Hi everyone,
Is there an easy way to combine the counts from table()?
Let's say that I have:
x<-1:4
y<-2:5
I want to replicate:
table(c(x,y))
using only table(x) and table(y) as input.
The reason is that it's cumbersome to carry all the values around when all I
care about are the counts. The
Hello,
Suppose your files list is called 'flist'. And that your files have
blanks as separators.
dflist <- lapply(flist, read.table, header=TRUE, stringsAsFactors=FALSE)
big <- do.call(rbind, dflist)
You can get a list of all files you want with list.files(). See
?list.files
Hope this hel
I have hundreds of text files which has data like a data frame with three
columns.The column names are same in all the files.I need to merge all files
into a single big file.
My files are like this
file1
"new.col" "ppm.p." "freq.p."
"1_3_diaminopropane" 3.13859 5.67516
"1_3_diaminopropane" 3.137 6.
Hi again,
Petr, your solution worked!
Thanks everyone for your input. I'll look more into "setdiff."
Cheers!
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Hi
If you used shorter names for your objects you will get probably more
readable advice
Is this what you wanted?
truncated_dataframe[truncated_dataframe$CLAIM_NO %in%
setdiff(truncated_dataframe$CLAIM_NO, truncated_list$CLAIM_NO),]
Regards
Petr
> Hi there,
> I've tried the noted solutions
Hi there,
I've tried the noted solutions:
"If you do `no <- unlist(hrc_78_clm_no`, do you get a character vector
of claim numbers you want to exclude? If so, then `subset(whatever,
!CLAIM_NO %in% no)` should work."
I converted the CLAIM_NO list to a character, with
> hrc78_clmno_char <- format
# dput() example
# lets say you have data called y, like this:
> y
sp1 sp2 sp3 sp4
d 0 0 0 0
e 0 0 0 0
f 0 0 0 0
# ok, so do this:
> dput(y)
structure(list(sp1 = c(0, 0, 0), sp2 = c(0, 0, 0), sp3 = c(0,
0, 0), sp4 = c(0, 0, 0)), .Names = c("sp1", "sp2", "sp3", "sp4"
)
Assuming everything else is good, the "all" or "all.x" or "all.y"
arguments to merge() should do what I think you're asking for. You did
read the help page for merge, right?
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
O
Hi there,
Thanks for your responses. I haven't used/heard of dput() before. I'm
looking it up & understanding how it works.
Thanks!
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Sent from the R help mailing list archive
Hi,
As Sarah reiterated -- it'd *really* be helpful if you give us data we
can actually work with.
That having been said:
On Thu, Apr 26, 2012 at 4:12 PM, RHelpPlease wrote:
> Hi again,
> I tried the sample code like this:
>
>> merged_clmno <- subset(bestPartAreadmin, !CLAIM_NO %in% hrc78_clm_n
You'd get better help if you actually did as Steve requested and
provided sample data (a reproducible example!) using dput().
But since you didn't:
> fakedata <- data.frame(a = 1:5, b=11:15, c=c(1,1,1,2,2))
> fakedata
a b c
1 1 11 1
2 2 12 1
3 3 13 1
4 4 14 2
5 5 15 2
> notb <- c(12, 14, 15)
>
Hi again,
I tried the sample code like this:
> merged_clmno <- subset(bestPartAreadmin, !CLAIM_NO %in% hrc78_clm_no)
> dim(merged_clmno)
[1] 1306893
Note that:
> dim(bestPartAreadmin)
[1] 1306893
So, no change between the original data.frame (bestPartAreadmin) & the
(should be) less-row
Hi Steve,
Thanks for replying. Here's a small piece of the data.frame:
> bestPartAreadmin[1:5,1:6]
DESY_SORT_KEY PRVDR_NUM CLM_THRU_DT CLAIM_NO
NCH_NEAR_LINE_REC_IDEN_CD NCH_CLM_TYPE_CD
1 10193 290003 20090323 20
Hi,
To increase the chances of you getting help on this one, please give
example data (a small data.frame, a small list) that you are trying to
do this on, and also show the desired output. Whip these variables up
in your R workspace and paste the output of `dput` for each into your
follow up emai
Hi there,
I wish to merge a common variable between a list and a data.frame & return
rows via the data.frame where there is NO match. Here are some details:
The list, where the variable/col.name = CLAIM_NO
CLAIM_NO
20
83
1440
4439
7002
...
