Thanks a lot!
On Wed, Nov 21, 2012 at 12:51 PM, Rui Barradas wrote:
> Hello,
>
> You're complicating what is simple:
>
>
> prop3$effort[which.max(prop3$**Low)] # First maximum of Low
> prop3$effort[which.max(prop3$**High)] # Ditto, of High
>
> which.max(prop3$Low) # Row number that maximizes
On Wed, Nov 21, 2012 at 9:51 AM, Rui Barradas wrote:
> Hello,
>
> You're complicating what is simple:
Fortune?
(Well, it's a profound truism that we all should live by -- but I
leave it to others to judge whether it meets Fortunes criteria).
-- Bert
>
>
> prop3$effort[which.max(prop3$Low)] # F
Hello,
You're complicating what is simple:
prop3$effort[which.max(prop3$Low)] # First maximum of Low
prop3$effort[which.max(prop3$High)] # Ditto, of High
which.max(prop3$Low) # Row number that maximizes Low
which.max(prop3$High) # Row number that maximizes High
Hope this helps,
Rui Barr
My data looks like this:
X Y1(X) Y2(X)
i want to find the values of x that maximize Y1 and Y2.
Right now I'm getting the answer but I would like to know if there is a
more efficient/elegant way of doing this.
This code reproduces what I'm doing:
[code]
prop3<-structure(list(effort = c(0, 0.00898
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