Às 15:36 de 11/08/2024, Steven Yen escreveu:
Thanks. Will try it.
Have not tried it but I think the following may work:
out$results<-NULL
out$results$ei<-ap
out$results$vi<-vap
All I need is printing by returning out (unless I turn it off). And,
retrieve ap and vap as needed as shown above.
Just for reference, R's "preferred" way to handle printing is to
create "classed" objects from a function that produces all the
necessary information and have an appropriate "print" method, i.e.
function, for that class to print it. R has several class object
systems that can do this, including the
В Sun, 11 Aug 2024 22:36:08 +0800
Steven Yen пишет:
> All I need is printing by returning out (unless I turn it off). And,
> retrieve ap and vap as needed as shown above. Guess I need to read
> more about invisible.
Perhaps you could print(out) instead of returning it in the if
(printing) branc
Thanks. Will try it.
Have not tried it but I think the following may work:
out$results<-NULL
out$results$ei<-ap
out$results$vi<-vap
All I need is printing by returning out (unless I turn it off). And,
retrieve ap and vap as needed as shown above. Guess I need to read more
about invisible.
Às 09:51 de 11/08/2024, Steven Yen escreveu:
Hi
In the following codes, I had to choose between printing (= TRUE) or
deliver something for grab (ei, vi). Is there a way to get both--that
is, to print and also have ei and vi for grab? Thanks.
Steven
...
out<-round(as.data.frame(cbind(ap,se,
Hi
In the following codes, I had to choose between printing (= TRUE) or
deliver something for grab (ei, vi). Is there a way to get both--that
is, to print and also have ei and vi for grab? Thanks.
Steven
...
out<-round(as.data.frame(cbind(ap,se,t,p)),digits)
out<-cbind(out,sig)
out<-out[!gr
Read ?print.data.frame. There is an argument for that.
On March 27, 2023 10:05:10 AM PDT, Dennis Fisher wrote:
>R 4.2.3
>OS X
>
>Colleagues,
>
>I am printing a large number of tables using the print command. A simple
>example is:
> print(data.frame(COL1=1:5, COL2=10:6))
>
>The result in t
Try:
print(data.frame(COL1=1:5, COL2=10:6), row.names=FALSE)
-Original Message-
From: R-help On Behalf Of Dennis Fisher
Sent: Monday, March 27, 2023 1:05 PM
To: r-help@r-project.org
Subject: [R] printing a data.frame without row numbers
R 4.2.3
OS X
Colleagues,
I am printing a
print(data.frame(COL1=1:5, COL2=10:6), row.names=FALSE)
On 27/03/2023 1:05 p.m., Dennis Fisher wrote:
R 4.2.3
OS X
Colleagues,
I am printing a large number of tables using the print command. A simple
example is:
print(data.frame(COL1=1:5, COL2=10:6))
The result in this case is:
R 4.2.3
OS X
Colleagues,
I am printing a large number of tables using the print command. A simple
example is:
print(data.frame(COL1=1:5, COL2=10:6))
The result in this case is:
COL1 COL2
11 10
229
338
447
556
I would like to print the table WITH
Às 10:15 de 16/01/2023, Martin Maechler escreveu:
Rui Barradas
on Mon, 16 Jan 2023 08:46:43 + writes:
> Às 08:31 de 16/01/2023, Jeff Newmiller escreveu:
>> Use the Cairo PDF device?
>>
>> On January 16, 2023 12:18:48 AM PST, Dennis Fisher
>> wrote:
>>> R
> Rui Barradas
> on Mon, 16 Jan 2023 08:46:43 + writes:
> Às 08:31 de 16/01/2023, Jeff Newmiller escreveu:
>> Use the Cairo PDF device?