> dim(hrc78_clm_no)
[1] 66781
The data.frame, where
Hello,
I am having trouble with the merge function.
I am trying to merge two dataframes.
Before I merge them I can get the value labels by using the command
attr(Dataframe_1$MyVariable,"value.labels")
attr(Dataframe_2$MyVariable,"value.lables")
Personen unter 15 Jahren Präsenz- und Zivildiener
to study for a while
thank you for your help
max
- Original Message - From: "MacQueen, Don"
To: "Massimo Bressan" ;
Sent: Monday, January 30, 2012 4:47 PM
Subject: Re: [R] merge multiple data frames
Does this example help? It doesn't handle the problem of
On Mar 16, 2012, at 5:51 AM, zhu free wrote:
Hi everyone,
I have a question for R code to merge.
Say I have two dataframes:
File1 is:
V1V2V3V4
1100101name1
2200201name2
2300301name3
3400401name4
3500501name5
4600601
Hi everyone,
I have a question for R code to merge.
Say I have two dataframes:
File1 is:
V1V2V3V4
1100101name1
2200201name2
2300301name3
3400401name4
3500501name5
4600601name6
4700701name7
File2 is:
V1
thanks don
I have here enough to study for a while
thank you for your help
max
- Original Message -
From: "MacQueen, Don"
To: "Massimo Bressan" ;
Sent: Monday, January 30, 2012 4:47 PM
Subject: Re: [R] merge multiple data frames
Does this example help? I
t;-sqldf("select a_b.*, c.* from a_b left join c on a_b.date=c.date")
>
>bye
>
>max
>
>
>
>
>
>- Original Message -
>From: "MacQueen, Don"
>To: "maxbre" ;
>Sent: Saturday, January 28, 2012 12:24 AM
>Subject: Re
thanks michael
it's working like a charm: that's exaclty what I was looking for
bye
max
- Original Message -
From: "R. Michael Weylandt"
To: "Massimo Bressan"
Cc:
Sent: Friday, January 27, 2012 4:16 PM
Subject: Re: [R] merge multiple data frames
O
t a_b.*, c.* from a_b left join c on a_b.date=c.date")
bye
max
- Original Message -
From: "MacQueen, Don"
To: "maxbre" ;
Sent: Saturday, January 28, 2012 12:24 AM
Subject: Re: [R] merge multiple data frames
Not tested, but this might be a case for the s
Not tested, but this might be a case for the sqldf package.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 1/26/12 9:29 AM, "maxbre" wrote:
>This is my reproducible example (three data frames: a, b, c)
>
>a<-structure
Massimo Bressan
wrote:
> I tested your code: it's OK but there is still the problem of the suffixes
> for the last dataframe
> thank you for the support
>
>
> - Original Message - From: "R. Michael Weylandt"
>
> To: "maxbre"
> Cc:
I tested your code: it's OK but there is still the problem of the suffixes
for the last dataframe
thank you for the support
- Original Message -
From: "R. Michael Weylandt"
To: "maxbre"
Cc:
Sent: Thursday, January 26, 2012 8:19 PM
Subject: Re: [R] m
thank you for your reply
I'll study and test your code (which is a bit obscure to me up to now);
by the way do you think that "merge_all" is a wrong way to hit?
thanks again
m
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Sent fr
I might do something like this:
mergeAll <- function(..., by = "date", all = TRUE) {
dotArgs <- list(...)
Reduce(function(x, y)
merge(x, y, by = by, all = all, suffixes=paste(".", names(dotArgs),
sep = "")),
dotArgs)}
mergeAll(a = a, b = b, c = c)
str(.Last.value)
You also might be able
This is my reproducible example (three data frames: a, b, c)
a<-structure(list(date = structure(1:6, .Label = c("2012-01-03",
"2012-01-04", "2012-01-05", "2012-01-06", "2012-01-07", "2012-01-08",
"2012-01-09", "2012-01-10", "2012-01-11", "2012-01-12", "2012-01-13",
"2012-01-14", "2012-01-15", "
On Oct 10, 2011, at 1:28 PM, Alaios wrote:
Dear all,
I have some device measurements and the time stamps I get from it
have the below format:
MyStruct$TimeStamps[1,]
[1] 2011.000 10.0006.000 16.000 23.000 30.539
I can convert them easily with ISOdate() to a number and do the
Dear all,
I have some device measurements and the time stamps I get from it have the
below format:
MyStruct$TimeStamps[1,]
> [1] 2011.000 10.000 6.000 16.000 23.000 30.539
I can convert them easily with ISOdate() to a number and do the calculations I
need.
