Dear R-experts,
I write to you to know if somebody is aware of a R package (or function) able
to plot graphs for extrapolation.
I need to be clear on what extrapolation really is to me. It is when we use the
model for X variables outside the range of X variables that were used to
construct
Às 14:57 de 01/08/2023, Paul Bernal escreveu:
Dear friends,
I hope this email finds you all well. This is the dataset I am working
with:
dput(random_mod12_data2)
structure(list(Index = c(1L, 5L, 11L, 3L, 2L, 8L, 9L, 4L), x = c(5,
13, 25, 9, 7, 19, 21, 11), n = c(500, 500, 500, 500, 500, 500,
logistic_regmod2 <- glm(formula = ratio~x, family = binomial(logit), data =
random_mod12_data2, weights =n)
plot(ratio ~ x, data = random_mod12_data2)
pframe <- data.frame(x = sort(random_mod12_data2$x))
pframe$ratio <- predict(logistic_regmod2, newdata = pframe, type =
"response")
Dear friends,
I hope this email finds you all well. This is the dataset I am working
with:
dput(random_mod12_data2)
structure(list(Index = c(1L, 5L, 11L, 3L, 2L, 8L, 9L, 4L), x = c(5,
13, 25, 9, 7, 19, 21, 11), n = c(500, 500, 500, 500, 500, 500,
500, 500), r = c(100, 211, 391, 147, 122, 310,
a.cz/en/personal-data-protection-principles/
>> > <https://www.precheza.cz/en/personal-data-protection-principles/>*
>> >
>> > *Důvěrnost: *Tento e-mail a jakékoliv k němu připojené dokumenty jsou
>> > důvěrné a podléhají tomuto právně závaznému prohlášení
jakékoliv k němu připojené dokumenty jsou
> > důvěrné a podléhají tomuto právně závaznému prohlášení o vyloučení
> > odpovědnosti: *https://www.precheza.cz/01-dovetek/
> > <https://www.precheza.cz/01-dovetek/>* | This email and any documents
> > attached to it may b
hed to it may be confidential and are subject to the legally binding
> disclaimer: *https://www.precheza.cz/en/01-disclaimer/
> <https://www.precheza.cz/en/01-disclaimer/>*
>
>
>
> *From:* Anupam Tyagi
> *Sent:* Friday, July 7, 2023 12:48 PM
> *To:* PIKAL Petr
> *Cc:*
M
To: PIKAL Petr
Cc: r-help@r-project.org
Subject: Re: [R] Plotting factors in graph panel
Thanks! You are correct, the graphs look very similar, except ggplot is scaling
the text font to make it more readable. Is there a way to scale down the x-axis
labels, so they are readable?
; From: R-help On Behalf Of Deepayan Sarkar
> > Sent: Thursday, July 6, 2023 3:06 PM
> > To: Anupam Tyagi
> > Cc: r-help@r-project.org
> > Subject: Re: [R] Plotting factors in graph panel
> >
> > On Thu, 6 Jul 2023 at 15:21, Anupam Tyagi wrote:
> > >
&
Current 2", "Bank Current 2",
> > > "Bank Current 2", "Bank Current 2", "Bank Savings 2", "Bank Savings 2",
> > > "Bank Savings 2", "Bank Savings 2", "Bank Savings 2", "MF None 3",
> &g
ent: Thursday, July 6, 2023 3:06 PM
> To: Anupam Tyagi
> Cc: r-help@r-project.org
> Subject: Re: [R] Plotting factors in graph panel
>
> On Thu, 6 Jul 2023 at 15:21, Anupam Tyagi wrote:
> >
> > Btw, I think "lattice" graphics will provide a better solution than
;, "Bank Current 2", "Bank Current 2", "Bank Current 2",
> > "Bank Current 2", "Bank Current 2", "Bank Savings 2", "Bank Savings 2",
> > "Bank Savings 2", "Bank Savings 2", "Bank Savings 2
ot;Bank Savings 2", "Bank Savings 2", "MF None 3",
> "MF None 3", "MF None 3", "MF None 3", "MF None 3", "MF Equity 3",
> "MF Equity 3", "MF Equity 3", "MF Equity 3", "MF Equity 3", "MF
None 3",
"MF None 3", "MF None 3", "MF None 3", "MF None 3", "MF Equity 3",
"MF Equity 3", "MF Equity 3", "MF Equity 3", "MF Equity 3", "MF Debt 3",
"MF Debt 3", "MF Debt 3&q
I am working with Jim's solution, but I am getting some errors. I organized
the data in Excel and read into R using the Import option in the menu of
R-Studio. For some reason it is telling me my data is a Tibble and not a
dataframe. Am I using Tidyverse unknowingly? I thought I was working in
On Behalf Of Anupam Tyagi
> Sent: Monday, July 3, 2023 11:54 AM
> To: Jim Lemon
> Cc: r-help mailing list
> Subject: Re: [R] Plotting factors in graph panel
>
> Attached is another example plot, that is better than the earlier one.
