mat <- outer( 0:9, 0:(1024-1), function(x,y) y %/% (2^x) %% 2 )
On Thu, 26 Jun 2008, Daniel Folkinshteyn wrote:
this is probably a cludge, and there may be a "neater" way to do this, but...
here's one:
a = 0:1
for (i in 1:9){ a= merge(unname(a), 0:1) }
a = t(a)
after the for loop, 'a'
Try this also:
t(expand.grid(rep(list(0:1), 10)))
On Thu, Jun 26, 2008 at 3:18 PM, SARAH A DEPAOLI <[EMAIL PROTECTED]> wrote:
> I am looking for a way to generate a data matrix that contains all possible
> response patterns for 10 binary items. This should produce a matrix with 10
> rows (repre
this is probably a cludge, and there may be a "neater" way to do this,
but... here's one:
> a = 0:1
> for (i in 1:9){ a= merge(unname(a), 0:1) }
> a = t(a)
after the for loop, 'a' will contain a 1024 row by 10 col dataframe.
putting it through a transpose, gives you the 10 rows by 1024 cols ma
I am looking for a way to generate a data matrix that contains all possible
response patterns for 10 binary items. This should produce a matrix with 10
rows (representing 10 items) and 1024 columns (representing 2^10 possible
response patterns). Does anyone know of code that would produce such a
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