One of my problems is that
Hi everybody,
I got a solution for my problem with Eric Paniagua (many thanks!)! Thank you
a lot everybody!
Paniagua said explained that I was losing row.names when I merged a
data.frame with a factor object (data2$color), because a factor objects
don't have row.names. Instead of merging data1 to
On Oct 7, 2011, at 9:34 AM, jdanielnd wrote:
Hello,
I am having some problems to use the 'merge' function. I'm not sure
if I got
its working right.
What I want to do is:
1) Suppose I have a dataframe like:
height width
11.12.3
22.1
I'm not sure if this solves the problem.
The NA cases are spread into de cases. This solution always returns the NA
cases for the last variables as the last cases.
It's not keeping the same row.names they have in data1.
What I want to do it return exactly the same data1 (cases in the same
order)
On 07.10.2011 15:34, jdanielnd wrote:
Hello,
I am having some problems to use the 'merge' function. I'm not sure if I got
its working right.
What I want to do is:
1) Suppose I have a dataframe like:
height width
11.12.3
22.1
Hello,
I am having some problems to use the 'merge' function. I'm not sure if I got
its working right.
What I want to do is:
1) Suppose I have a dataframe like:
height width
11.12.3
22.12.5
31.81.9
4
Sorry---I thought it worked but I think I am actually definitely doing
something wrong...
The problem might be that there are NA's and there are also duplicated
values...My fault. I can't figure out what is going wrong...
I'll be more thorough and modify the two df to mirror more what I have to
ex
Yes, your code did exactly what I needed.
Thank you!!
-f
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PLEASE do read the posting guide http://www.R-project.org/posting-gu
Hi,
On Mon, Oct 3, 2011 at 1:54 PM, francy wrote:
> Hi,
>
> I am trying to find a function to match two data frames of different lengths
> for one field only.
> So, for example,
> df1 is:
>
> Name Position location
> francesca A 75
> cristina B 36
>
> And df2 is:
>
> location Country
> 75 UK
> 5
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
> Behalf Of francy
> Sent: Monday, October 03, 2011 10:55 AM
> To: r-help@r-project.org
> Subject: [R] Merge two data frames and find common values and non-matching
> values
>
> Hi,
>
> I am tryin
Hi,
I am trying to find a function to match two data frames of different lengths
for one field only.
So, for example,
df1 is:
Name Position location
francesca A 75
cristina B 36
And df2 is:
location Country
75 UK
56 Austria
And I would like to match on "Location" and the output to be something
On Sep 2, 2011, at 9:30 AM, David Winsemius wrote:
On Sep 2, 2011, at 8:34 AM, Joao Fadista wrote:
Dear all,
I would like to know how to merge columns like:
Input file:
V1 V2 V3 V4 V5 V6
1 G A G G G G
2 A A G A A G
Looked like an mapply-type problem:
> with(dat,
mapply
On Sep 2, 2011, at 8:34 AM, Joao Fadista wrote:
Dear all,
I would like to know how to merge columns like:
Input file:
V1 V2 V3 V4 V5 V6
1 G A G G G G
2 A A G A A G
Looked like an mapply-type problem:
> with(dat,
mapply(paste,
list(V1, V3, V5),
Hi:
Here's one approach:
d <- read.table(textConnection("
V1 V2 V3 V4 V5 V6
1 G A G G G G
2 A A G A A G"), header = TRUE, stringsAsFactors = FALSE)
closeAllConnections()
# Create two vectors of variable names, one for odd numbered,
# one for even numbered
vars1 <- names(d)[seq_along(
Dear all,
I would like to know how to merge columns like:
Input file:
V1 V2 V3 V4 V5 V6
1 G A G G G G
2 A A G A A G
Desired output file:
V1 V2 V3
1 G/A G/G G/G
2 A/A G/A A/G
So for every 2 consecutive columns merge their content into one.
Thanks in advance.
[[al
On Tue, Aug 16, 2011 at 6:40 PM, Sam Steingold wrote:
>> * Ista Zahn [2011-08-16 18:31:00 -0400]:
>> On Tue, Aug 16, 2011 at 6:29 PM, Ista Zahn wrote:
>>> Hi Tia,
>
> "tia" == "thanks in advance" :-)
*facepalm* Thanks Sam, one day I'll learn internet acronyms...
