Re: [R] data format issue

2008-12-20 Thread Gabor Grothendieck
Use read.zoo and aggregate.zoo from zoo and months, hours and as.chron from chron. Note that we must read in col 1 as character to ensure leading zeros don't get dropped. There are two mph columns and it is assumed you want both: Lines <- "LST inch mphDeg DegF DegF%volts D

Re: [R] data format issue

2008-12-20 Thread jim holtman
Does this do it for you: > # quick and dirty -- remove the 'mm' from the data and then aggregate > x$hours <- (x$LST %/% 100) * 100 > aggregate(x$mph, list(x$hours), mean) Group.1x 1 50601 13.82500 2 506010100 17.55000 3 506010200 23.04167 4 506010300 22.0 > > You can also 'fi

[R] data format issue

2008-12-20 Thread Sherri Heck
Dear all- I have a dataset (see a sample below - but the whole dataset is June 2005 - June 2008). The "LST" format is "YYMMDDHHmm" and I would like to get the hourly average of the "mph" for the summer months (spanning all years). I have been trying to use "aggregate" but am not having much