On 03/26/2013 12:52 PM, Peter Ehlers wrote:
Sooner or later most R beginners are bitten by this all too
convenient shortcut. [I.e. the use of $-extraction] As an R newbie,
think of R as your
bank account: overuse of $-extraction can lead to undesirable
consequences. It's best to acquire
To the OP:
Sooner or later most R beginners are bitten by this all too
convenient shortcut. As an R newbie, think of R as your
bank account: overuse of $-extraction can lead to undesirable
consequences. It's best to acquire the '[[' and '[' habit early.
Peter Ehlers
On 2013-03-25 12:43, Bert G
Hello Starter
Before posting, please read relevant Help files!
?"$"
where it tells you:
"x$name is equivalent to x[["name", exact = FALSE]]. Also, the partial
matching behavior of [[ can be controlled using the exact argument."
..etc.
-- Bert
On Mon, Mar 25, 2013 at 12:21 PM, Andrew Lin wr
If you use the shortcut $ then R will use partial matching to hunt for the
list element you mean.
l$fo will also match.
l[["foo"]]
will not match - the full subsetting construct doesn't use partial matching.
I think the intro to R covers this, and you can also see
?"$"
?"[["
Sarah
On Monday, Ma
Hi Max,
This is known as fuzzy matching. When using `$`, if R can uniquely
match the element name based on what is typed, it returns it. Thus,
in your example, foo uniquely matches foobar, but if you had foobar,
foobox, $foo would not be a unique match.
Cheers,
Josh
On Mon, Mar 25, 2013 at 1
Hi folks,
I am starter for R. While I tried list as following:
> l <- list()
> l$foo
NULL
> l$foobar <- 1
> l$foo
[1] 1
Apparently, foo and foobar are different name for elements in list (actually
foo does not exist). But why they are sharing same value?
Thanks a lot!
Max
[[alternativ
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