: socserv.mcmaster.ca/jfox
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On
Behalf Of Ocaña Riola, Ricardo
Sent: January-30-09 5:30 AM
To: r-help@r-project.org
Subject: [R] Factor Analysis-factanal function
Dear friends,
I'm using R
PROTECTED] On
Behalf Of [EMAIL PROTECTED]
Sent: Tuesday, October 07, 2008 2:29 PM
To: r-help@r-project.org
Subject: [R] Factor tutorial?
This is probably a very basic question. I want to understand factors
but I
am not sure where to turn. Looking up factor in the Chambers book
doesn't
This is probably a very basic question. I want to understand factors but I am
not sure where to turn. Looking up factor in the Chambers book doesn't even
show up in the index. Maybe I am just slow but ?factor doesn't help either.
Would someone please point me to a very basic tutorial where I
Hi Edna,
Because I am always subsetting, I keep the following function handy
mydata[] - lapply(mydata, function(x) if(is.factor(x)) x[,drop=T] else x)
This will strip out all factor levels that have been dropped by a previous
subsetting operation. For novice users of R (though I am not
Hello!
I have a problem whith a data.frame. I want to make a subset where some of the
variables have values within ceartain limits.
The variables are proportions like 1,00, 0,54, 0,00 etc.
I don't get it right as R take the variables for factors.
ekobsub1 - subset(ekob, PAP0,25 PAP0,6
The decimal point in R is always '.', never ','.
On Thu, 24 Apr 2008, Jojje Andersson wrote:
Hello!
I have a problem whith a data.frame. I want to make a subset where some of
the variables have values within ceartain limits.
The variables are proportions like 1,00, 0,54, 0,00 etc.
I don't
Hello!
Thanks!
I changed the , to . in both datafile and code but the problem remains
identical.
Cheers!
Jojje
Date: Thu, 24 Apr 2008 09:16:38 +0100 From: [EMAIL PROTECTED] To: [EMAIL
PROTECTED] CC: r-help@r-project.org Subject: Re: [R] Factor to numeric
The decimal point in R
__
Date: Thu, 24 Apr 2008 09:16:38 +0100
From: [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
CC: r-help@r-project.org
Subject: Re: [R] Factor to numeric
The decimal point in R is always '.', never ','.
On Thu, 24 Apr 2008, Jojje Andersson wrote:
Hello!
I have a problem whith
PROTECTED]
wrote:
Hello!
Thanks!
I changed the , to . in both datafile and code but the problem remains
identical.
Cheers!
Jojje
Date: Thu, 24 Apr 2008 09:16:38 +0100 From: [EMAIL PROTECTED] To:
[EMAIL PROTECTED] CC: r-help@r-project.org Subject: Re: [R] Factor
to numeric The decimal
but the problem
remains identical.
Cheers!
Jojje
Date: Thu, 24 Apr 2008 09:16:38 +0100 From:
[EMAIL PROTECTED] To: [EMAIL PROTECTED] CC:
r-help@r-project.org Subject: Re: [R] Factor to numeric The
decimal point in R is always '.', never ','. On Thu, 24 Apr
2008, Jojje Andersson wrote:Hello
Good Morning,
Is it possible to use the R program for a CFA with dichotomous data?
Thank you,
Kathleen
Kathleen Kemp, M.A.
Doctoral Clinical Psychology Student,
Concentration: Forensic Psychology
Drexel University
Philadelphia, PA 19104
[EMAIL PROTECTED]
[[alternative HTML version
you may check the ltm package:
http://wiki.r-project.org/rwiki/doku.php?id=packages:cran:ltm
I hope it helps.
Best,
Dimitris
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel:
, Ontario, Canada L8S 4M4
905-525-9140x23604
http://socserv.mcmaster.ca/jfox
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]
project.org] On Behalf Of Kathleen Kemp
Sent: January-12-08 9:11 AM
To: r-help@r-project.org
Subject: [R] Factor Analysis
Good Morning
- Original Message -
From: Christopher Marcum [EMAIL PROTECTED]
To: [EMAIL PROTECTED]
Sent: Thursday, December 20, 2007 8:33 AM
Subject: [R] factor manipulation: edgelist to a matrix?
Hello All,
I have had considerable bad luck with attempting the following with
for
loops. Here
You may be haning Ion coerced into a factor. Have a
look at
http://finzi.psych.upenn.edu/R/Rhelp02a/archive/98260.html
for some discussion of this.
I find that I usually set
options(stringsAsFactors = FALSE) just because of
this but as Gabor points out it may have its own
disadvantages in
Yep, but I figured that out quite fast ;0)
Thanks for giving me a hand ... you want believe a many times I skimmed the
cbind help without actually seeing this ... well, it was 0:30 ...
Thanks again, Joh
Tony Plate wrote:
Whoops, it looks like there's a typo in ?cbind (R version 2.6.0 Patched
Hello All,
I have had considerable bad luck with attempting the following with for
loops. Here is the problem:
# Suppose we have a data.frame with the following data, which can be
considered a type of edgelist (for those with networks backgrounds):
#
# V1 V2
# 1 A
#
From ?cbind:
Data frame methods
The cbind data frame method is just a wrapper for data.frame(...,
check.names = FALSE). This means that it will split matrix columns in data
frame arguments, and convert character columns to factors unless
stringsAsFactors = TRUE is passed.
(I'm guessing
On 3/10/2007, at 5:48 PM, Peter Dalgaard wrote:
Rolf Turner wrote:
I have factors with levels ``Unit, Achieved, and Scholarship;
I wish to replace these with
U, A, and S.
So I do
fff - factor(fff,labels=c(U,A,S))
This works as long as all of the levels are actually present in
On 4/10/2007, at 7:50 AM, Peter Dalgaard wrote:
Rolf Turner wrote:
Does it even work? (What if it is the first or the 2nd level that
is absent?
Yes it works. What's the problem?
To beat it to death: if the second level of fff is absent
then fff will consist entirely of 1's
Rolf Turner wrote:
P.S. ***Are*** there any risks/dangers in following Christos
Hatzis' suggestion of simply doing
levels(fff) - c(U,A,S) ???
Not if the levels are right to begin with.
Problems only arise if fff somehow becomes a two-level factor, e.g. if
you do
I have factors with levels ``Unit, Achieved, and Scholarship; I
wish to replace these with
U, A, and S.
So I do
fff - factor(fff,labels=c(U,A,S))
This works as long as all of the levels are actually present in the
factor. But if ``Scholarship'' is absent
(as if often is) then I
If you don't know ahead of time how many columns you have and
only that they are a mix of numeric and character (to be converted to
factor) then you can do this:
DF - read.table(textConnection(Input), header = TRUE, as.is = TRUE)
f - function(x) if (is.character(x)) factor(x, levels = unique(x))
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