>>
>> On January 16, 2023 12:18:48 AM PST, Dennis Fisher
>> wrote:
>>> R 4.2.2 OS X
>>>
>>> Colleagues
>>>
-project.org
> Subject: [R] Printing special characters
>
> R 4.2.2
> OS X
>
> Colleagues
>
> A file that I have read includes strings like this:
> "EVENT ≥ 30 sec"
> When I include the string in a graphic using:
> mtext(STRING, …)
>
Às 08:31 de 16/01/2023, Jeff Newmiller escreveu:
Use the Cairo PDF device?
On January 16, 2023 12:18:48 AM PST, Dennis Fisher wrote:
R 4.2.2
OS X
Colleagues
A file that I have read includes strings like this:
"EVENT ≥ 30 sec"
When I include the string in a graphic using:
mtex
How about just 'EVENT > 30 sec' or 'EVENT > 29 sec' ?
On Mon, Jan 16, 2023 at 10:19 AM Dennis Fisher wrote:
> R 4.2.2
> OS X
>
> Colleagues
>
> A file that I have read includes strings like this:
> "EVENT ≥ 30 sec"
> When I include the string in a graphic using:
> mtext(STRING,
Use the Cairo PDF device?
On January 16, 2023 12:18:48 AM PST, Dennis Fisher wrote:
>R 4.2.2
>OS X
>
>Colleagues
>
>A file that I have read includes strings like this:
> "EVENT ≥ 30 sec"
>When I include the string in a graphic using:
> mtext(STRING, …)
>it appears as:
> "EVENT .
R 4.2.2
OS X
Colleagues
A file that I have read includes strings like this:
"EVENT ≥ 30 sec"
When I include the string in a graphic using:
mtext(STRING, …)
it appears as:
"EVENT ... 30 sec"
Is there a simple work-around (short of reformatting all the strings, then
using
Dear Rui,
Many thanks...
Yours
Akshay M Kulkarni
From: Rui Barradas
Sent: Sunday, July 10, 2022 12:39 AM
To: akshay kulkarni ; R help Mailing list
Subject: Re: [R] printing with bothe print and cat...
Hello,
Like this?
testprint <- function() {
for(i
Hello,
Like this?
testprint <- function() {
for(i in 1:5) {
for(j in 1:5) {
cat(j, "")
}
cat("\t", i, "\n")
}
}
testprint()
#> 1 2 3 4 5 1
#> 1 2 3 4 5 2
#> 1 2 3 4 5 3
#> 1 2 3 4 5 4
#> 1 2 3 4 5 5
Hope this helps,
Rui Barradas
Às 17:46 de 09/07/2
Dear Tim,
Many thanks...
Yours sincerely
AKSHAYM KULKARNI
From: Ebert,Timothy Aaron
Sent: Saturday, July 9, 2022 11:03 PM
To: akshay kulkarni ; David Winsemius
Cc: R help Mailing list
Subject: RE: [R] printing with bothe print and cat
Dear David,
Thanks ...
Yours sinecrely,
AKSHAY M KULKARNI
From: David Winsemius
Sent: Saturday, July 9, 2022 10:30 PM
To: akshay kulkarni
Cc: R help Mailing list
Subject: Re: [R] printing with bothe print and cat...
If spaces needed. In
If spaces needed. In first sequences then
paste( 1:5, collapse=“ “)
Sent from my iPhone
> On Jul 9, 2022, at 9:59 AM, David Winsemius wrote:
>
> Skip the for loops:
>
> cat(paste( seq(1:5), ““, 1:5) )
>
> —
> David
>
> Sent from my iPhone
>
>> On Jul 9, 2022, at 9:47 AM, akshay kulk
Skip the for loops:
cat(paste( seq(1:5), ““, 1:5) )
—
David
Sent from my iPhone
> On Jul 9, 2022, at 9:47 AM, akshay kulkarni wrote:
>
> Dear members,
> I have the following code:
>
> testprint <- function() {
>
> for(i in 1:5) {for(j in 1:5)
> {cat(j)}
>
Dear members,
I have the following code:
testprint <- function() {
for(i in 1:5) {for(j in 1:5)
{cat(j)}
print(i)}
}
And the output is:
> testprint()
12345[1] 1
12345[1] 2
12345[1] 3
12345[1] 4
12345[1] 5
Any idea on how to remove the [1] from the output, and g
M
To: Stefan Evert
Cc: R-help Mailing List
Subject: Re: [R] Printing upon calling a function
No. I wrote the function so I am sure no "invisible" command was used.
