Hello,
I'm glad you have a solution that works.
Maybe you could do the same without hard-coding the values 1:7, 8:14.
$
library(chron)
dat <- with(my_dataframe, paste(month, day, year, sep="/"))
week <- cut(chron(dat), breaks="weeks")
head(week)
tapply(my_dataframe$Freq, week, mean)
Hope thi
Thank you to Ozgur, who gave me the hints for an easy solution.
There are the commands that work for my case:
mean(my_dataframe$Freq[my_dataframe$month == 5 & my_dataframe$day %in% c(1:7)])
mean(my_dataframe$Freq[my_dataframe$month == 5 & my_dataframe$day %in% c(8:14)])
...
Stefano Sofia PhD
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