Rolf,
I hear you.
But, after reflection, ie I looked at my situation again, it is great :-)-O
el
Sent from Dr Lisse's iPad mini
> On Jun 30, 2014, at 0:48, Rolf Turner wrote:
>
>
>> On 30/06/14 10:32, Dr Eberhard W Lisse wrote:
>>
>> Thanks,
>>
>> I then set NA to 0, and can do the sutr
Thank you very much.
el
On 2014-06-30, 00:48 , Rolf Turner wrote:
>
> On 30/06/14 10:32, Dr Eberhard W Lisse wrote:
>
>> Thanks,
>>
>> I then set NA to 0, and can do the sutraction,
>>
>> great.
>
> Not so great. I haven't gone through the issues underlying this post,
> but replacing NA by 0
On 30/06/14 10:32, Dr Eberhard W Lisse wrote:
Thanks,
I then set NA to 0, and can do the sutraction,
great.
Not so great. I haven't gone through the issues underlying this post,
but replacing NA by 0 will almost surely yield nonsense. "Missing" is
***not*** the same thing as "zero". Pr
Thanks,
I then set NA to 0, and can do the sutraction,
great.
el
On 2014-06-29, 22:32 , Michael Peng wrote:
> you can get a new data frame by
> merge(qpiso, qplegit, all.x = TRUE, all.y = TRUE, by = "iso" )
> Take the subtraction on the new data frame.
>
>
>
>
> 2014-06-29 11:24 GMT-05:00
you can get a new data frame by
merge(qpiso, qplegit, all.x = TRUE, all.y = TRUE, by = "iso" )
Take the subtraction on the new data frame.
2014-06-29 11:24 GMT-05:00 Dr Eberhard Lisse :
> I have two data frames like so
>
> > qpiso
> iso requests
> 1A1 20
> 2A2 199
> 3
If you really prefer solution code, then provide reproducible example code as
the footer requests.
Use ?merge with the all.x=TRUE parameter, and then perform your calculations on
the resulting combined data frame, using ?ifelse and ?is.na as needed.
--
I have two data frames like so
> qpiso
iso requests
1A1 20
2A2 199
3AD5
4AE 176
...
189 ZW 82
> qplegit
iso requests
1A2 36
2AE4
3AM2
4AO1
...
100 ZW3
I want to create another dataframe
on 02/26/2009 11:52 AM Vadlamani, Subrahmanyam {FLNA} wrote:
> Hi:
> I am a new R user. I have the following question and would appreciate your
> input
>
> Data1 (data frame 1)
> p1,d1,d2 (p1 is text and d1 and d2 are numeric)
> xyz,10,25
>
> Data2 (data frame 2)
> p1,d1,d2
> xyz,11,15
>
> Now
Hi there,
something like this?
Data1<-read.table(stdin(), head=T, sep=",")
p1,d1,d2
xyz,10,25
kmz,100,250
Data2<-read.table(stdin(), head=T, sep=",")
p1,d1,d2
xyz,11,15
kmz,110,150
Data1
Data2
Data3<-data.frame(rbind(Data1,Data2))
Data3
Data3.sum<-aggregate(Data3[,c("d1","d2")], list(Data3$p1)
Hi:
I am a new R user. I have the following question and would appreciate your input
Data1 (data frame 1)
p1,d1,d2 (p1 is text and d1 and d2 are numeric)
xyz,10,25
Data2 (data frame 2)
p1,d1,d2
xyz,11,15
Now I want to create a new data frame that looks like so below. The fields d1
and s2 are su
10 matches
Mail list logo