What is it you think as.numeric accomplishes for you? A reproducible example as
requested in the posting guide might clarify.
Making factors and leaving them that way seems more productive.
---
Jeff Newmiller
Le lundi 24 septembre 2012 à 11:25 +0530, Vignesh Prajapati a écrit :
> Hello all,
>
> I am new to R, I am learning regression and logistic modeling
> with categorical predictor variables, when there is only one predictor
> categorical variable i can use as.numeric() but when more than t
Hello all,
I am new to R, I am learning regression and logistic modeling
with categorical predictor variables, when there is only one predictor
categorical variable i can use as.numeric() but when more than two variable
then what is solution? can anyone suggest me?
Thanks
vignesh
Dear ales,
Try this:
# Data
# set.seed(123)
mat=matrix(rnorm(36),ncol=6)
colnames(mat)=paste('x',1:6,sep="")
res=rnorm(6)
# All info for coefficients. First 4 columns # correspond to the intercept
and the next for to the slope
t(apply(mat,2,function(x){
sm=summary(lm(res~x))$coeff
res=matrix(sm,n
On Nov 27, 2008, at 9:49 AM, David Winsemius wrote:
Have you looked at results of str on a regression object? I would
not think that there would be a single p.value associated with such
a beast, but that there might be if you examined individual
coefficients.
? coefficients
?coef
That w
Have you looked at results of str on a regression object? I would not
think that there would be a single p.value associated with such a
beast, but that there might be if you examined individual coefficients.
? coefficients
?coef
--
David Winsemius
On Nov 27, 2008, at 4:03 AM, ales grill wro
Dear all,
I have wrote a code for a linear regression. I want to
write a loop for so, that I can get estimate for pavlues for six predictors.
But I am getting for estmate for only last one. How can I get pvalues for
all my predictors in a loop??
Anticipating your help
Thanks
Ales
On 7/15/08, Angila Albaros <[EMAIL PROTECTED]> wrote:
>
> Dear Sir,
> Thanks for your reply but my data is very huge 100 x 550 (
> for x ) and 100 x 1010 ( for y). So, I think that time , I need to take one
> column of x ($x1)and do multiple regreesion with y data set.i.e x1 will be
Douglas Bates wrote:
On Tue, Jul 15, 2008 at 10:25 AM, Patrick Burns
<[EMAIL PROTECTED]> wrote:
That can be accomplished with 8 keystrokes.
A hint is to do the 4 keystrokes:
?lm
Umm - unless you are counting the implicit , that's only 3
keystrokes isn't it?
You give away that you're an Em
On Tue, Jul 15, 2008 at 10:25 AM, Patrick Burns
<[EMAIL PROTECTED]> wrote:
> That can be accomplished with 8 keystrokes.
> A hint is to do the 4 keystrokes:
> ?lm
Umm - unless you are counting the implicit , that's only 3
keystrokes isn't it?
> Angila Albaros wrote:
>>
>> Hello all,
>>
That can be accomplished with 8 keystrokes.
A hint is to do the 4 keystrokes:
?lm
Patrick Burns
[EMAIL PROTECTED]
+44 (0)20 8525 0696
http://www.burns-stat.com
(home of S Poetry and "A Guide for the Unwilling S User")
Angila Albaros wrote:
Hello all,
I am new to r programmean
Hello all,
I am new to r programmeand need help. I want to do
multiple linear regression analysis. say, I have two matrix 'x' and 'y'. I
want, 'x' as my response variable and 'y' as predictor.
Each time one column of 'x' will be the response, say x[,1], then next x[,2]
and so on.
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