Re: [R] How to extract "specific"/"last" intercept value from segmented package.

Hello, I'm glad that it helped. Note, however, that you don't need inter.m <- as.matrix(...) because inter$x already is a matrix. You can simply do inter.row <- nrow(inter$x) answer <- inter$x[inter.row,1] Rui Barradas   Citando Narendra Modi : > Thanks! that worked.

Re: [R] How to extract "specific"/"last" intercept value from segmented package.

Thanks! that worked. I also tested with the below method although your solution is faster and done in fewer steps. inter <- intercept(segmented.mod) inter.m <- as.matrix(inter$x) inter.row <- nrow(inter.m) answer <- inter.m[inter.row,1] PD On Tue, Jul 5, 2016 at 2:28 PM,

Re: [R] How to extract "specific"/"last" intercept value from segmented package.

nter[[1]], 1)) [1] -86.77 - David L. Carlson Department of Anthropology Texas A University -Original Message- From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Narendra Modi Sent: Tuesday, July 5, 2016 1:42 PM To: R-help@r-project.org Subject: [R]

Re: [R] How to extract "specific"/"last" intercept value from segmented package.

Hello, Try dimnames(inter$x)[[1]] You could have seen this by inspecting 'inter': str(inter) Hope this helps, Rui Barradas   Citando Narendra Modi : > I am able to perform regression on a dataset as below: > > plot(x,y) > lin.mod <- lm(y~x) > m <- mean(x) > m > >

[R] How to extract "specific"/"last" intercept value from segmented package.

I am able to perform regression on a dataset as below: plot(x,y) lin.mod <- lm(y~x) m <- mean(x) m segmented.mod <- segmented(lin.mod, seg.Z = ~x, psi= m) plot(segmented.mod, add=T) sl <- slope(segmented.mod) inter <- intercept(segmented.mod) summary(segmented.mod)# Show Summary sl