Strangely enough, compiling the function isto part of a package, results were
NOT printed. Yes if I call the function d
On 30/11/2020 11:51 a.m., Steven Yen wrote:
Thanks to all. Presenting a large-scale, replicable example can be a
burden to the READERs which was why I was reluctant.
You shouldn't post a large scale reproducible example, you should
simplify it to just the essentials. Often in doing that you w
t
Subject: Re: [R] Printing upon calling a function
Thanks. I know, my point was on why I get something printed by simply doing
line 1 below and at other occasions had to do line 2.
me.probit(obj)
v<-me.probit(obj); v
On 2020/11/30 下午 05:33, Jim Lemon wrote:
> Hi Steven,
> You seem
Thanks to all. Presenting a large-scale, replicable example can be a
burden to the READERs which was why I was reluctant.
I am embarrassed to report that after having to restart Windows after
the system hang on something unrelated, the issue was resolved and
printing was normal. I bet it had n
By not posting a reproducible example, you're wasting everyone's time.
Duncan Murdoch
On 30/11/2020 6:06 a.m., Steven Yen wrote:
No, sorry. Line 1 below did not print for me and I had to go around and
do line 2 to print:
me.probit(obj)
v<-me.probit(obj); v
A puzzle.
On 2020/11/30 下午 07:0
No, sorry. Line 1 below did not print for me and I had to go around and
do line 2 to print:
me.probit(obj)
v<-me.probit(obj); v
A puzzle.
On 2020/11/30 下午 07:00, Duncan Murdoch wrote:
On 30/11/2020 5:41 a.m., Stefan Evert wrote:
On 30 Nov 2020, at 10:41, Steven Yen wrote:
Thanks. I kno
On 30/11/2020 5:41 a.m., Stefan Evert wrote:
On 30 Nov 2020, at 10:41, Steven Yen wrote:
Thanks. I know, my point was on why I get something printed by simply doing
line 1 below and at other occasions had to do line 2.
me.probit(obj)
That means the return value of me.probit() has been mar
No. I wrote the function so I am sure no "invisible" command was used.
Strangely enough, compiling the function isto part of a package, results
were NOT printed. Yes if I call the function during run, by preceding
the call with a line that attach the source code:
source("A:/.../R/oprobit.R")
> On 30 Nov 2020, at 10:41, Steven Yen wrote:
>
> Thanks. I know, my point was on why I get something printed by simply doing
> line 1 below and at other occasions had to do line 2.
>
> me.probit(obj)
That means the return value of me.probit() has been marked as invisible, so it
won't auto-
Thanks. I know, my point was on why I get something printed by simply
doing line 1 below and at other occasions had to do line 2.
me.probit(obj)
v<-me.probit(obj); v
On 2020/11/30 下午 05:33, Jim Lemon wrote:
Hi Steven,
You seem to be assigning the result of me.oprobit(obj) to v instead of
prin
Hi Steven,
You seem to be assigning the result of me.oprobit(obj) to v instead of
printing it. By appending ";v" tp that command line, you implicitly
call "print".
Jim
On Mon, Nov 30, 2020 at 7:15 PM Steven Yen wrote:
>
> I hope I can get away without presenting a replicable set of codes
> becau
Answering you is also a burden without the reprodicible code. I'll pass on that.
But I will say that mixing analysis with output in the same function is a
terrible habit. Come to the functional side of coding... it is much more
re-usable here.
On November 30, 2020 12:14:35 AM PST, Steven Yen w
I hope I can get away without presenting a replicable set of codes
because doing so would impose burdens.
