0.003711
...
The times are shown in .
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
Of Mark Leeds
Sent: Saturday, October 20, 2012 9:16 AM
To: R help
Subject: [R
Hi : I looked at the help for system.time but I still have the following
question. Can someone explain the output following output
of system.time :
user system elapsed
12399.681 5632.352 56935.647
Here's my take based on the fact that I was doing ps -aux | grep R off and
on and
You asked several questions.
Elapsed: yes
User + System = CPU: yes
Finally: You have to look at the load and/or cpu core count. Unless you setup
your code to take advantage of multiple cores, R runs on a single core.
Also: Do you really need to ask that question?
On 20/10/2012 17:16, Mark Leeds wrote:
Hi : I looked at the help for system.time but I still have the following
question. Can someone explain the output following output
of system.time :
user system elapsed
12399.681 5632.352 56935.647
Yes, the help page can, via
This is an indication of the amount of CPU resources that you are
using. Elapsed time is just the number of seconds that the R process
(e.g., RGUI) has been running. user time is the amount of CPU that
any commands/scripts have used that you are running; this is the one
that you are typically
Dear R users.
I wanted to know, how do we read the output of system.time. It would be
helpful if you could let me know what are user system and elapsed.
Regards
Vikram
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R-help@r-project.org mailing list
Hi Vikram,
Check ?system.time and ?proc.time.
HTH,
Jorge.-
On Mon, Nov 28, 2011 at 12:41 AM, Vikram Bahure wrote:
Dear R users.
I wanted to know, how do we read the output of system.time. It would be
helpful if you could let me know what are user system and elapsed.
Regards
Vikram
Wacek Kusnierczyk wrote:
to contribute my few cents, here's a simple benchmarking routine,
inspired by the perl module Benchmark. it allows one to benchmark an
arbitrary number of expressions with an arbitrary number of
replications, and provides a summary matrix with selected timings.
On Wed, 2009-02-11 at 18:49 -0600, John Kerpel wrote:
Hi folks!
Does anyone know why I might see something like this after running
system.time?
system.time(svd(Mean_svd_data))
user system elapsed
0 0 0
The data set is tiny and the function returns results
Gavin Simpson wrote:
On Wed, 2009-02-11 at 18:49 -0600, John Kerpel wrote:
Hi folks!
Does anyone know why I might see something like this after running
system.time?
system.time(svd(Mean_svd_data))
user system elapsed
0 0 0
The data set is tiny and the function
On Thu, Feb 12, 2009 at 4:28 AM, Gavin Simpson gavin.simp...@ucl.ac.uk wrote:
When I'm testing the speed of things like this (that are in and of themselves
very quick) for situations where it may matter, I wrap the function call in a
call
to replicate():
system.time(replicate(1000,
On Thu, Feb 12, 2009 at 8:42 AM, Stavros Macrakis macra...@alum.mit.edu wrote:
On Thu, Feb 12, 2009 at 4:28 AM, Gavin Simpson gavin.simp...@ucl.ac.uk
wrote:
When I'm testing the speed of things like this (that are in and of themselves
very quick) for situations where it may matter, I wrap the
On Thu, 2009-02-12 at 09:42 -0500, Stavros Macrakis wrote:
On Thu, Feb 12, 2009 at 4:28 AM, Gavin Simpson gavin.simp...@ucl.ac.uk
wrote:
When I'm testing the speed of things like this (that are in and of
themselves
very quick) for situations where it may matter, I wrap the function call
Hi folks!
Does anyone know why I might see something like this after running
system.time?
system.time(svd(Mean_svd_data))
user system elapsed
0 0 0
The data set is tiny and the function returns results instantly, but
shouldn't it still give me a time?
Thanks,
John
It depends on the granularity that the operating system is recording
that time; on some systems the minimum might be 0.01 seconds. If it
is that short, why worry about it. There is nothing unusual about the
result.
On Wed, Feb 11, 2009 at 7:49 PM, John Kerpel john.ker...@gmail.com wrote:
Hi
I thought system.time() would return three numbers, the first two
adding up to the third one. However, this does not hold in my system
running Windows Vista Home Premium, with an Intel Core 2 Duo
processor. For example, using the code in the help for system.time()
(with one zero added), I got:
The first two numbers will not add up to the third. The third is the
elapsed time (wall clock) and the first two are CPU time; even though
they have what appears to be the same units (seconds), they can not
really be compared. If, for example, was script was taking input from
the console, you
Hello list,
I found that system.time works correctly when I used - to assign a
value to a variable but when I happened to use = instead of -, R
gave an error message:
Error in system.time(your argument here...). It happened with a few
functions I tried. Is this a bug or is there any circumstances
On Thu, 10 Apr 2008, Kyeongmi Cheon wrote:
Hello list,
I found that system.time works correctly when I used - to assign a
value to a variable but when I happened to use = instead of -, R
gave an error message:
Error in system.time(your argument here...). It happened with a few
functions I
Kyeongmi asks:
Hello list,
I found that system.time works correctly when I used - to assign
a value to a variable but when I happened to use = instead of
-, R gave an error message: Error in system.time(your argument
here...). It happened with a few functions I tried. Is this a bug
You need to print the result of an expression if used from source().
Autoprinting only occurs at the top level.
E.g.
% cat systest.R
print(system.time(for(i in 1:100) mad(runif(1000
source(systest.R)
user system elapsed
0.140.000.20
On Mon, 17 Sep 2007, Leeds, Mark (IED)
Try this:
source(myfile.R, echo = TRUE)
On 9/17/07, Leeds, Mark (IED) [EMAIL PROTECTED] wrote:
If I type the line below at my Rprompt, it works fine. But, if I put the
same line in a file called systest.R and then source that file at
the prompt, nothing happens. IF I use R CMD BATCH, it also
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