Hi,
Thanks for the response. Unfortunately this did not solve my problem and
may be the way I represented my data would be the problem. I am not sure
that I can give a link for the data which will give a clear representation.
If that is not a proper way, I have to follow my original method.
Regar
Correction to my code. I created a "doc" variable because I was thinking of
doing something faster, but I never did the change. grep needed to work on
the original source "dat" to be used for counting.
Fixed:
combs = structure(list(V1 = c(65L, 77L, 55L, 23L, 34L), V2 = c(23L, 34L,
34L, 77L, 65L
If I understood the request this is the same programming task as counting
words in a document and counting character sequences in a string or
matching bytes in byte arrays (though you don't want to go down that far)
You can do something like what follows. There are also vectorized greps
in strin
Hi,
It is not a just 79 triplets. As I said, there are 79 codes. I am making
triplets out of that 79 codes and matching the triplets in the list.
Please find the dput of the data below.
> dput(head(newd,10))
structure(list(uniq_id = c("1", "2", "3", "4", "5", "6", "7",
"8", "9", "10"), hi = c("1
You said you had 79 triplets and 8000 records.
When I compared 100 triplets to 1 records it took 86 seconds.
So obviously there is something you're not telling us about the format
of your data.
If you use dput() to provide actual examples, you will get better
results than if we on Rhelp have
Hi,
Thanks for the solution. But I am afraid that after running this code still
it takes more time. It has been an hour and still it is executing. I
understand the delay because each triplet has to compare almost 9000
elements.
Regards,
Sri
On Wed, Jul 27, 2016 at 9:02 PM, Sarah Goslee
wrote:
Hi,
It's really a good idea to use dput() or some other reproducible way
to provide data. I had to guess as to what your data looked like.
It appears that order doesn't matter?
Given than, here's one approach:
combs <- structure(list(V1 = c(65L, 77L, 55L, 23L, 34L), V2 = c(23L, 34L,
34L, 77L, 6
Hi,
Apologizes for the less information.
Basically, myCombos is a matrix with 3 variables which is a triplet that is
a combination of 79 codes. There are around 3lakh combination as such and
it looks like below.
V1 V2 V3
65 23 77
77 34 65
55 34 23
23 77 34
34 65 55
Each triplet will compare in
Not entirely sure I understand, but match() is already vectorized, so you
should be able to lose the supply(). This would speed things up a lot.
Please re-read ?match *carefully* .
Bert
On Jul 27, 2016 6:15 AM, "sri vathsan" wrote:
Hi,
I created list of 3 combination numbers (mycombos, around
A reproducible example makes your problem easier to understand.
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature and
Forest
team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
Kliniekstraat 25
1070 Anderlecht
Belgium
To call in the stat
Hi,
I created list of 3 combination numbers (mycombos, around 3 lakh
combinations) and counting the occurrence of those combination in another
list. This comparision list (mylist) is having around 8000 records.I am
using the following code.
myCounts <- sapply(1:nrow(myCombos), FUN=function(i) {
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