I call a function which return a data frame, with the final line
return(out)
In one case the data frame gets printed (similar to a regression
printout), with simply a call
me.probit(obj
Thank you Lei. I incorporate Bill Dunlap's idea of flagging with FORTRAN
stars when field width is short. It works great and serves what I need.
Thank you all.
I love R!
Steven
Linus Chen 於 2019/7/23 下午 05:46 寫道:
Dear Steven,
The function "write()" has a parameter "columns".
And sprint() ca
Very nice indeed. Thank you gentlemen.
Steven
Michael Friendly 於 2019/7/24 上午 01:23 寫道:
Nice to see William Dunlap take the trouble to mimic the classic
Fortran behavior of printing for numbers that don't fit in the
given width :)
-Michael
On 7/22/19 6:33 p.m., William Dunlap via R-hel
Nice to see William Dunlap take the trouble to mimic the classic Fortran
behavior of printing for numbers that don't fit in the given width :)
-Michael
On 7/22/19 6:33 p.m., William Dunlap via R-help wrote:
The following mimics Fortran printing with format
F..
print1 <- function (x, perL
Thank you, Gentlemen. That serves my need. Bill's routine is great.
Also, Rui: Is there a way to get rid of the filled "NA" and use space
instead. Using fill = "" does not help either; it causes all numbers to
be embraced with quotations. Finally, I have no idea why Rui's message
did not reach
Dear Steven,
The function "write()" has a parameter "columns".
And sprint() can do do some formatting in C style.
x <- rnorm(100)
s <- sprintf( fmt="%8.2f" ,x )
write(s, file="", ncolumns=7L)
Cheers,
Lei
On Mon, 22 Jul 2019 at 07:37, Steven wrote:
>
> Is there a convenient way to print a vect
Hello,
How could I forgot na.print? Thanks, Bill.
This version c no longer has an argument fill and it's the one that
behaves more like the OP asks for so far.
print0c <- function(x, len = 10, digits = 2){
n <- length(x)
x <- round(x, digits = digits)
fill <- NA
m <- n %/% len
remai
By the way, the default print method has the argument 'na.print' that can
speciify how to print an NA value. E.g.,
> print(c(1234/, NA, 1), na.print="n/a")
[1] 0.1234123 n/a 1.000
> print(c(1234/, NA, 1), na.print="")
[1] 0.1234123 1.000
> print(c(1234/, NA, 1)
The following mimics Fortran printing with format
F..
print1 <- function (x, perLine = 10, fWidth = 8, fPrecision = 2,
fortranStars = TRUE)
{
format <- paste0("%", fWidth, ".", fPrecision, "f")
oldWidth <- getOption("width")
on.exit(options(width = oldWidth))
options(width = perLin
Simpler, no loops:
print0b <- function(x, len = 10, digits = 2, fill = ""){
n <- length(x)
x <- round(x, digits = digits)
m <- n %/% len
remainder <- n %% len
A <- matrix(x[seq_len(len*m)], ncol = len)
if(remainder > 0){
A <- rbind(A, c(x[(len*m + 1):n], rep(fill, len*(m + 1) - n
Hello,
Maybe something like the following is what you want.
I have added an extra argument 'fill' to allow to choose what to print
in the end. It's default value is "" making the entire matrix elements
characters but it can be NA or 0.
print0 <- function(x, len = 10, digits = 2, fill = ""){
Dear All:
Below is what I meant. Procedure print0 allows me to print a vector of
length 53 in four rows of 10 plus 1 row of 3 (Ido not like the NA). This
is silly. I am hoping that there is a candid way to print the matrix.
Thank you.
Steven Yen
===
n<-53; x<-runif(n); # x<-round(x,2)
print0
Is there a convenient way to print a vector into rows of a specified
column length? What I need is to print in the old FORTRAN format, viz.,
format(10F8.2)
which would print, for instance, a vector of 25 into two rows of 10 plus
an incomplete row of 5. I managed to write a procedure for that ta
Great! Thanks.
