two things:
- R always counts from 1, not from 0
- listmembers are accessed by using [[ ]] , not [ ]
try
t1[t==ll[[1]], v] - 99
greetings Jessi
On 11.07.2012, at 15:47, Charles Stangor wrote:
I can't seem to determine how to get the name of a list member to
substitute:
ll - list(a1 =
thanks!
On Fri, Jul 13, 2012 at 4:35 AM, Jessica Streicher j.streic...@micromata.de
wrote:
two things:
- R always counts from 1, not from 0
- listmembers are accessed by using [[ ]] , not [ ]
try
t1[t==ll[[1]], v] - 99
greetings Jessi
On 11.07.2012, at 15:47, Charles Stangor wrote:
Jessica:
On Fri, Jul 13, 2012 at 1:35 AM, Jessica Streicher j.streic...@micromata.de
wrote:
two things:
- R always counts from 1, not from 0
- listmembers are accessed by using [[ ]] , not [ ]
FALSE! -- or at least not clearly stated:
x - list(a=letters[1:3],b=1:4)
x[[2]]
[1] 1 2 3 4
On 13/07/2012 9:50 AM, Bert Gunter wrote:
Jessica:
On Fri, Jul 13, 2012 at 1:35 AM, Jessica Streicher j.streic...@micromata.de
wrote:
two things:
- R always counts from 1, not from 0
- listmembers are accessed by using [[ ]] , not [ ]
FALSE! -- or at least not clearly stated:
x -
I can't seem to determine how to get the name of a list member to
substitute:
ll - list(a1 = a,a2 = b)
t1[t==ll[0], v] - 99
why doesn't this substitute to:
t1[t==a, v] - 99
Thank you!
--
Charles Stangor
Professor
[[alternative HTML version deleted]]
I can't seem to determine how to get the name of a list member to
substitute:
ll - list(a1 = a,a2 = b)
t1[t==ll[0], v] - 99
why doesn't this substitute to:
t1[t==a, v] - 99
Thank you!
[[alternative HTML version deleted]]
__
I can't seem to determine how to get the name of a list member to
substitute as a variable name:
ll - list(a1 = a,a2 = b)
t1[t==ll[1], v] - 99
why doesn't this substitute to:
t1[t==a, v] - 99
Thank you!
--
Charles Stangor
Professor
--
Charles Stangor
Professor
[[alternative
It should. Reproducible example of it not?
Michael
On Jul 11, 2012, at 3:06 PM, Charles Stangor cstan...@gmail.com wrote:
I can't seem to determine how to get the name of a list member to
substitute as a variable name:
ll - list(a1 = a,a2 = b)
t1[t==ll[1], v] - 99
why doesn't this
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