On 2010-12-28 11:17, Tyler Dean Rudolph wrote:
Part of the reason I was having difficulty is that I'm trying to add a
legend with more than one element:
plot(1,1)
obv = 5
txt = "Pop mean"
# this works
legend("topleft", legend=bquote(.(txt) == .(obv)*degree))
# but this doesn't
legend("topleft"
Hi,
this seems to work,
plot.new()
legend("topleft", legend=as.expression(c(bquote(.(txt) ==
.(obv)*degree), "Von Mises distribution")))
HTH,
baptiste
On 28 December 2010 20:17, Tyler Dean Rudolph
wrote:
> legend("topleft", legend=c(bquote(.(txt) == .(obv)*degree), "Von Mises
> distribution"
Part of the reason I was having difficulty is that I'm trying to add a
legend with more than one element:
plot(1,1)
obv = 5
txt = "Pop mean"
# this works
legend("topleft", legend=bquote(.(txt) == .(obv)*degree))
# but this doesn't
legend("topleft", legend=c(bquote(.(txt) == .(obv)*degree), "Von
On 2010-12-27 16:51, David Winsemius wrote:
On Dec 27, 2010, at 6:40 PM, T.D. Rudolph wrote:
I've exceeded the maximum time I am willing to accept for solving
simple
problems so I thank all in advance for your assistance.
I am trying to plot text combined with an object value and a
superscri
On Dec 27, 2010, at 6:40 PM, T.D. Rudolph wrote:
I've exceeded the maximum time I am willing to accept for solving
simple
problems so I thank all in advance for your assistance.
I am trying to plot text combined with an object value and a
superscript.
obv = 5
text = "Population mean ="
I've exceeded the maximum time I am willing to accept for solving simple
problems so I thank all in advance for your assistance.
I am trying to plot text combined with an object value and a superscript.
obv = 5
text = "Population mean ="
ss = ^o # degrees
Something like this (very naive so yo
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