Here is another approach, just for fun:
library(tidyverse)
library(tokenizers)
anyall <- function(x, # a character vector
terms # a list of character vectors
){
any(map_lgl(terms, function(term) {
all(term %in% x)
}))
}
mutate(th,
flag
Sorry. Typo. The last line should be:
ans$Result <- apply(ans,1,function(r)phrasewords[[r[1]]] %allin%
tweets[[r[2]]])
-- Bert
On Thu, Oct 18, 2018 at 7:04 PM Bert Gunter wrote:
> All (especially Nathan): **Please feel free to ignore this post without
> response.** It just represents a bit
All (especially Nathan): **Please feel free to ignore this post without
response.** It just represents a bit of OCD-ness on my part that may or may
not be of interest to anyone else.
Purpose of this post: To give an alternative considerably simpler and
considerably faster solution to the problem t
If you wish to use R, you need to at least understand its basic data
structures and functionality. Expecting that mimickry of code in special
packages will suffice is, I believe, an illusion. If you haven't already
done so, you should go through a basic R tutorial or two (there are many on
the web;
I do not have your command of base r, Bert. That is a herculean effort! Here’s
what I spent my night putting together:
## Create search terms
## dput(st)
st <- structure(list(word1 = c("technique", "me", "me", "feel", "feel"
), word2 = c("olympic", "abused", "hurt", "hopeless", "alone"
), word3 =
OK, as no one else has offered a solution, I'll take a whack at it.
Caveats: This is a brute force attempt using R's basic regular expression
engine. It is inelegant and barely tested, so likely to be at best
incomplete and buggy, and at worst, incorrect. But maybe Nathan or someone
else on the li
The problem wasn't the data tibbles. You posted in html -- which you were
explictly warned against -- and that corrupted your text (e.g. some quotes
became "smart quotes", which cannot be properly cut and pasted into R).
Bert
On Tue, Oct 16, 2018 at 2:47 PM Nathan Parsons
wrote:
> Argh! Here a
Argh! Here are those two example datasets as data frames (not tibbles).
Sorry again. This apparently is just not my day.
th <- structure(list(status_id = c("x1047841705729306624",
"x1046966595610927105",
"x1047094786610552832", "x1046988542818308097", "x1046934493553221632",
"x10472274428997754
Thanks all for your patience. Here’s a second go that is perhaps more
explicative of what it is I am trying to accomplish (and hopefully in plain
text form)...
I’m using the following packages: tidyverse, purrr, tidytext
I have a number of tweets in the following form:
th <- structure(list(st
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