ge -
> From: "Ivan Krylov"
> To: "Thomas Subia via R-help"
> Cc: "Thomas Subia"
> Sent: Sunday, 22 March, 2020 07:24:15
> Subject: Re: [R] Grouping Question
> On Sat, 21 Mar 2020 20:01:30 -0700
> Thomas Subia via R-help wrote:
>
>> Ser
On Sat, 21 Mar 2020 20:01:30 -0700
Thomas Subia via R-help wrote:
> Serial_test is a pass, when all of the Meas_test are pass for a given
> serial. Else Serial_test is a fail.
Use by/tapply in base R or dplyr::group_by if you prefer tidyverse
packages.
--
Best regards,
Ivan
__
Colleagues,
Here is my dataset.
Serial Measurement Meas_test Serial_test
1 17 failfail
1 16 passfail
2 12 passpass
2 8 passpass
2 10 pass
Hello Jorge,
Thank you for the reply. I tried a few different things with if/else but
couldn't get them to go. I really appreciate your feedback. I learned
something new from this
Will
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Se
Hello Jim
Wow. I tried cut but i see you have an interim step with labels a,b,c but
levels night and day. i was really close to this. i have labels
night,day,night and it wouldn't let me duplicate labels. I am very greatful
for your input
Will
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Hi Will,
One way would be:
> x
[1] 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23
24
> factor(ifelse(x>6 & x<18, 'day', 'night'))
[1] night night night night night night night day day day day day
day day day
[16] day day day night night night night nig
try this:
> x
[1] 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
> y <- cut(x, breaks=c(-Inf,6,18, Inf), labels=c('a','b','c'))
> levels(y) <- c('night','day','night')
> y
[1] night night night night night night night day day day day
day day day day day
Hello
I have what is probably a very simple grouping question however, given my
limited exposure to R, I have not found a solution yet despite my research
efforts and wild attempts at what I thought "might" produce some sort of
result.
I have a very simple list of integers that range between 1 a
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