On 5/15/2019 7:00 PM, Rui Barradas wrote:
> Hello,
>
> What's wrong with
>
> test <- function(x){
> table <- matrix(x, nrow = 4)
> cat("\nTable:\n")
> print(table)
> invisible(list(table = table))
> }
>
>
> Hope this helps,
>
> Rui Barradas
>
> Às 10:33 de 15/05/19, Steven Y
Hello,
What's wrong with
test <- function(x){
table <- matrix(x, nrow = 4)
cat("\nTable:\n")
print(table)
invisible(list(table = table))
}
Hope this helps,
Rui Barradas
Às 10:33 de 15/05/19, Steven Yen escreveu:
Dear All,
I would like to get a matrix (table) printed in a procedure,
Dear All,
I would like to get a matrix (table) printed in a procedure, as
attempted below. Please help. Thanks.
test<-function(x){
table<-matrix(x,nrow=4)
cat("\nTable:\n",table)
invisible(list(table=table))
}
x<-1:20
test(x)
--
st...@ntu.edu.tw (S.T. Yen)
[[alternative HTML v
2 13 14 15 16 17 18 1920
[3,] 21 22 23 24 25
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77843-4352
-Original Message-
From: R-help On Behalf Of K. Elo
Sent: Monday, March 25, 2019 2:26 AM
To: r
Hi!
2019-03-25 kello 09:30 +0800, Steven Yen wrote:
> The second command is ugly. How can I print the 25 numbers into 2
> rows
> of ten plus a helf row of 5? Thanks.
Something like this?
x<-1:25; for (i in seq(1,length(x),10))
print(x[i:ifelse((i+9)>length(x),length(x),i+9)])
HTH,
Kimmo
_
I like to print a vector, wrapped by rows of 10.
Below the first command below works for 20 numbers.
The second command is ugly. How can I print the 25 numbers into 2 rows
of ten plus a helf row of 5? Thanks.
> x<-1:20; matrix(x,nrow=2,byrow=T)
[,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9]
> -Original Message-
> From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Michael
> Friendly
> Check out the `matlib` package on CRAN and devel on github:
Very nice! Thanks for the pointer.
Steve E
***
This
John-
Don't try to forge a new wheel, when you can get one ready made
and it might fit your wagon.
Check out the `matlib` package on CRAN and devel on github:
https://github.com/friendly/matlib
install.packages("matlib")
library(matlib)
A <- matrix(c(1,2,3, -1, 2, 1), 3, 2)
b <- c(2,1,3)
show
Steve,
Thank you,
John
John David Sorkin M.D., Ph.D.
Professor of Medicine
Chief, Biostatistics and Informatics
University of Maryland School of Medicine Division of Gerontology and Geriatric
Medicine
Baltimore VA Medical Center
10 North Greene Street
GRECC (BT/18/GR)
Baltimore, MD 21201-1524
Don't use the default print method then. When you type an expression alone at
the console it uses a print function to convert the result to characters for
output. The default print method for matrices of character uses quotes to show
the exact contents of each character string.
Convert the matr
You can drop the quote marks by calling print() explicitly with quote=FALSE, by
using as.data.frame round your cbind, or - perhaps best - by constructing your
output matrix as a data frame in the first place. (print.data.frame defaults
to quote=FALSE). And if you suppress name checking in a dat
I am trying to print a list of equations in an easily readable form. At this
time all I can get is a series of characters enclosed in quotation marks
rather than equations with numbers and equal signs. What I get is
y equalsigns x z
eq1 "0.5" "=""1" "2"
eq2 "4" "=""
Thank you all - print works wonders.
On 12/22/2018 10:36 PM, Eric Berger wrote:
> Hi Steven,
> Here's one way, using print
>
> try5<-function(A,B){
> C<-A+B
> #cat("\nA =",A,"\nC = ",C)
> cat("\nA = ")
> print(A)
> cat("\nC = ")
> print(C)
> structure(list(A=A,B=B,C=C))
> }
>
> HTH,
Try using print instead of cat [1], and please read about what the arguments
are in the help file [2][3] for any function you are using before posting a
question.
