A very simple question. With a data frame like this:
n = c(2, 3, 5)
s = c(aa, bb, cc)
df = data.frame(n, s)
I want df$s[1] or df[1,2], but how can I get rid of the extra line in
the output about the factor levels:
df$s[1]
[1] aa
Levels: aa bb cc
Thanks,
Gang
See the max.levels argument in ?print. I think this is what you're looking
for.
--
Robert Tirrell | r...@stanford.edu | (607) 437-6532
Program in Biomedical Informatics | Butte Lab | Stanford University
On Thu, Mar 10, 2011 at 13:35, Gang Chen gangch...@gmail.com wrote:
n = c(2, 3, 5)
s =
Thanks! You mean something like:
print(df$s[1], max.levels=0)
It seems I could also do
as.character(df$s[1])
Any other/better solutions?
On Thu, Mar 10, 2011 at 4:40 PM, Rob Tirrell r...@stanford.edu wrote:
See the max.levels argument in ?print. I think this is what you're looking
for.
try this:
n = c(2, 3, 5)
s = c(aa, bb, cc)
df = data.frame(n, s, stringsAsFactors = FALSE)
df
n s
1 2 aa
2 3 bb
3 5 cc
str(df)
'data.frame': 3 obs. of 2 variables:
$ n: num 2 3 5
$ s: chr aa bb cc
On Thu, Mar 10, 2011 at 4:35 PM, Gang Chen gangch...@gmail.com wrote:
A very
Gang -
It sounds like you want your character variables to
be stored as character values, not factor values. If that's
the case, use
df = data.frame(n, s,stringsAsFactors=FALSE)
If you want them to be factors, but not to display as factors,
others have provided usable solutions.
Yes, indeed I wanted them stored as characters instead of factor
levels. Thanks a lot for the help, Jim and Phil!
Gang
On Thu, Mar 10, 2011 at 5:19 PM, Phil Spector spec...@stat.berkeley.edu wrote:
Gang -
It sounds like you want your character variables to
be stored as character values, not
Dear group,
I am losing my mind with a simple question. Sorry if obvious, but I maybe
start to be confused after days and days of reading documentations.
Df :
df -
structure(list(a = 1:3, b = 4:6, c = structure(c(1L, 1L, 1L), class =
factor, .Label = w)), .Names = c(a,
b, c), row.names =
On Apr 30, 2010, at 9:08 AM, arnaud Gaboury wrote:
Dear group,
I am losing my mind with a simple question. Sorry if obvious, but I
maybe
start to be confused after days and days of reading documentations.
Df :
df -
structure(list(a = 1:3, b = 4:6, c = structure(c(1L, 1L, 1L), class =
df[1:2]-df[1:2]*-1
-
Lanna Jin
lanna...@gmail.com
510-898-8525
--
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Hi:
On Fri, Apr 30, 2010 at 6:08 AM, arnaud Gaboury arnaud.gabo...@gmail.comwrote:
Dear group,
I am losing my mind with a simple question. Sorry if obvious, but I maybe
start to be confused after days and days of reading documentations.
Df :
df -
structure(list(a = 1:3, b = 4:6, c =
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