Dear Wu,
Thank you indeed very much for your response. Is it possible that I
use this method to compare the distribution of original population
that this observations come from?
Thank you ideed very much.
On 3/28/12, alan wu [via R] ml-node+s789695n4511310...@n4.nabble.com wrote:
try
Dear all,
Novice in statistics.
I have 2 experimental conditions. Each condition has ~400 points as its
response. Each condition is done in 4 repereats (so I have 2 x 400 x 4
points).
I want to compare the means of two conditions and test whether they are same
or not. Which test should I use?
You should use mixed effects modeling to analyze data of this sort.
This is not a topic that has generally been covered by introductory
classes, so you should consult with a professional statistician on
your problem, or educate yourself well beyond the novice level (this
takes more than just
try anova if they have same observe points.
conditions-rep(c(1,2),each=1600)
response-sample (1:20,1600*2, replace= TRUE)
points-rep(rep(1:400, each=4),2)
replicates-rep(1:4,800)
obs-data.frame(response,conditions,points,replicates)
fit - lm(response~conditions+points,data=obs)
anova(fit)
On
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