[1]
https://stackoverflow.com/questions/31843662/what-is-the-difference-between-cat-and-print
[2] ?cat
[3] ?print
On December 22, 2
Hello,
Use print(A) and print(C). cat is meant for simpler objects.
Hope this helps,
Rui Barradas
Às 14:31 de 22/12/2018, Steven Yen escreveu:
How do I print a matrix running a procedure? In the code below, I print
with the cat command and get a vector (from A and C).
A<-matrix(rpois(16,lamb
Hi Steven,
Here's one way, using print
try5<-function(A,B){
C<-A+B
#cat("\nA =",A,"\nC = ",C)
cat("\nA = ")
print(A)
cat("\nC = ")
print(C)
structure(list(A=A,B=B,C=C))
}
HTH,
Eric
On Sat, Dec 22, 2018 at 4:32 PM Steven Yen wrote:
> How do I print a matrix running a procedure? I
How do I print a matrix running a procedure? In the code below, I print
with the cat command and get a vector (from A and C).
A<-matrix(rpois(16,lambda=5),nrow=4,byrow=T)
B<-diag(4)
try5<-function(A,B){
C<-A+B
cat("\nA =",A,"\nC = ",C)
structure(list(A=A,B=B,C=C))
}
v<-try5(A,B)
v$C
--
st
University of New England
Armidale NSW 2350
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of David
Winsemius
Sent: Friday, 28 September 2018 04:53
To: David Disabato
Cc: r-help@r-project.org
Subject: Re: [R] Printing standard notation and scientific notation in
First compare
> format(c(0.52, 0.17, 0.03, 1e-20))
[1] "5.2e-01" "1.7e-01" "3.0e-02" "1.0e-20"
> prettyNum(c(0.52, 0.17, 0.03, 1e-20))
[1] "0.52" "0.17" "0.03" "1e-20"
>
If you want to print one column at a time, that will do what you ask. If you
want to print the entire data frame, with num
> On Sep 27, 2018, at 9:35 AM, David Disabato wrote:
>
> Hi R-help,
>
> I was wondering if it was possible for a column of a dataframe to print
> some numbers in standard notation and some in scientific notation. Say my
> column of data (i.e., dat$x) has numbers between 0 and 1 with a few numb
Hi R-help,
I was wondering if it was possible for a column of a dataframe to print
some numbers in standard notation and some in scientific notation. Say my
column of data (i.e., dat$x) has numbers between 0 and 1 with a few numbers
very close to 0. When using the "scipen" argument in "options," R
Duncan
Many thanks. I removed the (re-)definitions for print and print.default, and I
redefined print.data.frame using 'x' instead of 'df'.
Your point about possible issues downstream with row names is well taken. I'll
keep a lookout for any untoward side effects.
In the meantime, all is wel
On 06/06/2018 6:28 AM, zListserv wrote:
Sorry. Here's how I re-defined print, print.default, and print.data.frame:
print = function(df, ..., right=FALSE, row.names=FALSE) base::print(df, ...,
right=right, row.names=row.names)
base::print doesn't have those arguments. It only has arguments
Sorry. Here's how I re-defined print, print.default, and print.data.frame:
print = function(df, ..., right=FALSE, row.names=FALSE) base::print(df, ...,
right=right, row.names=row.names)
print.default = function(df, ..., right=FALSE, row.names=FALSE)
base::print.default(df, ..., right=right, ro
yes, thank you for catching that slip.
On Tue, Jun 5, 2018 at 11:29 PM, Christopher W. Ryan
wrote:
> Richard--
>
> Nice. If I understand your code correctly, in the line
>
> ddm <- matrix("", (n+2) %/% nc, nc)
>
> I could instead use
>
> ddm <- matrix("", (n + nc - 1) %/% nc, nc)
>
> for generali
Richard--
Nice. If I understand your code correctly, in the line
ddm <- matrix("", (n+2) %/% nc, nc)
I could instead use
ddm <- matrix("", (n + nc - 1) %/% nc, nc)
for generalizability, as I may have to increase nc as the list of words
grows ever longer.