>
> On Mon, 3 Jul 2023 at 15:21, Anupam Tya
Attached is another example plot, that is better than the earlier one.
On Mon, 3 Jul 2023 at 15:21, Anupam Tyagi wrote:
> I thought maybe I can share with you how the data looks in Excel, and an
> example plot I found on the web that looks similar to what I want to plot.
> These are attached to
Thanks Jim, thanks everyone. I was caught up with work and moving home, so
a delay in response. I tried running the code you provided and it is not
running well in my R-Studio setup. It is giving errors and not producing
plots. I don't yet understand all the code well yet, so I need to work on
it
Okay. Here is a modification that does four single line plots.
at_df<-read.table(text=
"Income MF MF_None MF_Equity MF_Debt MF_Hybrid Bank_None Bank_Current
Bank_Savings Bank_NA
$10 1 3.05 29.76 31.18 36.0 46.54 24.75 25.4 3.307
$25 2 2.29 28.79 32.64 36.27 54.01 24.4 18.7 2.891
$40 3 2.24
w
> $10 do not make much sense compared to other values.
>
> I am tired of guessing.
>
> Tim
>
> -Original Message-
> From: R-help On Behalf Of Anupam Tyagi
> Sent: Wednesday, June 28, 2023 11:49 PM
> To: r-help@r-project.org
> Subject: Re: [R] Plotting f
. The values below $10 do not
make much sense compared to other values.
I am tired of guessing.
Tim
-Original Message-
From: R-help On Behalf Of Anupam Tyagi
Sent: Wednesday, June 28, 2023 11:49 PM
To: r-help@r-project.org
Subject: Re: [R] Plotting factors in graph panel
[External Email
riable names to fit your needs.
Cheers
Petr
> -Original Message-
> From: R-help On Behalf Of Anupam Tyagi
> Sent: Thursday, June 29, 2023 5:49 AM
> To: r-help@r-project.org
> Subject: Re: [R] Plotting factors in graph panel
>
> Thanks, Pikal and Jim. Yes, it has been
Thanks, Pikal and Jim. Yes, it has been a long time Jim. I hope you have
been well.
Pikal, thanks. Your solution may be close to what I want. I did not know
that I was posting in HTML. I just copied the data from Excel and posted in
the email in Gmail. The data is still in Excel, because I have
Hi Anupam,
Haven't heard from you in a long time. Perhaps you want something like this:
at_df<-read.table(text=
"Income MF MF_None MF_Equity MF_Debt MF_Hybrid Bank_None Bank_Current
Bank_Savings Bank_NA
$10 1 3.05 29.76 31.18 36.0 46.54 24.75 25.4 3.307
$25 2 2.29 28.79 32.64 36.27 54.01 24.4
> -Original Message-
> From: R-help On Behalf Of Anupam Tyagi
> Sent: Wednesday, June 28, 2023 10:34 AM
> To: R-help@r-project.org
> Subject: [R] Plotting factors in graph panel
>
> Hello,
>
> I want to plot the following kind of data (percentage of respondents f
Hello,
I want to plot the following kind of data (percentage of respondents from a
survey) that varies by Income into many small *line* graphs in a panel of
graphs. I want to omit "No Answer" categories. I want to see how each one
of the categories (percentages), "None", " Equity", etc. varies by
Perhaps the ragg package? That has an `agg_capture` device "that lets
you access the device buffer directly from your R session."
