Try also
subset(x, as.Date(Inspected, %m/%d/%y) as.Date(Sold, %m/%d/%y) )
HTH,
Jorge.-
On Mon, Dec 26, 2011 at 9:32 PM, Jorge I Velez wrote:
Hi Eric,
Try
# data
x - structure(list(House_number = 1:4, Inspected = structure(c(3L,
4L, 1L, 2L), .Label = c(10/31/2011, 8/3/2011, 9/2/2011,
I should have said, those date vairable are indeed date variables, but I'll
try some of these techniques as soon as I get in this morning.
Thanks so much for your input.
- Eric
On Tue, Dec 27, 2011 at 6:54 AM, Jorge I Velez jorgeivanve...@gmail.comwrote:
Try also
subset(x,
Hi,
I hope this isn't a really simple question, I've been struggling with it
for a while.
I'm looking for a way to get a function to go through a data frame line by
line, compare fields, and produce a result, kind of a transform and an if
statement combined (I tried to put them together and it
Hi Eric,
Try
# data
x - structure(list(House_number = 1:4, Inspected = structure(c(3L,
4L, 1L, 2L), .Label = c(10/31/2011, 8/3/2011, 9/2/2011,
9/4/2011), class = factor), Sold = structure(c(1L, 2L, 4L,
3L), .Label = c(10/10/2011, 10/20/2011, 11/1/2011, 8/28/2011
), class = factor)), .Names =
On Dec 26, 2011, at 7:52 PM, Eric Wolff wrote:
Hi,
I hope this isn't a really simple question, I've been struggling
with it
for a while.
I'm looking for a way to get a function to go through a data frame
line by
line, compare fields, and produce a result, kind of a transform and
an if
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