Re: [R] Pearson chi-square test

2011-09-27 Thread Meyners, Michael
elp@r-project.org Cc: Meyners, Michael Subject: RE: [R] Pearson chi-square test Dear Michael,   Thanks very much for your answers!   The purpose of my analysis is to test whether the contingency table x is different from the contingency table y. Or, to put it differently, whether there is a significant diffe

Re: [R] Pearson chi-square test

2011-09-27 Thread Michael Haenlein
ember 2011 17:00 To: Michael Haenlein; r-help@r-project.org Subject: RE: [R] Pearson chi-square test Just for completeness: the manual calculation you'd want is most likely sum((x-y)^2 / (x+y)) (that's one you can find on the Wikipedia link you provided). To get the same from ch

Re: [R] Pearson chi-square test

2011-09-27 Thread Meyners, Michael
n Behalf Of Meyners, Michael > Sent: Tuesday, September 27, 2011 13:28 > To: Michael Haenlein; r-help@r-project.org > Subject: Re: [R] Pearson chi-square test > > Not sure what you want to test here with two matrices, but reading the > manual helps here as well: > > y a vector;

Re: [R] Pearson chi-square test

2011-09-27 Thread Meyners, Michael
aenlein > Sent: Tuesday, September 27, 2011 12:45 > To: r-help@r-project.org > Subject: [R] Pearson chi-square test > > Dear all, > > I have some trouble understanding the chisq.test function. > Take the following example: > > set.seed(1) > A <- cut(runif(100)

[R] Pearson chi-square test

2011-09-27 Thread Michael Haenlein
Dear all, I have some trouble understanding the chisq.test function. Take the following example: set.seed(1) A <- cut(runif(100),c(0.0, 0.35, 0.50, 0.65, 1.00), labels=FALSE) B <- cut(runif(100),c(0.0, 0.25, 0.40, 0.75, 1.00), labels=FALSE) C <- cut(runif(100),c(0.0, 0.25, 0.50, 0.80, 1.00), labe