https://github.com/r-lib/ragg
HTH,
Jan
On 28-05-2023 13:46, Duncan Murdoch wrote:
Is there a way to open a graphics device that plots entirely to an array
On Sun, May 28, 2023 at 1:46 PM Duncan Murdoch wrote:
>
> Is there a way to open a graphics device that plots entirely to an array
> or raster in memory? I'd prefer it to use base graphics, but grid would
> be fine if it makes a difference.
>
> For an explicit example, I'd like to do the
Is there a way to open a graphics device that plots entirely to an array
or raster in memory? I'd prefer it to use base graphics, but grid would
be fine if it makes a difference.
For an explicit example, I'd like to do the equivalent of this:
filename <- tempfile(fileext = ".png")
Dear List member,
My data are from 30 years of opportunistic counting of migratory Eurasian
Curlew (Numenius arquata) during the core breeding season when the local
population is supposed to be stable. My main objective is the trend in numbers
over the years, but information about sighting
om: R-help On Behalf Of Erin Hodgess
Sent: Thursday, November 10, 2022 8:46 PM
To: r-help@r-project.org
Subject: [R] Plotting a triangular prism
[External Email]
Hello!
I'm trying to draw a triangular prism. I have used rgl, plot3d, and it's still
not working as I would like.
Has anyone done th
Great, thank you!
Sincerely,
Erin
On Thu, Nov 10, 2022 at 11:56 PM Jim Lemon wrote:
> Hi Erin,
> If you want a realistic 3D prism, I would use something like POVRay or
> other rendering software. You have to know your geometry, but you can
> get a very realistic image. I suspect that you want
Hi Erin,
If you want a realistic 3D prism, I would use something like POVRay or
other rendering software. You have to know your geometry, but you can
get a very realistic image. I suspect that you want more than just a
picture of a prism, so you can then generate a PNG image and use it as
a layer
One might think that after all these years you would have understood that “it’s
not working” is an excessively imprecise description of, well, anything.
Also html is deprecated severely on Rhelp.
—
David.
Sent from my iPhone
> On Nov 10, 2022, at 5:46 PM, Erin Hodgess wrote:
>
> Hello!
Hello!
I’m trying to draw a triangular prism. I have used rgl, plot3d, and it’s
still not working as I would like.
Has anyone done this, please?
Thanks for any help.
Sincerely,
Erin
--
Erin Hodgess, PhD
mailto: erinm.hodg...@gmail.com
[[alternative HTML version deleted]]
Hi Nick,
If you can bear using R base graphics, the plotrix package has a
function named "getYmult" that allows you to adjust for the aspect
ratio of any plot area.
Jim
On Sun, Apr 3, 2022 at 11:14 PM Nick Wray wrote:
>
> Hello If you plot a square in the default R studio window you see a
>
... and following up on Rui's reply, assuming that the default (in R,
not RStudio) "m" is being used, I would assume that the aspect ratio
in the RStudio device depends on the layout of your windows. Also, you
might do better asking here, https://community.rstudio.com/ , than on
this list.
Bert
Hello,
There's a graphics parameter for aspect ratio that you can set asp=1 on
a plot by plot basis. But you also need to change pty. From ?par:
pty
A character specifying the type of plot region to be used; "s" generates
a square plotting region and "m" generates the maximal plotting
Hi Eliza
This seems to work:
plot(BFA3[,1],BFA3[,4],
pch=16, xlab = "", ylab = "",col=(BFA3[,2]==BFA3[,3])+2,axes=FALSE)
but I have no idea what you are trying to do with the
as.numeric(as.Date(...))
business.
