It's the other way around.
You are trying to replace 10 elements (x[i]) with 20 elements (y). R
makes a "best
guess" as to how you want to do that. 10 is not a multiple of 20.
If you were trying to replace 20 elements with 10, then R would recycle them
because 20 _is_ a multiple of 10.
The safes
rkevinbur...@charter.net wrote:
> This was just an illustration. It is the warning message that I don't
understand. The warning says "number of items to replace is not a
multiple of replacement length". The way I look at it 10 is a multiple
of 20.
Um, with a multiplier of 0.5 ?
You're trying to p
This was just an illustration. It is the warning message that I don't
understand. The warning says "number of items to replace is not a multiple of
replacement length". The way I look at it 10 is a multiple of 20.
Kevin
Sarah Goslee wrote:
> The lengths are different, particularly the le
The lengths are different, particularly the length of subsetted x[i]
> x <- 1:20
> i <- x %% 2 > 0
> y <- rep(1,20)
> length(x)
[1] 20
> length(i)
[1] 20
> length(x[i])
[1] 10
> length(y)
[1] 20
You happened to be lucky and got what you wanted, but a more reliable
approach is:
> x[i] <- y[i]
S
I have a question on whether a warning message is valid or if I just don't
understand the process. Let me illustrate via some R code:
x <- 1:20
i <- x %% 2 > 0
y <- rep(1,20)
x[i] <- y
Warning message:
In x[i] <- y :
number of items to replace is not a multiple of replacement length
But it st
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