Great help. It works when the first and the second columns are ordered the
same way. But aggregate does not work for the following case:
z=c('ab','ah','bc','ah','dv')
x=substr(z,start=1,stop=1)
y=substr(z,start=2,stop=2)
v1=5:9
v2=7:11
data=data.frame(x,y,z,v1,v2)
data
x y z v1 v2
1 a b ab 5
You can do this in reshape package as mentioned earlier.
However, if you need a solution with aggregate here it is
a - with(data, aggregate(cbind(v1,v2), by=list(x,y,z),sum))
names (a) - c(x,y,z,v1,v2)
Nikhil Kaza
Asst. Professor,
City and Regional Planning
University of North Carolina
Hi, folks,
Please let me address the problem by the following codes:
first=c('u','b','e','k','j','c','u','f','c','e')
second=c('usa','Brazil','England','Korea','Japan','China','usa','France','China','England')
third=1:10
data=data.frame(first,second,third)
## You may understand values in the
aggregate(data$third, by=list(data$first), sum)
or
reqiure(reshape)
cast(melt(data), ~first, sum)
On Jun 28, 2010, at 9:30 PM, Yi wrote:
first=c('u','b','e','k','j','c','u','f','c','e')
second
=
c
('usa
','Brazil
','England','Korea','Japan','China','usa','France','China','England')
On Jun 28, 2010, at 9:30 PM, Yi wrote:
Hi, folks,
Please let me address the problem by the following codes:
first=c('u','b','e','k','j','c','u','f','c','e')
second
=
c
('usa
','Brazil
','England','Korea','Japan','China','usa','France','China','England')
third=1:10
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