Jim
On Fri, Sep 3, 2021 at 8:44 AM Eliza Botto wrote:
>
> Dear useRs,
>
> For
Dear useRs,
For the following dataset,
dput(BFA3)
structure(c(17532, 17533, 17534, 17535, 17536, 17537, 17538,
17539, 17540, 17541, 17542, 17543, 17544, 17545, 17546, 17547,
17548, 17549, 17550, 17551, 17552, 17553, 17554, 17555, 17556,
17557, 17558, 17559, 17560, 17561, 17562, 17563, 17564,
On Mon, 2 Aug 2021 17:53:34 +0100
Rui Barradas wrote:
> Hello,
>
> I'm glad it helped.
> Here are a couple of ideas for theme.
Thanks Rui. The scope of your knowledge and understanding is simply
amazing!
cheers,
Rolf
--
Honorary Research Fellow
Department of Statistics
University of
Hello,
I'm glad it helped.
Here are a couple of ideas for theme.
1) From ?theme:
Theme inheritance
Theme elements inherit properties from other theme elements
hierarchically. For example, axis.title.x.bottom inherits from
axis.title.x which inherits from axis.title, which in turn inherits
I would like to tie off this thread (?!?!) by thanking Jeff Newmiller,
Rui Barradas, Avi Gross and Bill Dunlap for their advice and insight.
I have attached the code that I finally put together, on the basis of
the aforementioned advice, in the file ciPlot.txt. I have also
attached the
Thanks to Bill Dunlap and Avi Gross for their clear and helpful answers
to my questions.
cheers,
Rolf Turner
--
Honorary Research Fellow
Department of Statistics
University of Auckland
Phone: +64-9-373-7599 ext. 88276
__
R-help@r-project.org
Of Rolf Turner
Sent: Monday, July 19, 2021 7:24 PM
To: r-help@r-project.org
Subject: Re: [R] Plotting confidence intervals with ggplot, in multiple facets.
Thanks to Jeff Newmiller, Rui Barradas and Avi Gross for their extremely
helpful replies. I have got both Jeff's and Rui's code
ggplot2::labs() interprets expressions as plotmath. E.g.,
data.frame(X=1:10,Y=(1:10)^2) %>% ggplot(aes(X,Y)) + geom_point() +
labs(x = expression(beta), y = expression(beta^2))
-Bill
On Mon, Jul 19, 2021 at 4:24 PM Rolf Turner wrote:
>
>
> Thanks to Jeff Newmiller, Rui Barradas
Thanks to Jeff Newmiller, Rui Barradas and Avi Gross for their
extremely helpful replies. I have got both Jeff's and Rui's code to
run. I am currently experimenting with Avi's suggestion of producing
multiple plots and then putting them together using plotgrid() or
grid.arrange(). This idea
error bars being displayed with parts
below zero so showing where zero is graphically can be useful.
-Original Message-
From: R-help On Behalf Of Rolf Turner
Sent: Sunday, July 18, 2021 2:17 AM
To: r-help@r-project.org
Subject: [R] Plotting confidence intervals with ggplot, in multiple f
Hello,
Something like this?
library(ggplot2)
eg <- dget("data/egData.txt")
ggplot(eg, aes(Ndat, estimate)) +
� geom_errorbar(aes(ymin = lower, ymax = upper), width = 20) +
� geom_point(colour = "slateblue", size = 1) +
� geom_hline(yintercept = 0, colour = "red") +
� facet_grid(param ~ .)
ggplot(dta,aes(x=Ndat,y=estimate, ymin=lower,ymax=upper))+
geom_point() +
geom_errorbar(width=30) +
facet_grid(param~1) +
theme_minimal()
Width parameter seems odd... play with it I suppose.
For facets, you can also use facet_wrap(~param, ncol=1).
ggplot is very much about the data and
I have need of creating a plot displaying confidence intervals
(for the mean bias in parameter estimates) with one panel or facet
for each of the two parameters in question.
