Try this:
dir()[file.info(dir())$isdir]
On Tue, Jun 1, 2010 at 11:06 PM, Nevil Amos wrote:
> How do I get a list of subdirectories only, not files, in a directory
>
>
> dir.create("test")
> setwd("test")
> dir.create("adir")
> dir.create("bdir")
> file.create("afile")
> dir()
>
> returns [1] "
How do I get a list of subdirectories only, not files, in a directory
dir.create("test")
setwd("test")
dir.create("adir")
dir.create("bdir")
file.create("afile")
dir()
returns [1] "adir" "afile" "bdir"
in need to return [1] "adir" "bdir"
cheers
Nevil Amos
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