I have 5 items in total (1:5), but I show a person only 4 items (1:4)
and ask this person to rank items 1:4 in terms of preferences (1 is
best, 2 is second best, 4 is worst), and I get a vector of ranks:
ranks - c(2,4,3,1)
# That means that this person liked item 4 best and item 2 worst.
I would
## I leave it to you to add the NA edges
rk - c(2,4,3,1)
outer(rk,rk,)+0
[,1] [,2] [,3] [,4]
[1,]0110
[2,]0000
[3,]0100
[4,]1110
Cheers,
Bert
Bert Gunter
Data is not information. Information is not knowledge. And
Wow!
On Mon, Jul 27, 2015 at 5:28 PM, Bert Gunter bgunter.4...@gmail.com wrote:
## I leave it to you to add the NA edges
rk - c(2,4,3,1)
outer(rk,rk,)+0
[,1] [,2] [,3] [,4]
[1,]0110
[2,]0000
[3,]0100
[4,]1110
With NAs it'd be:
rk - c(2,NA,4,3,1, NA)
outer(rk, rk, ) + 0
Wow, I still can't believe it - just one line!
On Mon, Jul 27, 2015 at 5:31 PM, Dimitri Liakhovitski
dimitri.liakhovit...@gmail.com wrote:
Wow!
On Mon, Jul 27, 2015 at 5:28 PM, Bert Gunter bgunter.4...@gmail.com wrote:
## I leave
No it wouldn't.
Presumably you have a typo and meant
rk - c(2,4,3,1,NA)
## and set the (5,5) entry to 0 after
-- Bert
Bert Gunter
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
-- Clifford Stoll
On Mon, Jul 27, 2015 at 2:32 PM, Dimitri
Yes, correct, thank you, Bert!
On Mon, Jul 27, 2015 at 5:46 PM, Bert Gunter bgunter.4...@gmail.com wrote:
No it wouldn't.
Presumably you have a typo and meant
rk - c(2,4,3,1,NA)
## and set the (5,5) entry to 0 after
-- Bert
Bert Gunter
Data is not information. Information is not
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