I can do this in base R graphics, but the result is not as
aesthetically pleasing as I would like. I have attached an
Thanks to Ivan Krylov, David Winsemius and Duncan Murdoch for their
informative replies to my cri de coeur. The most complete answer was
however provided off-list by Andrew Simmons who wrote a new and
carefully structured function plotASCII() to replace my old no-longer
functioning plot_ascii()
On 03/07/2021 9:59 p.m., Rolf Turner wrote:
... deletia ...
Also note that there is a bit of difference between the results of using
Encoding() and the results of using iconv(). E.g. if I do
a <- "\x80"
b <- iconv(a,"latin1","UTF-8")
Encoding(a) <- "latin1"
then when I type "a" I get the
On Sun, 4 Jul 2021 13:59:49 +1200
Rolf Turner wrote:
> a substantial number of the characters are displayed as a wee
> rectangle containing a 2 x 2 array of digits such as
>
> > 0 0
> > 8 0
Interesting. I didn't pay attention to it at first, but now I see that
a range of code points,
Sent from my iPhone
> On Jul 3, 2021, at 7:00 PM, Rolf Turner wrote:
>
>
>> On Sat, 3 Jul 2021 09:40:28 +0200
>> Ivan Krylov wrote:
>>
>> Hello Rolf Turner,
>>
>> On Sat, 3 Jul 2021 14:02:59 +1200
>> Rolf Turner wrote:
>>
>>> Can anyone suggest how I might get my plot_ascii() function
On Sat, 3 Jul 2021 09:40:28 +0200
Ivan Krylov wrote:
> Hello Rolf Turner,
>
> On Sat, 3 Jul 2021 14:02:59 +1200
> Rolf Turner wrote:
>
> > Can anyone suggest how I might get my plot_ascii() function working
> > again? Basically, it seems to me, the question is: how do I
> > persuade R to
Hello Rolf Turner,
On Sat, 3 Jul 2021 14:02:59 +1200
Rolf Turner wrote:
> Can anyone suggest how I might get my plot_ascii() function working
> again? Basically, it seems to me, the question is: how do I persuade
> R to read in "\260" as "\ub0" rather than "\xb0"?
Part of the problem is that
I have (used to have?) a function plot_ascii() which would display the
ascii character set in a graphical display. It simply used text() to
place the symbols on a 16 x 16 grid. The labels used by text() were
taken from a character vector that I called "all.ascii". According to
my notes, the
Hi, John,
it should work the same way as without interaction (but make sure
to use the fitted object "coxfit", not just "fit" in our call of
survfit, and note that age*rx already expands to age + rx + age:rx
so that age + rx is redundant in your formula):
coxfit <- coxph(Surv(futime, fustat) ~
Perhaps this might be useful:
https://rpubs.com/tf_peterson/interactionplotDemo
Bert Gunter
"The trouble with having an open mind is that people keep coming along and
sticking things into it."
-- Opus (aka Berkeley Breathed in his "Bloom County" comic strip )
On Thu, May 20, 2021 at 10:29 AM
Colleagues,
I hope someone can tell me how to plot a cox model that contains an interaction
term.
I know that plot(survfit(. . . . )) can be used to plot a Cox model, i.e..
coxfit <- coxph(Surv(futime, fustat) ~ age+rx, data = ovarian)
plot(survfit(fit, newdata=data.frame(age=60,rx=2)))
but
Hello,
Can you post sample data? For instance, the output of
dput(head(dovrez, 20))
dput(head(rqa_df_USD, 20))
Or maybe you could rbind the data.frames with one column telling which
of Res or LAM the values come from.
