Many thanks for all of you for your responses.
Best Regards,
SV
Le mardi 8 mai 2018 à 21:58:37 UTC+2, Daniel Nordlund a
écrit :
On 5/8/2018 12:26 PM, varin sacha via R-help wrote:
>
> Dear R-experts,
>
> Here below the reproducible example. I am trying to get the average of the
On 5/8/2018 12:26 PM, varin sacha via R-help wrote:
Dear R-experts,
Here below the reproducible example. I am trying to get the average of the 100 results
coming from the "lst" function. I have tried lst$mean and mean(lst). It does
not work.
Any help would be highly appreciated >
##
mean(lst) ### See ?mean. A list cannot be an argument of mean.
lst$mean ## nonsense! Don't guess -- read the docs.
Here is an an example:
> z <- list()
> for(i in 1:5) z[i] <- i
> z
[[1]]
[1] 1
[[2]]
[1] 2
[[3]]
[1] 3
[[4]]
[1] 4
[[5]]
[1] 5
> mean(z)
[1] NA
Warning message:
In mean.default(
mean(unlist(lst))
On Tue, May 8, 2018 at 10:26 PM, varin sacha via R-help <
r-help@r-project.org> wrote:
>
> Dear R-experts,
>
> Here below the reproducible example. I am trying to get the average of the
> 100 results coming from the "lst" function. I have tried lst$mean and
> mean(lst). It doe
Dear R-experts,
Here below the reproducible example. I am trying to get the average of the 100
results coming from the "lst" function. I have tried lst$mean and mean(lst). It
does not work.
Any help would be highly appreciated.
## R script for getting MedAe and MedAeSQ
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