Thanks, but why does f[f=4] yield 16 instead of 4?
f
[1] -24 -8 16 -32 64 -128
f[f0]
[1] -2 -8 -32 -128
f[f0]
[1] 4 16 64
f[f=4]
[1] 16
2013/5/8 Jorge I Velez jorgeivanve...@gmail.com
f [ f 0 ]
On Wed, May 8, 2013 at 11:54 AM, jpm miao miao...@gmail.com wrote:
Sorry. I just got it
f[f==4]
[1] 4
2013/5/8 jpm miao miao...@gmail.com
Thanks, but why does f[f=4] yield 16 instead of 4?
f
[1] -24 -8 16 -32 64 -128
f[f0]
[1] -2 -8 -32 -128
f[f0]
[1] 4 16 64
f[f=4]
[1] 16
2013/5/8 Jorge I Velez
Check
?==
and try
f[f == 4]
More in section 2.4 at http://cran.r-project.org/doc/manuals/R-intro.pdf
On Wed, May 8, 2013 at 5:14 PM, jpm miao miao...@gmail.com wrote:
Thanks, but why does f[f=4] yield 16 instead of 4?
f
[1] -24 -8 16 -32 64 -128
f[f0]
[1] -2 -8
Hi,
I have a vector f with some negative columns. I remember that there is
an easy expression that can find out negative items. Can someone tell me
how I can do it?
It seems to be
f[i such that f[i]0 ...]
Thanks,
Miao
d-1:7
f-(-2)^d
f
[1] -24 -8 16 -32 64 -128
Hi,
The solution can be easily found on Internet.
By the way, the following does what you are looking for:
f[f0]
Regards,
Pascal
On 05/08/2013 10:54 AM, jpm miao wrote:
Hi,
I have a vector f with some negative columns. I remember that there is
an easy expression that can find out
f [ f 0 ]
On Wed, May 8, 2013 at 11:54 AM, jpm miao miao...@gmail.com wrote:
Hi,
I have a vector f with some negative columns. I remember that there is
an easy expression that can find out negative items. Can someone tell me
how I can do it?
It seems to be
f[i such that f[i]0
6 matches
Mail list logo