Hope this helps,
Rui Barradas
Às 19:38 de 02/05/21, Baki UNAL via
Hi
I'm trying to plot two time series in one graph. I tried the following code:
p = ggplot() +
geom_line(data = dovrez, aes(x = Date, y = Res), color = "blue") +
geom_line(data = rqa_df_USD, aes(x = DATE, y = LAM), color = "red") +
xlab('Dates') +
ylab('Values')
print(p)
But I got the
On 2021-04-05 03:34, Sorkin, John wrote:
Colleagues,
I am using the coxph to model survival time. How do I plot an adjusted Kaplan
Meir plot resulting from coxph? The code I would like to run would start with:
# run cox model
fit1Cox <- coxph(surv_object ~age+sex,data=mydata)
I have no
Hi
Google answered
https://rdrr.io/bioc/survcomp/man/km.coxph.plot.html
Is it what do you want?
Cheers
Petr
> -Original Message-
> From: R-help On Behalf Of Sorkin, John
> Sent: Monday, April 5, 2021 3:35 AM
> To: r-help@r-project.org (r-help@r-project.org)
> Subjec
On 2021-04-04 10:45 p.m., John Fox wrote:
Dear John,
I think that what you're looking for is
plot(survfit(fit1Cox, newdata=data.frame(age=rep(65, 2),
sex=factor("female", "male"
Whoops, that should be
plot(survfit(fit1Cox, newdata=data.frame(age=rep(65, 2),
sex=factor(c("female",
Dear John,
I think that what you're looking for is
plot(survfit(fit1Cox, newdata=data.frame(age=rep(65, 2),
sex=factor("female", "male"
assuming, of course, that sex is a factor with levels "female" and "male".
I hope this helps,
John
John Fox, Professor Emeritus
McMaster University
Colleagues,
I am using the coxph to model survival time. How do I plot an adjusted Kaplan
Meir plot resulting from coxph? The code I would like to run would start with:
# run cox model
fit1Cox <- coxph(surv_object ~age+sex,data=mydata)
I have no idea what would follow.
I would like to plot
Awesome, thanks! I will make corrections and see if it will work.
On Sat, Feb 13, 2021 at 6:04 AM David Winsemius
wrote:
>
>
> Sent from my iPhone
>
> > On Feb 12, 2021, at 9:01 PM, David Winsemius
> wrote:
> >
> >
> >
> > Sent from my iPhone
> >
> >> On Feb 12, 2021, at 1:35 PM, Jibrin
Sent from my iPhone
> On Feb 12, 2021, at 9:01 PM, David Winsemius wrote:
>
>
>
> Sent from my iPhone
>
>> On Feb 12, 2021, at 1:35 PM, Jibrin Alhassan
>> wrote:
>>
>> Hello Romanus,
>> You are to post only the code and the error messages and not all the
>> information from your
Sent from my iPhone
> On Feb 12, 2021, at 1:35 PM, Jibrin Alhassan
> wrote:
>
> Hello Romanus,
> You are to post only the code and the error messages and not all the
> information from your terminal in R session.
That’s not actually the best practice for rhelp questions. More info is
Hello Romanus,
You are to post only the code and the error messages and not all the
information from your terminal in R session.
On Fri, Feb 12, 2021, 4:35 PM Romanus Ejike
wrote:
> Please, I need help from anyone that can solve this problem.
> I wanted to plot a world map with locations and
Please, I need help from anyone that can solve this problem.
I wanted to plot a world map with locations and names of the locations but
could not. The codes I have tried are as shown below.
ugwoke@ugwoke-HP-ENVY-Laptop-13-aq0xxx:~/Desktop$ R
R version 4.0.3 (2020-10-10) -- "Bunny-Wunnies Freak
I have used the ggplot2 package to create a world map, the png file of the
output is attached. The code I use is below:
library(ggplot2)
library(mapproj)
long_Min <- -180.0
long_Max <- 180.0
lat_Min <- -50.0
lat_Max <- 80.0
Width <- 12.0
Height <- 2.0*Width*(lat_Max-lat_Min)/(long_Max-long_Min)
Thanks, I'll check it out.
On Fri, Feb 7, 2020 at 1:08 PM Martin Morgan
wrote:
> Probably have more success asking on https://support.bioconductor.org.
>
> Martin Morgan
>
> On 2/7/20, 12:57 PM, "R-help on behalf of pooja sinha" <
> r-help-boun...@r-project.org on behalf of
Probably have more success asking on https://support.bioconductor.org.