>
>> AB3 <- AB2[order(AB$Time,
> * Ista Zahn [2011-08-16 18:31:00 -0400]:
> On Tue, Aug 16, 2011 at 6:29 PM, Ista Zahn wrote:
>> Hi Tia,
"tia" == "thanks in advance" :-)
> AB3 <- AB2[order(AB$Time, decreasing=TRUE), ]
> AB4 <- AB3[!duplicated(AB3[c("Name", "Open")]), ]
thanks!
--
Sam Steingold (http://sds.podval.org/) on
On Tue, Aug 16, 2011 at 6:29 PM, Ista Zahn wrote:
> Hi Tia,
>
> On Tue, Aug 16, 2011 at 6:00 PM, Sam Steingold wrote:
>> I have two datasets:
>> A with columns Open and Name (and many others, irrelevant to the merge)
>> B with columns Time and Name (and many others, irrelevant to the merge)
>>
>>
Hi Tia,
On Tue, Aug 16, 2011 at 6:00 PM, Sam Steingold wrote:
> I have two datasets:
> A with columns Open and Name (and many others, irrelevant to the merge)
> B with columns Time and Name (and many others, irrelevant to the merge)
>
> I want the dataset AB with all these columns
> Open from A -
I have two datasets:
A with columns Open and Name (and many others, irrelevant to the merge)
B with columns Time and Name (and many others, irrelevant to the merge)
I want the dataset AB with all these columns
Open from A - a difftime (time of day)
Time from B - a difftime (time of day)
Name (same
to have a well-defined problem from the outset.
-pd
>
> "Downey, Patrick" wrote:
>
> Hello,
>
> I'm clearly confused about the merge function. In the following
>
> r <- merge(x,y,all.x=T,all.y=F)
>
> my y vector has only unique values (no dupl
uot;Downey, Patrick" wrote:
Hello,
I'm clearly confused about the merge function. In the following
r <- merge(x,y,all.x=T,all.y=F)
my y vector has only unique values (no duplicates). So I don't understand
how this can ever generate an r which is of greater length than x.
I thou
n the following
r <- merge(x,y,all.x=T,all.y=F)
my y vector has only unique values (no duplicates). So I don't understand
how this can ever generate an r which is of greater length than x.
I thought the default behavior was only matching rows are included, but
that using all.x=T included rows w
Hello,
I'm clearly confused about the merge function. In the following
r <- merge(x,y,all.x=T,all.y=F)
my y vector has only unique values (no duplicates). So I don't understand
how this can ever generate an r which is of greater length than x.
I thought the default behavior was
Thank you Henrik and Rolf. My migraine just disappeared. : )
myobjects = ls(pattern='^RH')
dataobj = mget(myTemp,.GlobalEnv)
map = Reduce(merge,dataobj)
did the trick. do.call() didn't cut it for some reason . . . it
returned an " 'x' is missing " error. But Reduce works quite nicely for
On 10/06/11 14:57, Ben Zaitchik wrote:
Hello,
I have a large number of raster objects in memory, with names RH100,
RH101, RH102, etc. (myobjects <- ls(pattern='^RH')).
These rasters are sections of a continuous map, and I would like to
combine them using the RasterObject merge tool in package
...and ?mget for retrieving multiple objects as a list. /Henrik
On Thu, Jun 9, 2011 at 10:32 PM, Henrik Bengtsson wrote:
> See ?get and ?do.call. That should be enough.
>
> ?Reduce may be an alternative for do.call(), but could also be less
> memory efficient.
>
> My $.02
>
> /Henrik
>
> On Thu
See ?get and ?do.call. That should be enough.
?Reduce may be an alternative for do.call(), but could also be less
memory efficient.
My $.02
/Henrik
On Thu, Jun 9, 2011 at 7:57 PM, Ben Zaitchik wrote:
> Hello,
>
> I have a large number of raster objects in memory, with names RH100, RH101,
> RH
Hello,
I have a large number of raster objects in memory, with names RH100,
RH101, RH102, etc. (myobjects <- ls(pattern='^RH')).
These rasters are sections of a continuous map, and I would like to
combine them using the RasterObject merge tool in package 'raster.'
