On Wed, Sep 29, 2010 at 4:15 AM, Steven Kang wrote:
> x <- rep(letters[1:3], 2)
>
> Are there any ways to transform & assign the above as the one shown below
> to an object? (in exact format; i.e length of 1 & class of character),
> i.e
>>x
> "('a', 'b', 'c', 'a', 'b', 'c')"
>
> Highly appreciate
> Cc: r-help@r-project.org
> Subject: Re: [R] String split and concatenation
>
> > paste( '(', paste( "'", rep(letters[1:3],2), "'", sep="",
> collapse=','), ')', sep="" )
> [1] "('a',
-
> From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
> project.org] On Behalf Of Steven Kang
> Sent: Wednesday, September 29, 2010 2:16 AM
> To: bill.venab...@csiro.au
> Cc: r-help@r-project.org
> Subject: Re: [R] String split and concatenation
>
> x <- rep(le
r-project.org]
> On Behalf Of Steven Kang
> Sent: Wednesday, 29 September 2010 3:11 PM
> To: r-help@r-project.org
> Subject: [R] String split and concatenation
>
> Hi R users,
>
>
> I desire to transform the following vector consisting of repeated
> characters
>
>
dump("x", file = "x.R")
file.show("x.R")
will get you most of the way.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Steven Kang
Sent: Wednesday, 29 September 2010 3:11 PM
To: r-help@r-project.org
Hi Steven,
This should do it:
paste('"', unlist(strsplit(x, split="")), c(rep('",', length(x)-1), ""), sep="")
-Ista
On Wed, Sep 29, 2010 at 1:11 AM, Steven Kang wrote:
> Hi R users,
>
>
> I desire to transform the following vector consisting of repeated characters
>
> x <- rep(letters, 3)
> in
Hi R users,
I desire to transform the following vector consisting of repeated characters
x <- rep(letters, 3)
into this exact format (i.e a single string containing each characters in
quotation mark separated by comma between each; al ).
("a", "b", "c", "d", "a", "b", "c", "d",
7 matches
Mail list logo