Martin Morgan
On 2/7/20, 12:57 PM, "R-help on behalf of pooja sinha"
wrote:
Hi All,
I have a file list consisting of Chromosome, Start , End & Methylation
Difference in the following format in excel:
Hi All,
I have a file list consisting of Chromosome, Start , End & Methylation
Difference in the following format in excel:
Chrom Start End Meth. Diff
chr1 38565900 38566000 -0.20276818
chr1 38870400 38870500 -0.342342342
chr1 39469400 39469500 -0.250260552
Thanks so much Jim. Yes, this is giving me what I want.
Philip
On 2019-12-08 05:00, Jim Lemon wrote:
Hi Philip,
This may be a starter:
attach(airquality)
heights <- tapply(Temp,Month,mean)
temp_sd<-tapply(Temp,Month,sd)
lower <- tapply(Temp,Month,function(v) t.test(v)$conf.int[1])
upper <-
Hi Philip,
This may be a starter:
attach(airquality)
heights <- tapply(Temp,Month,mean)
temp_sd<-tapply(Temp,Month,sd)
lower <- tapply(Temp,Month,function(v) t.test(v)$conf.int[1])
upper <- tapply(Temp,Month,function(v) t.test(v)$conf.int[2])
library(plotrix)
Thanks for these helpful suggestions.
These options don't work in my case because I don't know the individual
observations (the dots). A statistical agency collects the observations
and keeps them confidential. It provides the mean value and the standard
deviation, plus the fact that the
Hi,
Would something like yarrr do the trick?
https://ndphillips.github.io/yarrr.html
Or gghalves? https://github.com/erocoar/gghalves
Cheers,
Ben
On Sat, Dec 7, 2019 at 9:32 PM wrote:
> I want to show little bell curves on my bar chart to illustrate the
> confidence ranges. The following
I want to show little bell curves on my bar chart to illustrate the
confidence ranges. The following example from Paul Teetor's "R Cookbook"
does what I want, but shows I-beams instead of bell curves. The I-beams
suggest uniform, rather than normal distributions. So I am looking for a
way to
Hello,
I don't know if you want something like this:
hc_long <- reshape::melt(hc, id.vars = "Cluster") # convert to long format
library(ggplot2)
ggplot(hc_long, aes(x = Cluster, y = value, colour = variable)) +
geom_point() +
geom_line() +
coord_flip() +
facet_wrap(~ variable)
#Data
R Help Forum
I have output from hierarchal clustering and want to plot the results using
the ggplot2 function. Where I have a scatter plot with 5 lines representing
the 5 clusters. I assuming I need to transform the data into three columns
(like) cluster, variable, and value. Not an issue but was
ssage-
From: Jim Lemon
Sent: Thursday, July 18, 2019 5:25 AM
To: nst...@gmail.com
Cc: r-help mailing list
Subject: Re: [R] Plotting in R
Hi Steven,
I caved in and installed plotly. Not an easy task. When I tried your example, I
got a blank HTML page displayed. I then created a plot with
t;array",
> tickangle = 270
> ))
>
> Any ideas?
>
> Thanks,
> Steven
>
> -Original Message-
> From: nst...@gmail.com
> Sent: Tuesday, July 16, 2019 9:55 AM
> To: 'Jim Lemon'
> Cc: 'r-help mailing list'
> Subject: RE: [R] Plottin
, 2019 9:55 AM
To: 'Jim Lemon'
Cc: 'r-help mailing list'
Subject: RE: [R] Plotting in R
OK, I think I got this:
For example every 3rd element would be:
sydf$monthday[seq(1, length(sydf$monthday), 3)]
Thanks,
Steven
-Original Message-
From: nst...@gmail.com
Sent: Tuesday, July 16, 2019 9:3
OK, I think I got this:
For example every 3rd element would be:
sydf$monthday[seq(1, length(sydf$monthday), 3)]
Thanks,
Steven
-Original Message-
From: nst...@gmail.com
Sent: Tuesday, July 16, 2019 9:39 AM
To: 'Jim Lemon'
Cc: 'r-help mailing list'
Subject: RE: [R] Plotting in R
day, July 12, 2019 6:41 PM
To: nst...@gmail.com
Cc: r-help mailing list
Subject: Re: [R] Plotting in R
Oh, sorry, I think I see what you have tried to do. You want yearly ticks but
month-day labels. These won't mean much unless you also have the year. If you
ask for a date with just the year
= 270
> > ))
> >
> > But the chart didn't show any tick labels.
