Here's what I would do. Let's assume that you are presenting the
results of the example on the cph help page. I agree with you that
the results should be presented on the hazard ratio scale. The Design
package provides appropriate plotting tools for creation of
publication quality
Thanks for your help!
2009/8/2 David Winsemius dwinsem...@comcast.net
Here's what I would do. Let's assume that you are presenting the results of
the example on the cph help page. I agree with you that the results should
be presented on the hazard ratio scale. The Design package provides
On Jul 31, 2009, at 11:24 PM, zhu yao wrote:
Could someone explain the summary(cph.object)?
The example is in the help file of cph.
n - 1000
set.seed(731)
age - 50 + 12*rnorm(n)
label(age) - Age
sex - factor(sample(c('Male','Female'), n,
rep=TRUE, prob=c(.6, .4)))
cens -
Thx for your reply.
In this example, age was transformed with rcs. So the output was different
between f and summary(f).
If I need to publicate the results, how do I explation the hazard ratio of
age?
2009/8/1 David Winsemius dwinsem...@comcast.net
On Jul 31, 2009, at 11:24 PM, zhu yao wrote:
zhu yao wrote:
Thx for your reply.
In this example, age was transformed with rcs. So the output was different
between f and summary(f).
If I need to publicate the results, how do I explation the hazard ratio of
age?
David explained this. Nonlinearity in age does not complicate the
Could someone explain the summary(cph.object)?
The example is in the help file of cph.
n - 1000
set.seed(731)
age - 50 + 12*rnorm(n)
label(age) - Age
sex - factor(sample(c('Male','Female'), n,
rep=TRUE, prob=c(.6, .4)))
cens - 15*runif(n)
h -
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