Dear R forum,
I want to replace all the elements in a data frame (dd) which match the
character x with 0.
What's the most elegant way of doing this (there must be an easy way which
I've missed)? I settled on the following loop:
for(i in 5:12){# These are the column of dd I am
Here a way of doing it:
for (i in 5:12){
# convert to character so you can substitute 'x'
a - as.character(dd[,i])
a[a == 'x'] - '0' replace with zero
dd[,i] - as.numeric(a)
}
On Fri, Dec 4, 2009 at 11:55 AM, Allen L allen.laroc...@gmail.com wrote:
Dear R forum,
I want to
On Dec 4, 2009, at 11:55 AM, Allen L wrote:
Dear R forum,
I want to replace all the elements in a data frame (dd) which match
the
character x with 0.
What's the most elegant way of doing this (there must be an easy way
which
I've missed)? I settled on the following loop:
for(i in
3 matches
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