> > I guess I need to sample sydf$monthday, right? Because that's what I want
> > to show as tick labels. But the problem is that monthday is string, and
> > can't use a value for "by=",
em is that monthday is string, and can't
> use a value for "by=", maybe I need to sample somehow by the index position.
>
> Thanks,
> Steven
>
> -Original Message-
> From: Jim Lemon
> Sent: Thursday, July 11, 2019 10:41 PM
> To: nst...@gmail.com
>
somehow by the index position.
Thanks,
Steven
-Original Message-
From: Jim Lemon
Sent: Thursday, July 11, 2019 10:41 PM
To: nst...@gmail.com
Cc: r-help mailing list
Subject: Re: [R] Plotting in R
Hi Steven,
Neat solution. With a lot more values on the time axis, you will be better of
axis lables, and
> use that for the "ticktext" parameter.
> I thought it must be some variation of the seq(from, to, by= ). Can I use
> that with a list of strings?
>
> Thanks,
> Steven
>
> -Original Message-
> From: Jim Lemon
> Sent: Thursday,
e list of x axis lables, and use
that for the "ticktext" parameter.
I thought it must be some variation of the seq(from, to, by= ). Can I use that
with a list of strings?
Thanks,
Steven
-Original Message-
From: Jim Lemon
Sent: Thursday, July 11, 2019 7:46 PM
To: nst...@gmail.com; r-he
the
> values on the x axis to show 05-01 06-01, etc.
> Is that possible?
>
> Thanks,
> Steven
>
> -Original Message-
> From: R-help On Behalf Of Jim Lemon
> Sent: Sunday, July 7, 2019 2:59 AM
> To: Steven Yen ; r-help mailing list
>
> Subject: Re: [R] Plotting i
t; but this only changes the title of the x axis to "month-day". I want the
> values on the x axis to show 05-01 06-01, etc.
> Is that possible?
>
> Thanks,
> Steven
>
> -Original Message-
> From: R-help On Behalf Of Jim Lemon
> Sent: Sunday, July 7, 2019 2:59 AM
&g
,sydf$rate,type="b",
> xlab="month-day",ylab="Rate")
>
> but this only changes the title of the x axis to "month-day". I want the
> values on the x axis to show 05-01 06-01, etc.
> Is that possible?
>
> Thanks,
> Steven
>
&g
ot_ly?"
-Original Message-
From: nst...@gmail.com
Sent: Thursday, July 11, 2019 11:59 AM
To: 'Jim Lemon' ; 'Steven Yen' ;
'r-help mailing list'
Subject: RE: [R] Plotting in R
Hi Jim,
Thanks for your email.
My question was: how to change the x axis labels without changing the chart.
Or is that no
, etc.
Is that possible?
Thanks,
Steven
-Original Message-
From: R-help On Behalf Of Jim Lemon
Sent: Sunday, July 7, 2019 2:59 AM
To: Steven Yen ; r-help mailing list
Subject: Re: [R] Plotting in R
Hi Steven,
A basic plot can be displayed like this:
sydf<-read.table(text="year
Hi Steven,
A basic plot can be displayed like this:
sydf<-read.table(text="year rate
1993 0.608
1994 0.622
1996 0.623
1998 0.647
2000 0.646
2002 0.625
2004 0.628
2006 0.685
2008 0.679
2010 0.595
2012 0.567
2014 0.599
2016 0.642
2018 0.685",
header=TRUE)
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