Thanks Bill,
That is what I was looking for.
Gerrit
On 12/29/2014 05:53 PM, William Dunlap wrote:
as.vector(x) will return x without any attributes and
structure(x, attrA=NULL, attrB=NULL) will return x
without the named attributes.
> z <- f(1:3, 4)
> z
[1] 14
attr(,"gradient")
as.vector(x) will return x without any attributes and
structure(x, attrA=NULL, attrB=NULL) will return x
without the named attributes.
> z <- f(1:3, 4)
> z
[1] 14
attr(,"gradient")
[1] -6 -4 -2
> as.vector(z)
[1] 14
> structure(z, gradient=NULL)
[1] 14
as.vector is a gen
Thanks Duncan.
But my question was how to extract
simply the function value from value,
without the gradient attribute?
I see that things like value<2 give the right answer.
I was curiosity. I found now that value[1]
gives strips the attributes from value:
--
> value
[1] 1
attr(,"gradient")
On 29/12/2014 10:32 AM, Gerrit Draisma wrote:
> Just a curiosity question:
>
> In the documentation for the nlm procedure
> a find this example of defining a function
> with a gradient attribute:
> ---
> f <- function(x, a)
> {
> res <- sum((x-a)^2)
> attr(r
Just a curiosity question:
In the documentation for the nlm procedure
a find this example of defining a function
with a gradient attribute:
---
f <- function(x, a)
{
res <- sum((x-a)^2)
attr(res, "gradient") <- 2*(x-a)
res
}
---
I get the
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