Thanks everyone. Several good suggesti
I think this is cuter, and it is a hair faster.
n <- length(dd)
ddm <- matrix("", (n+2) %/% nc, nc)
ddm[1:n] <- dd
Rich
> system.time(for (i in 1:1) {
+ add <- nc - (length(dd) %% nc)
+ dd2 <- c(dd, rep("", add))
+ ddm <- matrix(dd2, ncol = nc)
+ })
user system elapsed
0.064 0.100
> On Jun 5, 2018, at 9:45 AM, Christopher W Ryan wrote:
>
> I'm writing code for a recurring report, using an R --> Sweave --> pdflatex
> workflow. It includes a character vector of short words that I would like
> to display compactly, in columns on a page, rather than one word per line,
> whi
On 05/06/2018 7:49 PM, zListserv wrote:
p.s. It seems to work for print command, but not for head, tail, or printing a
data frame, per below. Any way fix the others so they all left-justify?
You haven't shown us what you did.
Duncan Murdoch
__
R-
p.s. It seems to work for print command, but not for head, tail, or printing a
data frame, per below. Any way fix the others so they all left-justify?
R> x <- as.data.frame(rep(c("a", "ab", "abc"), 7))
R> print(x)
rep(c("a", "ab", "abc"), 7)
a
ab
Duncan et al
I tried to redefine print.data.frame the way you suggested, but I misplaced the
ellipsis by putting it at the end of the function definition instead of
immediately following the name of the data frame.
Works now.
Thanks!
> On 2018-06-05, at 12:39, Duncan Murdoch wrote:
>
> On
Anthropology
Texas A&M University
-Original Message-
From: R-help [mailto:r-help-boun...@r-project.org] On Behalf Of Duncan Murdoch
Sent: Tuesday, June 5, 2018 11:40 AM
To: zListserv ; r-help@r-project.org
Subject: Re: [R] Printing left-justified character strings
On 05/06/2018 10:2
I'm writing code for a recurring report, using an R --> Sweave --> pdflatex
workflow. It includes a character vector of short words that I would like
to display compactly, in columns on a page, rather than one word per line,
which would waste a lot of space. The vector of words will increase
unpred
On 05/06/2018 10:24 AM, zListserv wrote:
Many (most?) R functions print character strings and factor labels
right-justified.
Could you be more specific? I see character strings left justified,
e.g. x <- rep(c("a", "ab", "abc"), 7) prints as
[1] "a" "ab" "abc" "a" "ab" "abc" "a"
[
Many (most?) R functions print character strings and factor labels
right-justified.
print accepts right=FALSE to print character strings left-justified, but
neither head nor tail seem to do so, and even print is a little inconsistent
depending on whether it's done while knitting.
Is there a wa
Martin, I'm pretty sure the use of Matrix here (actually by someone
else than Dr Bryan) was to make an easy, inline, reproducible example.
The actual "ugh" column comes from using git2r. I'm assuming there's
an API call returning some pretty gnarly structures that are getting
shoehorned into a data
> boB Rudis
> on Tue, 12 Jan 2016 13:51:50 -0500 writes:
> I wonder if something like:
> format.list <- function(x, ...) {
> rep(class(x[[1]]), length(x))
> }
> would be sufficient? (prbly needs more 'if's though)
Dear Jenny,
for a different perspective (and a lo
I wonder if something like:
format.list <- function(x, ...) {
rep(class(x[[1]]), length(x))
}
would be sufficient? (prbly needs more 'if's though)
On Tue, Jan 12, 2016 at 12:15 PM, Jenny Bryan wrote:
> Is there a general problem with printing a data.frame when it has a
> list-column of S4 obj
Is there a general problem with printing a data.frame when it has a
list-column of S4 objects? Or am I just unlucky in my life choices?