Merge expects an input list
Another possibility:
dfs <- list(df1, df2, df3)
df.1.2.3 <- as.data.frame(unlist(sapply(dfs, function(x) do.call(paste, x
On Mon, Jun 6, 2011 at 2:37 PM, Ista Zahn wrote:
> Hi Abraham,
> Just take it step by step. Paste the values together, combine them,
> and assign them to a data.frame col
Hi Abraham,
Just take it step by step. Paste the values together, combine them,
and assign them to a data.frame column. Like this perhaps:
df.1.2.3 <- data.frame(Var1 =
c(with(df1, paste(Var1, Var2, Var3)),
with(df2, paste(Var1, Var2)),
with(df3, paste(Var1, Var2
B
I have the following data:
prefix <- c("cheap", "budget")
roots <- c("car insurance", "auto insurance")
suffix <- c("quote", "quotes")
prefix2 <- c("cheap", "budget")
roots2 <- c("car insurance", "auto insurance")
roots3 <- c("car insurance", "auto insurance")
suffix3 <- c("quote", "quotes")
df
Eric -
As others have said, you should change the names of the variables
in the data frames before you merge them. Here's one implementation
of that idea:
DF.wave.1 <- data.frame(id=1:10,var.A=sample(letters[1:4],10,TRUE))
DF.wave.2 <- data.frame(id=1:10,var.M=sample(letters[5:8],10,TR
Is there anyone out there who can suggest a way to solve this problem?
Thanks,
Esben
On Sun, Apr 24, 2011 at 8:53 PM, Jeff Newmiller
wrote:
> Merge only lets you combine two tables at a time, but it does have a
> "suffix" argument that is intended to address your concern, but only for
> variable
Merge only lets you combine two tables at a time, but it does have a "suffix"
argument that is intended to address your concern, but only for variable names
that would conflict.
In your example, the id variables are all sequenced exactly the same, so you
could actually use cbind rather than mer
Dear R-list,
Here is my simple question,
I have n data frames that I would like to merge, but I can't figure
out how to add information about the origin of the variable(s).
Here is my problem,
DF.wave.1 <- data.frame(id=1:10,var.A=sample(letters[1:4],10,TRUE))
DF.wave.2 <- data.frame(id=1:10,va
Hi Kevin,
Sorry.it is not Bt ? A and B are two independent Matrices with equal number
rows and different number of columns.
dim (A)
[1] 30380 104
dim(B)
[1] 3038063
I want to combine both A and B to matrix C wheredim(C)
[1] 30380 167
So I got the answer
C<-cbind(A,B)
Thanks and reg
On 04/12/2011 10:54 AM, pankaj borah wrote:
I have two matrices A and B
dim (A)
[1] 30380 104
dim(Bt)
[1] 3038063
I want to combine both A and B to matrix C where
dim(C)
[1] 30380 167
How do I do that ?
Assuming that Bt is the transpose of B and you want C = [A|Bt] you coul
?cbind should solve your problem
2011-04-12 07:54 keltezéssel, pankaj borah írta:
> I have two matrices A and B
>
>> dim (A)
> [1] 30380 104
>
>> dim(Bt)
> [1] 3038063
>
> I want to combine both A and B to matrix C where
>> dim(C)
> [1] 30380 167
>
> How do I do that ?
>
>
> Regards,
>
I have two matrices A and B
> dim (A)
[1] 30380 104
> dim(Bt)
[1] 30380 63
I want to combine both A and B to matrix C where
>dim(C)
[1] 30380 167
How do I do that ?
Regards,
Pankaj Barah
Department of Biology,
Norwegian University of Science & Technology (NTNU)
Realfagbygget, N-
Thanks to both of you for your help!
Jim, my problem is to match some observations of a time serie (vector 'a' in
my example) with theoretical predictions of this process (vector 'b' in my
example), with a small time lag between them.
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View this message in context:
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use the sqldf package:
> require(sqldf)
> a
time x
1 1.0 4
2 2.2 5
3 5.2 6
> b
time y
10 1
21 3
32 5
44 7
55 9
> sqldf("
+ select a.time, a.x, b.y
+ from a, b
+ where abs(a.time - b.time) < 0.5
+ ")
time x y
1 1.0 4 3
2 2.2 5 5
3 5.2 6 9
>
On Mar 12, 2011, at 4:14 PM, flymer wrote:
Dear All,
Debuting in R, I'm facing a problem.
