Here is the structure
str(all_differ)
num [1:6280, 1:8] 2.22e-16 2.22e-16 2.22e-16 2.22e-16 2.22e-16 ...
- attr(*, dimnames)=List of 2
..$ : NULL
..$ : chr [1:8] rawp Bonferroni Holm Hochberg ...
I tried, but it still giving me the same error message Incorrect Dimension
You have a 'matrix' not a 'list', so
I think you want something like this:
all_differ[all_differ[, 'BY'] = 0.01, 'BY'], this will return the
values where column is 'BY' in all rows which is less or equal to
0.01.
On 02/03/2008, Keizer_71 [EMAIL PROTECTED] wrote:
Here is the structure
This is exactly what i am looking for.
many thanks
Chris
On 3/2/08, Henrique Dallazuanna [EMAIL PROTECTED] wrote:
You have a 'matrix' not a 'list', so
I think you want something like this:
all_differ[all_differ[, 'BY'] = 0.01, 'BY'], this will return the
values where column is 'BY' in all
dim(data.sub)
[1] 1 140
#extracting all differentially express genes##
library(multtest)
two_side- (1-pt(abs(data.sub),50))*2
diff- mt.rawp2adjp(two_side)
all_differ-diff[[1]][37211:1,]
all_differ
#list of differentially expressed genes##
probe.names-
+
It would be helpful if you provided commented, minimal,
self-contained, reproducible code.
What does str(all_differ) say? That will tell you the structure of
the object that you are trying to work with.
On Sat, Mar 1, 2008 at 3:35 AM, Keizer_71 [EMAIL PROTECTED] wrote:
dim(data.sub)
[1]
5 matches
Mail list logo