On Mar 25, 2015, at 8:45 AM, David Winsemius wrote:
>
> On Mar 25, 2015, at 4:55 AM,
> wrote:
>
>> Dear all,
>>
>> Finally I have tried three different options to integrate a function in a 3D
>> volume. Here
>> I show a test example. The volume is the box [0,100] x [0,100] x [0,100] and
On Mar 25, 2015, at 4:55 AM, wrote:
> Dear all,
>
> Finally I have tried three different options to integrate a function in a 3D
> volume. Here
> I show a test example. The volume is the box [0,100] x [0,100] x [0,100] and
> the
> function is
>
> nfw(d) = 4/((d/5)*(1+(d/5))^2)
>
> where
On 25/03/2015 7:55 AM, lluis.hurt...@uv.es wrote:
> Dear all,
>
> Finally I have tried three different options to integrate a function in a 3D
> volume. Here
> I show a test example. The volume is the box [0,100] x [0,100] x [0,100] and
> the
> function is
>
> nfw(d) = 4/((d/5)*(1+(d/5))^2)
>
Dear all,
Finally I have tried three different options to integrate a function in a 3D
volume. Here
I show a test example. The volume is the box [0,100] x [0,100] x [0,100] and
the
function is
nfw(d) = 4/((d/5)*(1+(d/5))^2)
where d is the distance between each point in the box to the point (
On Mar 23, 2015, at 3:44 AM, wrote:
> Dear all,
>
> I am currently working with the spatstat package with 3D samples. I am trying
> to
> evaluate a non analytical function over the window that encloses the sample
> and I
> need to know which is the fastest way of doing it.
>
> The functio
On 23/03/15 23:44, lluis.hurt...@uv.es wrote:
Dear all,
I am currently working with the spatstat package with 3D samples. I am trying to
evaluate a non analytical function over the window that encloses the sample and
I
need to know which is the fastest way of doing it.
I gather that you mea
Dear all,
I am currently working with the spatstat package with 3D samples. I am trying
to
evaluate a non analytical function over the window that encloses the sample and
I
need to know which is the fastest way of doing it.
The function input is a 3 coordinate position in the window (x,y,z) a
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