On Feb 20, 2012, at 1:45 AM, johnmark wrote:
MIchael -
Thanks for your insight. I think I see where you're going with this.
To make '==' comparisons for subsetting against an ordered factor,
I've had
to create a lookup table for all possible values I'd ever want to
compare
against (all d
MIchael -
Thanks for your insight. I think I see where you're going with this.
To make '==' comparisons for subsetting against an ordered factor, I've had
to create a lookup table for all possible values I'd ever want to compare
against (all dates covered by the quarters in question, in this c
It's not a matter of unordered & ordered factors, but ordered factors
and Dates (as the warning says)
I can see at least one ambiguity -- should comparison be made from the
level or the internal code -- so the warning makes sense to me (though
an error might make even more sense). Generally, for f
This error occurs because the "==" comparison operator doesn't allow
comparison of ordered and normal factors:
/df[df5$close_quarter == as.Date("2011-02-01"),]/
Warning message:
In /`[.data.frame`(df, df$close_quarter == as.Date("2011-02-01")/, :
Incompatible methods ("Ops.ordered", "Ops.Date"
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