On Jan 6, 2015, at 3:29 PM, Monnand monn...@gmail.com wrote:
Thank you, all! Your replies are very useful, especially Don's explanation!
One complaint I have is: the function name (talbe) is really not very
informative.
Why not? You used the word 'table' in your original post, except as
Thank you, all! Your replies are very useful, especially Don's explanation!
One complaint I have is: the function name (talbe) is really not very
informative.
On Sun Jan 04 2015 at 5:03:47 PM MacQueen, Don macque...@llnl.gov wrote:
This seems to me to be a case where thinking in terms of
Dear Monnad,
one possible way would be to use as.factor() and in the summary you would get
counts for every level.
Like this:
x = c(1, 1, 2, 1, 5, 2)
summary(as.factor(x))
Cheers, Christian
Hi all,
I thought this was a very naive problem but I have not found any solution
which is
Hi all,
I thought this was a very naive problem but I have not found any solution
which is idiomatic to R.
The problem is like this:
Assuming we have vector of strings:
x = c(1, 1, 2, 1, 5, 2)
We want to count number of appearance of each string. i.e. in vector x,
string 1 appears 3 times; 2
On 04-01-2015, at 10:02, Monnand monn...@gmail.com wrote:
Hi all,
I thought this was a very naive problem but I have not found any solution
which is idiomatic to R.
The problem is like this:
Assuming we have vector of strings:
x = c(1, 1, 2, 1, 5, 2)
We want to count number of
This seems to me to be a case where thinking in terms of computer
programming concepts is getting in the way a bit. Approach it as a data
analysis task; the S language (upon which R is based) is designed in part
for data analysis so there is a function that does most of the job for you.
(I
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