I very appreciate for good comments and tip regarding my question. All
postings are excellent to know when I am writing such expression in R.
Thank you so much, and my question is completely resolved from all your
postings.
On Sun, 2012-09-02 at 00:50 +0100, Rui Barradas wrote:
> Em 02-09-2012 00
On 02/09/12 10:52, CHEL HEE LEE wrote:
I have some trouble to deal the value of 'NaN'. For example,
exp(1e3)
[1] Inf
exp(1e3)*0
[1] NaN
The correct answer should be 0 rather than NaN. I will very appreciate
if anyone can share some technique to get a correct answer.
There is no techniqu
Em 02-09-2012 00:10, Jeff Newmiller escreveu:
I disagree that this answer is "wrong". If you want a mathematically correct
answer you are going to have to obtain it by applying intelligence to the algorithm in
which this calculation occurred.
Logarithms are the product of intelligence.
And t
I disagree that this answer is "wrong". If you want a mathematically correct
answer you are going to have to obtain it by applying intelligence to the
algorithm in which this calculation occurred. This is not a mailing list about
numerical methods in general, so it probably isn't appropriate to
I have some trouble to deal the value of 'NaN'. For example,
> exp(1e3)
[1] Inf
> exp(1e3)*0
[1] NaN
The correct answer should be 0 rather than NaN. I will very appreciate
if anyone can share some technique to get a correct answer.
__
R-help@r-proje
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