l1)), function(i) fun2(l1[[i]], l2[[i]]))
If I'm wrong, sorry for the mess.
Rui Barradas
Em 25-05-2012 11:00, r-help-requ...@r-project.org escreveu:
Date: Thu, 24 May 2012 15:37:51 -0700 (PDT)
From: Hans Thompson
To:r-help@r-project.org
Subject: Re: [R] applying cbind (or any function) a
wrong, sorry for the mess.
>
> Rui Barradas
>
>
> Em 25-05-2012 11:00, r-help-requ...@r-project.org escreveu:
>
>> Date: Thu, 24 May 2012 15:37:51 -0700 (PDT)
>> From: Hans Thompson
>> >
>>
>> To:r-help@r-project.org
>> Subject: Re: [R] applyi
s
}
lapply(seq_len(length(l1)), function(i) fun1(l1[[i]], l2[[i]]))
lapply(seq_len(length(l1)), function(i) fun2(l1[[i]], l2[[i]]))
If I'm wrong, sorry for the mess.
Rui Barradas
Em 25-05-2012 11:00, r-help-requ...@r-project.org escreveu:
Date: Thu, 24 May 2012 15:37:51 -0700 (PDT)
From:
oject.org
> Subject: Re: [R] applying cbind (or any function) across all components
> in a list
>
> Yes. This gives me:
>
> [,1] [,2] [,3] [,4]
> [1,]1234
> [2,]2345
> [,1] [,2] [,3] [,4]
> [1,]6789
> [2,]
On May 24, 2012, at 6:37 PM, Hans Thompson wrote:
The function I am giving for context is cbind. Are you asking how I
would
like to apply the answer to my question?
I am trying to take the results of a Fluidigm SNP microarray,
organized by
assay into a list (each component is the results
The function I am giving for context is cbind. Are you asking how I would
like to apply the answer to my question?
I am trying to take the results of a Fluidigm SNP microarray, organized by
assay into a list (each component is the results of one assay), find
coordinate midpoints ([1,] and [2,] of
Yes. This gives me:
[,1] [,2] [,3] [,4]
[1,]1234
[2,]2345
[,1] [,2] [,3] [,4]
[1,]6789
[2,]789 10
BUT, how can I have it still within components like
[[1]]
[,1] [,2] [,3] [,4]
[1,]1234
[2,]23
On May 24, 2012, at 12:49 PM, Hans Thompson wrote:
I'm confused why I haven't made clear what I am asking for help with.
I have two different lists with two (or many) components, [[1]] and
[[2]].
One of the list has components with dim=c(2,3) and the other has
dim=c(2,2).
I want to create
; -Original Message-
> From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
> project.org] On Behalf Of Greg Snow
> Sent: Thursday, May 24, 2012 10:17 AM
> To: Hans Thompson
> Cc: r-help@r-project.org
> Subject: Re: [R] applying cbind (or any function) across all
I'm confused why I haven't made clear what I am asking for help with.
I have two different lists with two (or many) components, [[1]] and [[2]].
One of the list has components with dim=c(2,3) and the other has dim=c(2,2).
I want to create a new list with components dim=c(2,4) by binding togeth
The "do.call" function may be what you want, but it is not completely
clear. If that does not solve your problem then try giving us an
example of what your list looks like (the dput function can help) and
what you want your end result to look like.
On Thu, May 24, 2012 at 5:38 AM, Hans Thompson
The combination of column means in cbind is what I am trying to do. I just
don't know how to do it for every component (2 in this case) of the list.
I've been able to work with R to apply a function across all components when
there is just one list but I am having trouble working with multiple li
#If I have two lists as follows
a1<- array(1:6, dim=c(2,3))
a2<- array(7:12, dim=c(2,3))
l1<- list(a1,a2)
a3<- array(1:4, dim=c(2,2))
a4<- array(5:8, dim=c(2,2))
l2<- list(a3,a4)
#how can I create a new list with the mean across all arrays within the
list, so all components are included
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