I have 2 vectors, say 'a' et 'b', and I'd like to merge them
according to
the proximity of their variable 'time'.
How to do to keep elements which satisfy (for example) 'a$time-b
$time<0.5'?
For exa
Dear All,
Debuting in R, I'm facing a problem.
I have 2 vectors, say 'a' et 'b', and I'd like to merge them according to
the proximity of their variable 'time'.
How to do to keep elements which satisfy (for example) 'a$time-b$time<0.5'?
For example :
> a
time x
1 1.0 4
2 2.2 5
3 5.2 6
>
The "merge" command is creating duplicate column names in a dataframe
that is the result of the merge. The following is the 'merge'
command:
x <- merge(invType
, allocSlots
, by.x = 'index'
, by.y = 'indx'
, all.x = TRUE
)
The 'invType' dataframe was the result of a previous
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of dms
Sent: Wednesday, March 02, 2011 3:16 PM
To: r-help@r-project.org
Subject: [R] merge( , by='row.names') slowness
I noticed that joining two data.frames in R using
I noticed that joining two data.frames in R using the "merge"
function that using by='row.names' slows things down substantially
when compared to just joining on a common index column.
Using a dataframe size of ~10,000 rows: it's as slow as 10 minutes in
the by='row.names' case versus merely 1 s
Thanks for the help -- merge.data.table was being used!
On Wed, Mar 2, 2011 at 12:25 AM, Steve Lianoglou <
mailinglist.honey...@gmail.com> wrote:
> Hi Ted,
>
> On Tue, Mar 1, 2011 at 9:45 PM, Ted Rosenbaum
> wrote:
> > Hi,
> > I am trying to use the merge command in the data.tables package.
> >
Hi Ted,
On Tue, Mar 1, 2011 at 9:45 PM, Ted Rosenbaum wrote:
> Hi,
> I am trying to use the merge command in the data.tables package.
> However, when I run the command I am not sure if it is running the merge
> command from the base package or the merge command from data.tables.
> When I run "met
Hi,
I am trying to use the merge command in the data.tables package.
However, when I run the command I am not sure if it is running the merge
command from the base package or the merge command from data.tables.
When I run "methods(generic.function="merge")' it informs me that
'merge.data.table" is
ilto:r-help-boun...@r-project.org]
> On Behalf Of Benjamin Caldwell
> Sent: Thursday, 10 February 2011 1:22 PM
> To: r-help
> Subject: [R] merge multiple .csv files
>
> Am trying to merge about 15 .csv tables - tried a test run but came up with
> 0 rows (no data for each variable/co
same class, and some values in common?
You do not give us very much to go on.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Benjamin Caldwell
Sent: Thursday, 10 February 2011 1:22 PM
To: r-help
Subject: [R] merge multiple .csv
On 02/09/2011 09:21 PM, Benjamin Caldwell wrote:
Am trying to merge about 15 .csv tables - tried a test run but came up with
0 rows (no data for each variable/column head)
CAHSEE.EA.feb.2009<-read.csv("2009 CAHSEE EA feb 2009.csv", header=TRUE)
CAHSEE.IM.MATH.2009<-read.csv("2009 CAHSEE Impact
Am trying to merge about 15 .csv tables - tried a test run but came up with
0 rows (no data for each variable/column head)
> CAHSEE.EA.feb.2009<-read.csv("2009 CAHSEE EA feb 2009.csv", header=TRUE)
> CAHSEE.IM.MATH.2009<-read.csv("2009 CAHSEE Impact Math.csv", header=TRUE)
> testmerge<-merge(CAHSE
On Wed, Feb 9, 2011 at 1:10 AM, Ad Flan wrote:
> Hi all,
> I'm trying to add updated data to an existing time series where an
> overlap exists. I need to give priority to the update data.
> My script runs every morning to collect data the updated data. There
> are quite often varied lengths, so on
Hi all,
I'm trying to add updated data to an existing time series where an
overlap exists. I need to give priority to the update data.
My script runs every morning to collect data the updated data. There
are quite often varied lengths, so once off solutions identifying rows
to solve this example wo
Not sure exactly what you mean by, writing a table with several rows per
file.
If what you want to do is write output to an external file, adding to it as
your loop progresses, then look at the functions
sink()
cat()
And their file and append arguments.
If what you want to do is appe
I’m running a loop opening one file after another.
