Actually
sapply(x %% 1, function(x) isTRUE(all.equal(x, 0)))
seems to be the way to go.
Uwe Ligges
On 14.08.2011 07:17, Ken wrote:
How about something like:
If(round(x)!=x){zap} not exactly working code but might help
Ken
On Aug 13, 2554 BE, at 3:42 PM, Paul Johnson wrote:
A client
How about something like:
If(round(x)!=x){zap} not exactly working code but might help
Ken
On Aug 13, 2554 BE, at 3:42 PM, Paul Johnson wrote:
> A client came into our consulting center with some data that had been
> damaged by somebody who opened it in MS Excel. The columns were
> supposed
Hi Paul,
What about using:
x[x != as.integer(x)] <- NA
I cannot think of a situation off hand where this would fail to turn
every non integer to missing.
I wonder if there is really a point to this? Can the client proceed
with data analysis with any degree of confidence when an unknown
mechani
A client came into our consulting center with some data that had been
damaged by somebody who opened it in MS Excel. The columns were
supposed to be integer valued, 0 through 5, but some of the values
were mysteriously damaged. There were scores like 1.18329322 and such
in there. Until he tracks
Hello, fellow R users,
I recently need to estimate a dynamic linear model in the following form:
For the measurement equation:
Y_t = F_t * a_t + v_t
where Y_t is the observation. It is a 1 by q row vector for each t.
F_t is my forecasting variable. It is a 1 by p row vector.
a_t is my st
Hi folks,
Has any folks read before;
Basic Statistics
Rand R.Wilcox
http://www.ebooksx.com/Basic-Statistics-Understanding-Conventional-Methods-and-Modern-Insights_303718.html
It is good for a layman in statistics? TIA
B.R.
Stephen L
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