Hi,
I would like to have an index for a column in a matrix encoded in a
cell of the same matrix.
For example:
x = matrix(c(11,12,13,1,
21,22,23,3,
31,32,33,2),byrow=T,ncol=4)
In this case, column 4 is the index. I then access the column
specified in the index by:
for (i in 1:3)
diag(x[,x[,4]])
[1] 11 23 32
diag(x[,x[,4]]) - diag(x[,x[,4]])+5
x
[,1] [,2] [,3] [,4]
[1,] 16 12 131
[2,] 21 22 283
[3,] 31 37 332
Cheers
Joris
On Fri, Jun 18, 2010 at 8:58 PM, Iuri Gavronski i...@ufrgs.br wrote:
Hi,
I would like to have an index for a
On second thought, the addition only works in the case of a square matrix :
x = matrix(c(11,12,13,1,
21,22,23,3,
31,32,33,2,
41,42,43,1,
51,52,53,3),byrow=T,ncol=4)
diag(x[,x[,4]])
[1] 11 23 32 41 53
works, but
diag(x[,x[,4]]) - diag(x[,x[,4]])+5
x
[,1] [,2] [,3] [,4]
[1,] 11 12
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Joris Meys
Sent: Friday, June 18, 2010 5:08 PM
To: Iuri Gavronski
Cc: r-help
Subject: Re: [R] Non-procedural access to columns of a matrix
diag(x[,x[,4]])
[1] 11 23 32
diag(x[,x
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