mean? How do I make class formula
into a call?
This is really a misleading subject: it is already a call! From
?class
Many R objects have a ‘class’ attribute, a character vector giving
the names of the classes from which the object _inherits_. If the
object does not have a class attribute
On Jun 26, 2011, at 00:10 , David Winsemius wrote:
On Jun 25, 2011, at 4:33 PM, peter dalgaard wrote:
I.e., an unevaluated formulae expression (as in quote(y~x)) is class call,
as is an unclassed formula object. So it is pretty easy to have objects of
class formula very similar to
]])
[1] call
Rita
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If you think education is expensive, try ignorance.--Derek Bok
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Sent from the R help
]])
[1] formula class(eqSystem)
[1] list
class(eqSystem[1])
[1] list
class(eqSystem[[1]])
[1] call
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On Jun 25, 2011, at 15:24 , David Winsemius wrote:
On Jun 24, 2011, at 6:12 PM, StellathePug wrote:
Hello R Users!
I have a list called tabs that I would like to have the same structure as
my list eqSystem. The two look like they have the same structure but they
are different because
On Jun 25, 2011, at 4:33 PM, peter dalgaard wrote:
On Jun 25, 2011, at 15:24 , David Winsemius wrote:
On Jun 24, 2011, at 6:12 PM, StellathePug wrote:
Hello R Users!
I have a list called tabs that I would like to have the same
structure as
my list eqSystem. The two look like they have
I have a list called tabs that I would like to have the same structure as my
list eqSystem. The two look like they have the same format but they are
different because when I look at their attributes, class(eqSystem[[1]]) is
call but class(tabs[[1]]) is formula. I want to have class(tabs[[1]])
Well, this is kind of complicated. The first place you should go for
help is not this list, but the R docs. Specfically ?call. This
assumes familiarity with R's (S3) class system and language structure,
however.. For this, I suggest ?UseMethod and consulting the R Language
Definition Manual.
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