>setwd("D:/Documents and Settings/trflp")
>a<-list.files()
>results.diversity<-data.frame(matrix(0,ncol=7,nrow=length(a)))
>names(results.diversity)<-c("file","simpson","shannon","eveness")
>x<-length(a)
>for (i in 1:x){
> trflp<-read.table(a[i
Hi All,
I'm getting some weird problems with merge(), which give me the
Error in match.names(clabs, names(xi)) :
names do not match previous names
Error.
I've found other people discussing this error, but they don't seem to match
my situation, and the strange thing is that changing the order
et as an error message this:
plot_shad_CR(CRX,CRY,1,CRagent,f)
Error in eval(expr, envir, enclos) : object 'z' not found
Calls: print ... lapply -> is.vector -> lapply -> FUN -> eval -> eval
From: Dennis Murphy
Cc: Rhelp
Sent: Sat, No
Dennis
>
> and I get as an error message this:
>
> plot_shad_CR(CRX,CRY,1,CRagent,f)
> Error in eval(expr, envir, enclos) : object 'z' not found
> Calls: print ... lapply -> is.vector -> lapply -> FUN -> eval -> eval
>
>
> -
Hi:
Perhaps a plus sign at the end of the line before geom_tile() would help.
Dennis
On Sat, Nov 20, 2010 at 6:30 AM, Alaios wrote:
> Hello everyone.
> I am using ggplot and I need some help to merge these two plots into one.
>
> plot_CR<-function(x,y,agentid,CRagent){
> library(ggplot2)
>
>
Hello everyone.
I am using ggplot and I need some help to merge these two plots into one.
plot_CR<-function(x,y,agentid,CRagent){
library(ggplot2)
agent<-CRagent[[agentid]] # To make following expression shorter
ggplot((data.frame(x=CRX,y=CRY,sr=agent$sr)))+
geom_point(aes(x,y,colour=cu
lto:r-help-boun...@r-
|> >> project.org] On Behalf Of Ralf B
|> >> Sent: Friday, November 12, 2010 12:07 AM
|> >> To: r-help Mailing List
|> >> Subject: [R] Merge postscript files into ps/pdf
|> >>
|> >> I created multiple pos
Thanks for all of your help. It works to me.
Kate
On Mon, Nov 15, 2010 at 10:06 AM, David Winsemius wrote:
>
> On Nov 15, 2010, at 10:42 AM, Kate Hsu wrote:
>
> Hi r users,
>>
>> I have two data sets (X1, X2). For example,
>> time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,21
On Mon, Nov 15, 2010 at 10:42 AM, Kate Hsu wrote:
> Hi r users,
>
> I have two data sets (X1, X2). For example,
> time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,211 )
> outpue1<-c(171 ,164 ,150 ,141 ,109 , 73 , 47 ,26 ,15 ,12 ,6 ,2 ,1 )
> X1<-cbind(time1,outpue1)
>
>
On Nov 15, 2010, at 10:42 AM, Kate Hsu wrote:
Hi r users,
I have two data sets (X1, X2). For example,
time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,
211 )
outpue1<-c(171 ,164 ,150 ,141 ,109 , 73 , 47 ,26 ,15 ,12 ,6 ,
2 ,1 )
X1<-cbind(time1,outpue1)
time2<-c(
See ?merge with argument all=TRUE and replace by 0 afterwards.
Uwe Ligges
On 15.11.2010 16:42, Kate Hsu wrote:
Hi r users,
I have two data sets (X1, X2). For example,
time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,211 )
outpue1<-c(171 ,164 ,150 ,141 ,109 , 73 , 47 ,26
Hi r users,
I have two data sets (X1, X2). For example,
time1<-c( 0, 8, 15, 22, 43, 64, 85, 106, 127, 148, 169, 190 ,211 )
outpue1<-c(171 ,164 ,150 ,141 ,109 , 73 , 47 ,26 ,15 ,12 ,6 ,2 ,1 )
X1<-cbind(time1,outpue1)
time2<-c( 0 ,8 ,15 , 22 ,43 , 64 ,85 ,106 ,148)
output2<-c(
On Fri, Nov 12, 2010 at 1:27 PM, Ralf B wrote:
> Assuming I would go into the trouble of messing with the existing R
> scripts that create mentioned postscripts/pdfs, how can I achieve that
> an array of scripts append to a single ps/pdf? I would want the first
> script to create the file if it do
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