George Coyle wrote:
Hi All,
I am trying to turn a Matrix into a vector for analysis purposes. I need to
select only certain columns from the entire matrix for the vector (intraday
time intervals). Also I need to transpose the Matrix (so times are in rows)
stack each successive new column on
How about:
?subset
?t
?as.vector
I'm not sure transposing is really needed, but without a workable example
as requested in the posting guide (hint, hint), it's hard to say for certain.
Sarah
On Tue, Jun 15, 2010 at 1:51 PM, George Coyle wrote:
> Hi All,
>
> I am trying to turn a Matrix into a v
Hi All,
I am trying to turn a Matrix into a vector for analysis purposes. I need to
select only certain columns from the entire matrix for the vector (intraday
time intervals). Also I need to transpose the Matrix (so times are in rows)
stack each successive new column on top of each other (lates
:
>
> > From: steven mosher
> > Subject: Re: [R] Matrix to Vector
> > To: "Henrique Dallazuanna"
> > Cc: r-help@r-project.org
> > Received: Saturday, June 5, 2010, 2:44 PM
> > as.vector(t(m))
> > [1] 1 9 17 25 33 41 2 10 18 26 34
> > 42
m<-matrix(seq(1,48),nrow=6,byrow=T)
as.vector(t(m))
gives me the correct result.
Any chance you may have already transformed m ?
--- On Sat, 6/5/10, steven mosher wrote:
> From: steven mosher
> Subject: Re: [R] Matrix to Vector
> To: "Henrique Dallazuanna"
>
as.vector(t(m))
[1] 1 9 17 25 33 41 2 10 18 26 34 42 3 11 19 27 35 43 4 12 20 28 36 44
5 13 21 29 37 45 6 14 22 30 38 46 7 15 23 31 39 47 8 16 24
[46] 32 40 48
the result I want is this:
[1] 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24
25 26 27 28 29 30 31 32
Hi Steven,
If I understood correctly, this might do what you want:
c(t(m))
HTH,
Jorge
On Sat, Jun 5, 2010 at 2:12 PM, steven mosher wrote:
> Given a matrix of m*n, I want to reorder it as a vector, using a row major
> transpose.
>
> so:
>
> > m<-matrix(seq(1,48),nrow=6,byrow=T)
> > m
> [,
Try this:
as.vector(t(m))
On Sat, Jun 5, 2010 at 3:12 PM, steven mosher wrote:
> Given a matrix of m*n, I want to reorder it as a vector, using a row major
> transpose.
>
> so:
>
> > m<-matrix(seq(1,48),nrow=6,byrow=T)
> > m
> [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
> [1,]123
Given a matrix of m*n, I want to reorder it as a vector, using a row major
transpose.
so:
> m<-matrix(seq(1,48),nrow=6,byrow=T)
> m
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8]
[1,]12345678
[2,]9 10 11 12 13 14 15 16
[3,] 17 18 19 20 21
Not sure it is really "matrix to vector" but here are a few of attempts:
> abM<-matrix(1:9, nrow=3)
> rownames(abM) <- letters[1:3]
> colnames(abM) <- letters[4:6]
> data.frame( cols=colnames(abM)[col(abM)[1:9]], rows= rownames(abM)
[row(abM)[1:9]], vals=abM[1:9])
cols rows vals
1da
Ian Coe wrote:
Hi,
Is there a way to convert a matrix into a vector representing all
permutations of values and column/row headings with native R functions?
I did this with 2 nested for loops and it took about 25 minutes to run
on a ~700x700 matrix. I'm assuming there must be a smarter way
Hi,
Is there a way to convert a matrix into a vector representing all
permutations of values and column/row headings with native R functions?
I did this with 2 nested for loops and it took about 25 minutes to run
on a ~700x700 matrix. I'm assuming there must be a smarter way to do
this with
Hi,
Is there a way to convert a matrix into a vector representing all
permutations of values and column/row headings with native R functions?
I did this with 2 nested for loops and it took about 25 minutes to run
on a ~700x700 matrix. I'm assuming there must be a smarter way to do
this with
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