predict() and coef() in prediction

X8 = c(0.42808332, 0.14058333, 0.30558333, 0.09558333, 0.01808333, -0.09191666, -0.11441666, -0.12941666, 0.13808333, -0.31691666, 0.25308333 ,-0.20941666 ,0.02808333, -0.04441667, -0.43691666) Y =c(370.6 , 887.6 ,3610.88333 , 435.1 , 1261.38333 , -741.11667,-3231.36667

[R] what is the difference between using function predict() and coef() in prediction

i do not know what is the difference between predict() and coef() i use the two function give me different result zz = predict(xy.lm,list(T8=T8)) ss = coef(xy.lm)[1]+(coef(xy.lm)[2])*T8 where is t8 is the data used in prediction did not use in the fitting in training sample where every sample is