Thank you, Michael.
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>>> "R. Michael Weylandt" 2011/12/07 09:27:38 PM
>>> >>>
" I'm not creating a sector'
Exactly, but your code
You should probably read some of the intro to R
documents, as this is a critical component of using
R.
On Wed, Dec 7, 2011 at 7:06 AM, John Visagie wrote:
> Dear All,
>
> I am having a very basic error, but somehow do not know how to resolve it.
> I've read a dataset in .csv into R with two col
" I'm not creating a sector'
Exactly, but your code (sector$exports) tells R to "find a variable
called sector and then look inside of it for something called
exports". It never bothers with the second part because it can't
execute the first because it can't find anything called sector (as the
err
On 07.12.2011 13:06, John Visagie wrote:
Dear All,
I am having a very basic error, but somehow do not know how to resolve it. I've read a
dataset in .csv into R with two columns - sector, export. When trying to plot the data
it says "sector not found" This is the formula.
SouthAfrica<-
You never create a "sector" object inR so it can't be found. Perhaps you meant
hist(SouthAfrica$exports)
Michael
On Dec 7, 2011, at 7:06 AM, "John Visagie" wrote:
> Dear All,
>
> I am having a very basic error, but somehow do not know how to resolve it.
> I've read a dataset in .csv into
Dear All,
I am having a very basic error, but somehow do not know how to resolve it.
I've read a dataset in .csv into R with two columns - sector, export. When
trying to plot the data it says "sector not found" This is the formula.
SouthAfrica<-read.csv(c,header=T)
> hist(sector$exports,
On 9/02/2010, at 12:51 PM, Daniel Malter wrote:
> The for loop tries to write into an object that does not yet exist. Do
> month.observed=NULL prior to the loop.
Bad advice. As Duncan Murdoch just pointed out, this is inefficient.
Compare:
> x <- NULL
> system.time(for(i in 1:5) x[i] <- 42
-project.org] On
Behalf Of emorway
Sent: Monday, February 08, 2010 6:38 PM
To: r-help@r-project.org
Subject: [R] object 'xxx' not found
The following line of code seems fairly straight forward, yet it is kicking
back an error message:
for (i in
1:length(mean.natveg.frac)){month.observed[i]=as.num
emorway wrote:
The following line of code seems fairly straight forward, yet it is kicking
back an error message:
for (i in
1:length(mean.natveg.frac)){month.observed[i]=as.numeric(names(mean.natveg.frac[i]))%%12}
Error message:
Error in month.observed[i] = as numeric(names(mean.natveg.frac[i])
The following line of code seems fairly straight forward, yet it is kicking
back an error message:
for (i in
1:length(mean.natveg.frac)){month.observed[i]=as.numeric(names(mean.natveg.frac[i]))%%12}
Error message:
Error in month.observed[i] = as numeric(names(mean.natveg.frac[i]))%%12 :
object '
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