I ran across this with objects from the git2r package but maintainer
Stefan Widgren points out this example below from Matrix as well. I note
that the offending o
Thanks a lot Sarah. I think I've got what I wanted.
On Mon, Jul 20, 2015 at 2:55 PM, Sarah Goslee wrote:
> Subsetting error. See below.
>
> On Mon, Jul 20, 2015 at 3:29 PM, gaurav kandoi wrote:
>> Hi Sarah, sorry for posting in HTML.
>>
>> I've two big matrices (5k*4k) with the same structure, i
Subsetting error. See below.
On Mon, Jul 20, 2015 at 3:29 PM, gaurav kandoi wrote:
> Hi Sarah, sorry for posting in HTML.
>
> I've two big matrices (5k*4k) with the same structure, i.e. :
>
> ,mRNA1,mRNA2,mRNA3
> lncRNA1,0.395646498,0.949950035,0.761770206
> lncRNA2,0.037909944,0.661258022,0.5586
Hi Sarah, sorry for posting in HTML.
I've two big matrices (5k*4k) with the same structure, i.e. :
,mRNA1,mRNA2,mRNA3
lncRNA1,0.395646498,0.949950035,0.761770206
lncRNA2,0.037909944,0.661258022,0.558657799
lncRNA3,0.678459646,0.652364052,0.359053653
Now, I would like to extract the names of the
Without a reproducible example, or at least a non-mangled one (please
don't post in HTML), I'm not inclined to try it, but why not use
sig_values to index row.names() and col.names() if you're after the
names?
Sarah
On Mon, Jul 20, 2015 at 1:44 PM, gaurav kandoi wrote:
> Hi All
>
> I've two big
Hi All
I've two big matrices (5k*4k) with the same structure, i.e. :
mRNA1 mRNA2 mRNA3 lncRNA1 0.395646 0.94995 0.76177 lncRNA2 0.03791
0.661258 0.558658 lncRNA3 0.67846 0.652364 0.359054 lncRNA4 0.57769 0.003
0.459127
Now, I would like to extract the names of the row,col pairs whose value
ingston ON Canada
> -Original Message-
> From: shivibha...@ymail.com
> Sent: Wed, 27 May 2015 04:32:30 -0700 (PDT)
> To: r-help@r-project.org
> Subject: [R] Printing with Header & no of observations
>
> HI Team,
> A quick question.
>
> When I used t
HI Team,
A quick question.
When I used the print option in R to see the output of my syntax I do not
see the headers or column names. Is there a way to see the headers in the
print.
Also as most of the datasets we work today have huge number of observations
but when I print it only shows a portion
On Tue, Dec 9, 2014 at 3:11 PM, Henrik Bengtsson wrote:
> I'm surprised no one mentioned alternatives to LaTeX, which is not
> necessarily installed on all systems and it's also quite a
> heavy-weight setup (100's-1000's MBs). An alternative is to output a
> table in Markdown or HTML and convert
?latex
answers a lot of these questions.
The design intent of the latex() function is to construct one table at
a time in its own .tex flle.
The user then collects these and inserts them into a full document,
either manually or with Sweave.
The individual table has no context and no caption.
It i
The program 'gv' is installed on just about any linux system.
It has many available options (one, which might be useful,
being "-watch", whose effect is that if the file being displayed
is changed, e.g. by being over-written by a new file with the
same name, then 'gv' automatically updates what it
Okay, all.
I have it to work using this:
library(Hmisc)
options(latexcmd='pdflatex')
options(dviExtension='pdf')
options(xdvicmd='gnome-open')
Running your simple code from above... by question is this: the pdf
is saved in a tmp directory... where do I change the directory path? I
thought it wa
I'm surprised no one mentioned alternatives to LaTeX, which is not
necessarily installed on all systems and it's also quite a
heavy-weight setup (100's-1000's MBs). An alternative is to output a
table in Markdown or HTML and convert that to PDF. The poor man's
HTML-to-PDF is to manually open the
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